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Theorem dffn5imf 5758
Description: Representation of a function in terms of its values. (Contributed by Jim Kingdon, 31-Dec-2018.)
Hypothesis
Ref Expression
dffn5imf.1 𝑥𝐹
Assertion
Ref Expression
dffn5imf (𝐹 Fn 𝐴𝐹 = (𝑥𝐴 ↦ (𝐹𝑥)))
Distinct variable group:   𝑥,𝐴
Allowed substitution hint:   𝐹(𝑥)

Proof of Theorem dffn5imf
Dummy variable 𝑧 is distinct from all other variables.
StepHypRef Expression
1 dffn5im 5748 . 2 (𝐹 Fn 𝐴𝐹 = (𝑧𝐴 ↦ (𝐹𝑧)))
2 dffn5imf.1 . . . 4 𝑥𝐹
3 nfcv 2392 . . . 4 𝑥𝑧
42, 3nffv 5705 . . 3 𝑥(𝐹𝑧)
5 nfcv 2392 . . 3 𝑧(𝐹𝑥)
6 fveq2 5695 . . 3 (𝑧 = 𝑥 → (𝐹𝑧) = (𝐹𝑥))
74, 5, 6cbvmpt 4226 . 2 (𝑧𝐴 ↦ (𝐹𝑧)) = (𝑥𝐴 ↦ (𝐹𝑥))
81, 7eqtrdi 2287 1 (𝐹 Fn 𝐴𝐹 = (𝑥𝐴 ↦ (𝐹𝑥)))
Colors of variables:    wff set class
This proof depends on syntax axioms:  wi 4   = wceq 1402  wnfc 2379  cmpt 4192   Fn wfn 5372  cfv 5377
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 721  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-10 1558  ax-11 1559  ax-i12 1560  ax-bndl 1562  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-14 2212  ax-ext 2220  ax-sep 4249  ax-pow 4311  ax-pr 4346
This proof depends on definitions:  df-bi 117  df-3an 1011  df-tru 1405  df-nf 1514  df-sb 1816  df-eu 2089  df-mo 2090  df-clab 2225  df-cleq 2231  df-clel 2234  df-nfc 2381  df-ral 2533  df-rex 2534  df-v 2823  df-sbc 3052  df-un 3224  df-in 3226  df-ss 3233  df-pw 3690  df-sn 3715  df-pr 3716  df-op 3718  df-uni 3936  df-br 4131  df-opab 4193  df-mpt 4194  df-id 4438  df-xp 4780  df-rel 4781  df-cnv 4782  df-co 4783  df-dm 4784  df-iota 5337  df-fun 5379  df-fn 5380  df-fv 5385
This theorem is used by: (None)
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