Theorem erdisj 8335

Description: Equivalence classes do not overlap. In other words, two equivalence classes are either equal or disjoint. Theorem 74 of [Suppes] p. 83. (Contributed by NM, 15-Jun-2004.) (Revised by Mario Carneiro, 9-Jul-2014.)

Assertion

Ref	Expression
erdisj	⊢ (𝑅 Er 𝑋 → ([𝐴]𝑅 = [𝐵]𝑅 ∨ ([𝐴]𝑅 ∩ [𝐵]𝑅) = ∅))

Proof of Theorem erdisj

Dummy variable 𝑥 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		neq0 4308	. . . 4 ⊢ (¬ ([𝐴]𝑅 ∩ [𝐵]𝑅) = ∅ ↔ ∃𝑥 𝑥 ∈ ([𝐴]𝑅 ∩ [𝐵]𝑅))
2		simpl 485	. . . . . . 7 ⊢ ((𝑅 Er 𝑋 ∧ 𝑥 ∈ ([𝐴]𝑅 ∩ [𝐵]𝑅)) → 𝑅 Er 𝑋)
3		elinel1 4171	. . . . . . . . . 10 ⊢ (𝑥 ∈ ([𝐴]𝑅 ∩ [𝐵]𝑅) → 𝑥 ∈ [𝐴]𝑅)
4	3	adantl 484	. . . . . . . . 9 ⊢ ((𝑅 Er 𝑋 ∧ 𝑥 ∈ ([𝐴]𝑅 ∩ [𝐵]𝑅)) → 𝑥 ∈ [𝐴]𝑅)
5		vex 3497	. . . . . . . . . 10 ⊢ 𝑥 ∈ V
6		ecexr 8288	. . . . . . . . . . 11 ⊢ (𝑥 ∈ [𝐴]𝑅 → 𝐴 ∈ V)
7	4, 6	syl 17	. . . . . . . . . 10 ⊢ ((𝑅 Er 𝑋 ∧ 𝑥 ∈ ([𝐴]𝑅 ∩ [𝐵]𝑅)) → 𝐴 ∈ V)
8		elecg 8326	. . . . . . . . . 10 ⊢ ((𝑥 ∈ V ∧ 𝐴 ∈ V) → (𝑥 ∈ [𝐴]𝑅 ↔ 𝐴𝑅𝑥))
9	5, 7, 8	sylancr 589	. . . . . . . . 9 ⊢ ((𝑅 Er 𝑋 ∧ 𝑥 ∈ ([𝐴]𝑅 ∩ [𝐵]𝑅)) → (𝑥 ∈ [𝐴]𝑅 ↔ 𝐴𝑅𝑥))
10	4, 9	mpbid 234	. . . . . . . 8 ⊢ ((𝑅 Er 𝑋 ∧ 𝑥 ∈ ([𝐴]𝑅 ∩ [𝐵]𝑅)) → 𝐴𝑅𝑥)
11		elinel2 4172	. . . . . . . . . 10 ⊢ (𝑥 ∈ ([𝐴]𝑅 ∩ [𝐵]𝑅) → 𝑥 ∈ [𝐵]𝑅)
12	11	adantl 484	. . . . . . . . 9 ⊢ ((𝑅 Er 𝑋 ∧ 𝑥 ∈ ([𝐴]𝑅 ∩ [𝐵]𝑅)) → 𝑥 ∈ [𝐵]𝑅)
13		ecexr 8288	. . . . . . . . . . 11 ⊢ (𝑥 ∈ [𝐵]𝑅 → 𝐵 ∈ V)
14	12, 13	syl 17	. . . . . . . . . 10 ⊢ ((𝑅 Er 𝑋 ∧ 𝑥 ∈ ([𝐴]𝑅 ∩ [𝐵]𝑅)) → 𝐵 ∈ V)
15		elecg 8326	. . . . . . . . . 10 ⊢ ((𝑥 ∈ V ∧ 𝐵 ∈ V) → (𝑥 ∈ [𝐵]𝑅 ↔ 𝐵𝑅𝑥))
16	5, 14, 15	sylancr 589	. . . . . . . . 9 ⊢ ((𝑅 Er 𝑋 ∧ 𝑥 ∈ ([𝐴]𝑅 ∩ [𝐵]𝑅)) → (𝑥 ∈ [𝐵]𝑅 ↔ 𝐵𝑅𝑥))
17	12, 16	mpbid 234	. . . . . . . 8 ⊢ ((𝑅 Er 𝑋 ∧ 𝑥 ∈ ([𝐴]𝑅 ∩ [𝐵]𝑅)) → 𝐵𝑅𝑥)
18	2, 10, 17	ertr4d 8302	. . . . . . 7 ⊢ ((𝑅 Er 𝑋 ∧ 𝑥 ∈ ([𝐴]𝑅 ∩ [𝐵]𝑅)) → 𝐴𝑅𝐵)
19	2, 18	erthi 8334	. . . . . 6 ⊢ ((𝑅 Er 𝑋 ∧ 𝑥 ∈ ([𝐴]𝑅 ∩ [𝐵]𝑅)) → [𝐴]𝑅 = [𝐵]𝑅)
20	19	ex 415	. . . . 5 ⊢ (𝑅 Er 𝑋 → (𝑥 ∈ ([𝐴]𝑅 ∩ [𝐵]𝑅) → [𝐴]𝑅 = [𝐵]𝑅))
21	20	exlimdv 1930	. . . 4 ⊢ (𝑅 Er 𝑋 → (∃𝑥 𝑥 ∈ ([𝐴]𝑅 ∩ [𝐵]𝑅) → [𝐴]𝑅 = [𝐵]𝑅))
22	1, 21	syl5bi 244	. . 3 ⊢ (𝑅 Er 𝑋 → (¬ ([𝐴]𝑅 ∩ [𝐵]𝑅) = ∅ → [𝐴]𝑅 = [𝐵]𝑅))
23	22	orrd 859	. 2 ⊢ (𝑅 Er 𝑋 → (([𝐴]𝑅 ∩ [𝐵]𝑅) = ∅ ∨ [𝐴]𝑅 = [𝐵]𝑅))
24	23	orcomd 867	1 ⊢ (𝑅 Er 𝑋 → ([𝐴]𝑅 = [𝐵]𝑅 ∨ ([𝐴]𝑅 ∩ [𝐵]𝑅) = ∅))

Syntax hints:  ¬ wn 3   → wi 4   ↔ wb 208   ∧ wa 398   ∨ wo 843   = wceq 1533  ∃wex 1776   ∈ wcel 2110  Vcvv 3494   ∩ cin 3934  ∅c0 4290   class class class wbr 5058   Er wer 8280  [cec 8281

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1792  ax-4 1806  ax-5 1907  ax-6 1966  ax-7 2011  ax-8 2112  ax-9 2120  ax-10 2141  ax-11 2157  ax-12 2173  ax-ext 2793  ax-sep 5195  ax-nul 5202  ax-pr 5321

This theorem depends on definitions:  df-bi 209  df-an 399  df-or 844  df-3an 1085  df-tru 1536  df-ex 1777  df-nf 1781  df-sb 2066  df-mo 2618  df-eu 2650  df-clab 2800  df-cleq 2814  df-clel 2893  df-nfc 2963  df-ne 3017  df-ral 3143  df-rex 3144  df-rab 3147  df-v 3496  df-sbc 3772  df-dif 3938  df-un 3940  df-in 3942  df-ss 3951  df-nul 4291  df-if 4467  df-sn 4561  df-pr 4563  df-op 4567  df-br 5059  df-opab 5121  df-xp 5555  df-rel 5556  df-cnv 5557  df-co 5558  df-dm 5559  df-rn 5560  df-res 5561  df-ima 5562  df-er 8283  df-ec 8285

This theorem is referenced by:  qsdisj  8368