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Theorem fabexd 7949
Description: Existence of a set of functions. In contrast to fabex 7951 or fabexg 7950, the condition in the class abstraction does not contain the function explicitly, but the function can be derived from it. Therefore, this theorem is also applicable for more special functions like one-to-one, onto or one-to-one onto functions. (Contributed by AV, 20-May-2025.)
Hypotheses
Ref Expression
fabexd.f ((𝜑 ∧ 𝜓) → 𝑓:𝑋⟶𝑌)
fabexd.x (𝜑 → 𝑋 ∈ 𝑉)
fabexd.y (𝜑 → 𝑌 ∈ 𝑊)
Assertion
Ref Expression
fabexd (𝜑 → {𝑓 ∣ 𝜓} ∈ V)
Distinct variable groups:   𝑓,𝑋   𝑓,𝑌   𝜑,𝑓
Allowed substitution hints:   𝜓(𝑓)   𝑉(𝑓)   𝑊(𝑓)

Proof of Theorem fabexd
StepHypRef Expression
1 fabexd.x . . . 4 (𝜑 → 𝑋 ∈ 𝑉)
2 fabexd.y . . . 4 (𝜑 → 𝑌 ∈ 𝑊)
31, 2xpexd 7765 . . 3 (𝜑 → (𝑋 × 𝑌) ∈ V)
43pwexd 5341 . 2 (𝜑 → 𝒫 (𝑋 × 𝑌) ∈ V)
5 fabexd.f . . . . 5 ((𝜑 ∧ 𝜓) → 𝑓:𝑋⟶𝑌)
6 fssxp 6737 . . . . . 6 (𝑓:𝑋⟶𝑌 → 𝑓 ⊆ (𝑋 × 𝑌))
7 velpw 4562 . . . . . 6 (𝑓 ∈ 𝒫 (𝑋 × 𝑌) ↔ 𝑓 ⊆ (𝑋 × 𝑌))
86, 7sylibr 237 . . . . 5 (𝑓:𝑋⟶𝑌 → 𝑓 ∈ 𝒫 (𝑋 × 𝑌))
95, 8syl 18 . . . 4 ((𝜑 ∧ 𝜓) → 𝑓 ∈ 𝒫 (𝑋 × 𝑌))
109ex 418 . . 3 (𝜑 → (𝜓 → 𝑓 ∈ 𝒫 (𝑋 × 𝑌)))
1110abssdv 4015 . 2 (𝜑 → {𝑓 ∣ 𝜓} ⊆ 𝒫 (𝑋 × 𝑌))
124, 11ssexd 5286 1 (𝜑 → {𝑓 ∣ 𝜓} ∈ V)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ∧ wa 401   ∈ wcel 2145  {cab 2739  Vcvv 3451   ⊆ wss 3899  𝒫 cpw 4557   × cxp 5649  ⟶wf 6534
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2733  ax-sep 5249  ax-pow 5327  ax-pr 5391  ax-un 7751
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2740  df-cleq 2753  df-clel 2836  df-ral 3078  df-rex 3088  df-rab 3414  df-v 3453  df-dif 3902  df-un 3904  df-in 3906  df-ss 3916  df-nul 4280  df-if 4483  df-pw 4559  df-sn 4585  df-pr 4587  df-op 4591  df-uni 4868  df-br 5104  df-opab 5168  df-xp 5657  df-rel 5658  df-cnv 5659  df-dm 5661  df-rn 5662  df-fun 6540  df-fn 6541  df-f 6542
This theorem is used by:  fabexg  7950  f1oabexg  7953  grlimfn  49076  isgrlim  49079
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