MPE Home Metamath Proof Explorer < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >  ordeq Structured version   Visualization version   GIF version

Theorem ordeq 6339
Description: Equality theorem for the ordinal predicate. (Contributed by NM, 17-Sep-1993.)
Assertion
Ref Expression
ordeq (𝐴 = 𝐵 → (Ord 𝐴 ↔ Ord 𝐵))

Proof of Theorem ordeq
StepHypRef Expression
1 treq 5222 . . 3 (𝐴 = 𝐵 → (Tr 𝐴 ↔ Tr 𝐵))
2 weeq2 5626 . . 3 (𝐴 = 𝐵 → ( E We 𝐴 ↔ E We 𝐵))
31, 2anbi12d 632 . 2 (𝐴 = 𝐵 → ((Tr 𝐴 ∧ E We 𝐴) ↔ (Tr 𝐵 ∧ E We 𝐵)))
4 df-ord 6335 . 2 (Ord 𝐴 ↔ (Tr 𝐴 ∧ E We 𝐴))
5 df-ord 6335 . 2 (Ord 𝐵 ↔ (Tr 𝐵 ∧ E We 𝐵))
63, 4, 53bitr4g 314 1 (𝐴 = 𝐵 → (Ord 𝐴 ↔ Ord 𝐵))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 206  wa 395   = wceq 1540  Tr wtr 5214   E cep 5537   We wwe 5590  Ord word 6331
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2008  ax-8 2111  ax-9 2119  ax-ext 2701
This theorem depends on definitions:  df-bi 207  df-an 396  df-tru 1543  df-ex 1780  df-sb 2066  df-clab 2708  df-cleq 2721  df-clel 2803  df-ral 3045  df-v 3449  df-ss 3931  df-uni 4872  df-tr 5215  df-po 5546  df-so 5547  df-fr 5591  df-we 5593  df-ord 6335
This theorem is referenced by:  elong  6340  limeq  6344  ordelord  6354  ordun  6438  ordeleqon  7758  ordsuc  7788  ordsucOLD  7789  ordzsl  7821  issmo  8317  issmo2  8318  smoeq  8319  smores  8321  smores2  8323  smodm2  8324  smoiso  8331  tfrlem8  8352  ord3  8449  ordtypelem5  9475  ordtypelem7  9477  oicl  9482  oieu  9492  dfsucon  43512
  Copyright terms: Public domain W3C validator