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Theorem sucneqond 38382
Description: Inequality of an ordinal set with its successor. Does not use the axiom of regularity. (Contributed by ML, 18-Oct-2020.)
Hypotheses
Ref Expression
sucneqond.1 (𝜑 → 𝑋 = suc 𝑌)
sucneqond.2 (𝜑 → 𝑌 ∈ On)
Assertion
Ref Expression
sucneqond (𝜑 → 𝑋 ≠ 𝑌)

Proof of Theorem sucneqond
StepHypRef Expression
1 sucneqond.2 . . . . 5 (𝜑 → 𝑌 ∈ On)
2 sucidg 6446 . . . . 5 (𝑌 ∈ On → 𝑌 ∈ suc 𝑌)
31, 2syl 18 . . . 4 (𝜑 → 𝑌 ∈ suc 𝑌)
4 sucneqond.1 . . . 4 (𝜑 → 𝑋 = suc 𝑌)
53, 4eleqtrrd 2863 . . 3 (𝜑 → 𝑌 ∈ 𝑋)
6 onsuc 7825 . . . . . . . 8 (𝑌 ∈ On → suc 𝑌 ∈ On)
71, 6syl 18 . . . . . . 7 (𝜑 → suc 𝑌 ∈ On)
84, 7eqeltrd 2860 . . . . . 6 (𝜑 → 𝑋 ∈ On)
9 eloni 6372 . . . . . 6 (𝑋 ∈ On → Ord 𝑋)
108, 9syl 18 . . . . 5 (𝜑 → Ord 𝑋)
11 ordirr 6380 . . . . 5 (Ord 𝑋 → ¬ 𝑋 ∈ 𝑋)
1210, 11syl 18 . . . 4 (𝜑 → ¬ 𝑋 ∈ 𝑋)
13 eleq1 2848 . . . . . 6 (𝑋 = 𝑌 → (𝑋 ∈ 𝑋 ↔ 𝑌 ∈ 𝑋))
1413biimprd 251 . . . . 5 (𝑋 = 𝑌 → (𝑌 ∈ 𝑋 → 𝑋 ∈ 𝑋))
1514con3d 153 . . . 4 (𝑋 = 𝑌 → (¬ 𝑋 ∈ 𝑋 → ¬ 𝑌 ∈ 𝑋))
1612, 15syl5com 32 . . 3 (𝜑 → (𝑋 = 𝑌 → ¬ 𝑌 ∈ 𝑋))
175, 16mt2d 137 . 2 (𝜑 → ¬ 𝑋 = 𝑌)
1817neqned 2962 1 (𝜑 → 𝑋 ≠ 𝑌)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3   → wi 4   = wceq 1569   ∈ wcel 2144   ≠ wne 2955  Ord word 6361  Oncon0 6362  suc csuc 6364
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-ext 2732  ax-sep 5248  ax-pr 5390  ax-un 7752
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3or 1104  df-3an 1105  df-tru 1572  df-fal 1582  df-ex 1812  df-sb 2099  df-clab 2739  df-cleq 2752  df-clel 2835  df-ne 2956  df-ral 3077  df-rex 3087  df-rab 3413  df-v 3452  df-ss 3896  df-pss 4014  df-dif 4047  df-in 4091  df-un 4151  df-nul 4279  df-if 4482  df-pw 4558  df-sn 4585  df-pr 4587  df-op 4835  df-uni 4867  df-br 5103  df-opab 5167  df-tr 5212  df-eprel 5550  df-po 5558  df-so 5559  df-fr 5603  df-we 5605  df-ord 6365  df-on 6366  df-suc 6368
This theorem is used by:  sucneqoni  38383
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