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Theorem sucneqond 38256
Description: Inequality of an ordinal set with its successor. Does not use the axiom of regularity. (Contributed by ML, 18-Oct-2020.)
Hypotheses
Ref Expression
sucneqond.1 (𝜑 → 𝑋 = suc 𝑌)
sucneqond.2 (𝜑 → 𝑌 ∈ On)
Assertion
Ref Expression
sucneqond (𝜑 → 𝑋 ≠ 𝑌)

Proof of Theorem sucneqond
StepHypRef Expression
1 sucneqond.2 . . . . 5 (𝜑 → 𝑌 ∈ On)
2 sucidg 6439 . . . . 5 (𝑌 ∈ On → 𝑌 ∈ suc 𝑌)
31, 2syl 18 . . . 4 (𝜑 → 𝑌 ∈ suc 𝑌)
4 sucneqond.1 . . . 4 (𝜑 → 𝑋 = suc 𝑌)
53, 4eleqtrrd 2864 . . 3 (𝜑 → 𝑌 ∈ 𝑋)
6 onsuc 7813 . . . . . . . 8 (𝑌 ∈ On → suc 𝑌 ∈ On)
71, 6syl 18 . . . . . . 7 (𝜑 → suc 𝑌 ∈ On)
84, 7eqeltrd 2861 . . . . . 6 (𝜑 → 𝑋 ∈ On)
9 eloni 6365 . . . . . 6 (𝑋 ∈ On → Ord 𝑋)
108, 9syl 18 . . . . 5 (𝜑 → Ord 𝑋)
11 ordirr 6373 . . . . 5 (Ord 𝑋 → ¬ 𝑋 ∈ 𝑋)
1210, 11syl 18 . . . 4 (𝜑 → ¬ 𝑋 ∈ 𝑋)
13 eleq1 2849 . . . . . 6 (𝑋 = 𝑌 → (𝑋 ∈ 𝑋 ↔ 𝑌 ∈ 𝑋))
1413biimprd 251 . . . . 5 (𝑋 = 𝑌 → (𝑌 ∈ 𝑋 → 𝑋 ∈ 𝑋))
1514con3d 153 . . . 4 (𝑋 = 𝑌 → (¬ 𝑋 ∈ 𝑋 → ¬ 𝑌 ∈ 𝑋))
1612, 15syl5com 32 . . 3 (𝜑 → (𝑋 = 𝑌 → ¬ 𝑌 ∈ 𝑋))
175, 16mt2d 137 . 2 (𝜑 → ¬ 𝑋 = 𝑌)
1817neqned 2963 1 (𝜑 → 𝑋 ≠ 𝑌)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3   → wi 4   = wceq 1570   ∈ wcel 2145   ≠ wne 2956  Ord word 6354  Oncon0 6355  suc csuc 6357
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2733  ax-sep 5249  ax-pr 5391  ax-un 7740
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3or 1104  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2740  df-cleq 2753  df-clel 2836  df-ne 2957  df-ral 3078  df-rex 3088  df-rab 3414  df-v 3453  df-dif 3902  df-un 3904  df-in 3906  df-ss 3916  df-pss 3919  df-nul 4280  df-if 4483  df-pw 4559  df-sn 4585  df-pr 4587  df-op 4591  df-uni 4868  df-br 5104  df-opab 5168  df-tr 5213  df-eprel 5551  df-po 5559  df-so 5560  df-fr 5604  df-we 5606  df-ord 6358  df-on 6359  df-suc 6361
This theorem is used by:  sucneqoni  38257
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