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Theorem bj-idreseq 37157
Description: Sufficient condition for the restricted identity relation to agree with equality. Note that the instance of bj-ideqg 37152 with V substituted for 𝑉 is a direct consequence of bj-idreseq 37157. This is a strengthening of resieq 5964 which should be proved from it (note that currently, resieq 5964 relies on ideq 5819). Note that the intersection in the antecedent is not very meaningful, but is a device to prove versions with either class assumed to be a set. It could be enough to prove the version with a disjunctive antecedent: ((𝐴𝐶𝐵𝐶) → ...). (Contributed by BJ, 25-Dec-2023.)
Assertion
Ref Expression
bj-idreseq ((𝐴𝐵) ∈ 𝐶 → (𝐴( I ↾ 𝐶)𝐵𝐴 = 𝐵))

Proof of Theorem bj-idreseq
Dummy variables 𝑥 𝑦 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 bj-brresdm 37141 . . . 4 (𝐴( I ↾ 𝐶)𝐵𝐴𝐶)
2 relres 5979 . . . . 5 Rel ( I ↾ 𝐶)
32brrelex2i 5698 . . . 4 (𝐴( I ↾ 𝐶)𝐵𝐵 ∈ V)
41, 3jca 511 . . 3 (𝐴( I ↾ 𝐶)𝐵 → (𝐴𝐶𝐵 ∈ V))
54adantl 481 . 2 (((𝐴𝐵) ∈ 𝐶𝐴( I ↾ 𝐶)𝐵) → (𝐴𝐶𝐵 ∈ V))
6 eqimss 4008 . . . . . 6 (𝐴 = 𝐵𝐴𝐵)
7 dfss2 3935 . . . . . 6 (𝐴𝐵 ↔ (𝐴𝐵) = 𝐴)
86, 7sylib 218 . . . . 5 (𝐴 = 𝐵 → (𝐴𝐵) = 𝐴)
98adantl 481 . . . 4 (((𝐴𝐵) ∈ 𝐶𝐴 = 𝐵) → (𝐴𝐵) = 𝐴)
10 simpl 482 . . . 4 (((𝐴𝐵) ∈ 𝐶𝐴 = 𝐵) → (𝐴𝐵) ∈ 𝐶)
119, 10eqeltrrd 2830 . . 3 (((𝐴𝐵) ∈ 𝐶𝐴 = 𝐵) → 𝐴𝐶)
12 eqimss2 4009 . . . . . . 7 (𝐴 = 𝐵𝐵𝐴)
13 sseqin2 4189 . . . . . . 7 (𝐵𝐴 ↔ (𝐴𝐵) = 𝐵)
1412, 13sylib 218 . . . . . 6 (𝐴 = 𝐵 → (𝐴𝐵) = 𝐵)
1514adantl 481 . . . . 5 (((𝐴𝐵) ∈ 𝐶𝐴 = 𝐵) → (𝐴𝐵) = 𝐵)
1615, 10eqeltrrd 2830 . . . 4 (((𝐴𝐵) ∈ 𝐶𝐴 = 𝐵) → 𝐵𝐶)
1716elexd 3474 . . 3 (((𝐴𝐵) ∈ 𝐶𝐴 = 𝐵) → 𝐵 ∈ V)
1811, 17jca 511 . 2 (((𝐴𝐵) ∈ 𝐶𝐴 = 𝐵) → (𝐴𝐶𝐵 ∈ V))
19 brres 5960 . . . 4 (𝐵 ∈ V → (𝐴( I ↾ 𝐶)𝐵 ↔ (𝐴𝐶𝐴 I 𝐵)))
2019adantl 481 . . 3 ((𝐴𝐶𝐵 ∈ V) → (𝐴( I ↾ 𝐶)𝐵 ↔ (𝐴𝐶𝐴 I 𝐵)))
21 eqeq12 2747 . . . . 5 ((𝑥 = 𝐴𝑦 = 𝐵) → (𝑥 = 𝑦𝐴 = 𝐵))
22 df-id 5536 . . . . 5 I = {⟨𝑥, 𝑦⟩ ∣ 𝑥 = 𝑦}
2321, 22brabga 5497 . . . 4 ((𝐴𝐶𝐵 ∈ V) → (𝐴 I 𝐵𝐴 = 𝐵))
2423anbi2d 630 . . 3 ((𝐴𝐶𝐵 ∈ V) → ((𝐴𝐶𝐴 I 𝐵) ↔ (𝐴𝐶𝐴 = 𝐵)))
25 simp3 1138 . . . . 5 (((𝐴𝐶𝐵 ∈ V) ∧ 𝐴𝐶𝐴 = 𝐵) → 𝐴 = 𝐵)
26253expib 1122 . . . 4 ((𝐴𝐶𝐵 ∈ V) → ((𝐴𝐶𝐴 = 𝐵) → 𝐴 = 𝐵))
27 3simpb 1149 . . . . 5 ((𝐴𝐶𝐵 ∈ V ∧ 𝐴 = 𝐵) → (𝐴𝐶𝐴 = 𝐵))
28273expia 1121 . . . 4 ((𝐴𝐶𝐵 ∈ V) → (𝐴 = 𝐵 → (𝐴𝐶𝐴 = 𝐵)))
2926, 28impbid 212 . . 3 ((𝐴𝐶𝐵 ∈ V) → ((𝐴𝐶𝐴 = 𝐵) ↔ 𝐴 = 𝐵))
3020, 24, 293bitrd 305 . 2 ((𝐴𝐶𝐵 ∈ V) → (𝐴( I ↾ 𝐶)𝐵𝐴 = 𝐵))
315, 18, 30pm5.21nd 801 1 ((𝐴𝐵) ∈ 𝐶 → (𝐴( I ↾ 𝐶)𝐵𝐴 = 𝐵))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 206  wa 395   = wceq 1540  wcel 2109  Vcvv 3450  cin 3916  wss 3917   class class class wbr 5110   I cid 5535  cres 5643
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2008  ax-8 2111  ax-9 2119  ax-ext 2702  ax-sep 5254  ax-nul 5264  ax-pr 5390
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1543  df-fal 1553  df-ex 1780  df-sb 2066  df-clab 2709  df-cleq 2722  df-clel 2804  df-ral 3046  df-rex 3055  df-rab 3409  df-v 3452  df-dif 3920  df-un 3922  df-in 3924  df-ss 3934  df-nul 4300  df-if 4492  df-sn 4593  df-pr 4595  df-op 4599  df-br 5111  df-opab 5173  df-id 5536  df-xp 5647  df-rel 5648  df-res 5653
This theorem is referenced by: (None)
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