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Theorem bj-idreseq 37306
Description: Sufficient condition for the restricted identity relation to agree with equality. Note that the instance of bj-ideqg 37301 with V substituted for 𝑉 is a direct consequence of bj-idreseq 37306. This is a strengthening of resieq 5947 which should be proved from it (note that currently, resieq 5947 relies on ideq 5799). Note that the intersection in the antecedent is not very meaningful, but is a device to prove versions with either class assumed to be a set. It could be enough to prove the version with a disjunctive antecedent: ((𝐴𝐶𝐵𝐶) → ...). (Contributed by BJ, 25-Dec-2023.)
Assertion
Ref Expression
bj-idreseq ((𝐴𝐵) ∈ 𝐶 → (𝐴( I ↾ 𝐶)𝐵𝐴 = 𝐵))

Proof of Theorem bj-idreseq
Dummy variables 𝑥 𝑦 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 bj-brresdm 37290 . . . 4 (𝐴( I ↾ 𝐶)𝐵𝐴𝐶)
2 relres 5962 . . . . 5 Rel ( I ↾ 𝐶)
32brrelex2i 5679 . . . 4 (𝐴( I ↾ 𝐶)𝐵𝐵 ∈ V)
41, 3jca 511 . . 3 (𝐴( I ↾ 𝐶)𝐵 → (𝐴𝐶𝐵 ∈ V))
54adantl 481 . 2 (((𝐴𝐵) ∈ 𝐶𝐴( I ↾ 𝐶)𝐵) → (𝐴𝐶𝐵 ∈ V))
6 eqimss 3990 . . . . . 6 (𝐴 = 𝐵𝐴𝐵)
7 dfss2 3917 . . . . . 6 (𝐴𝐵 ↔ (𝐴𝐵) = 𝐴)
86, 7sylib 218 . . . . 5 (𝐴 = 𝐵 → (𝐴𝐵) = 𝐴)
98adantl 481 . . . 4 (((𝐴𝐵) ∈ 𝐶𝐴 = 𝐵) → (𝐴𝐵) = 𝐴)
10 simpl 482 . . . 4 (((𝐴𝐵) ∈ 𝐶𝐴 = 𝐵) → (𝐴𝐵) ∈ 𝐶)
119, 10eqeltrrd 2835 . . 3 (((𝐴𝐵) ∈ 𝐶𝐴 = 𝐵) → 𝐴𝐶)
12 eqimss2 3991 . . . . . . 7 (𝐴 = 𝐵𝐵𝐴)
13 sseqin2 4173 . . . . . . 7 (𝐵𝐴 ↔ (𝐴𝐵) = 𝐵)
1412, 13sylib 218 . . . . . 6 (𝐴 = 𝐵 → (𝐴𝐵) = 𝐵)
1514adantl 481 . . . . 5 (((𝐴𝐵) ∈ 𝐶𝐴 = 𝐵) → (𝐴𝐵) = 𝐵)
1615, 10eqeltrrd 2835 . . . 4 (((𝐴𝐵) ∈ 𝐶𝐴 = 𝐵) → 𝐵𝐶)
1716elexd 3462 . . 3 (((𝐴𝐵) ∈ 𝐶𝐴 = 𝐵) → 𝐵 ∈ V)
1811, 17jca 511 . 2 (((𝐴𝐵) ∈ 𝐶𝐴 = 𝐵) → (𝐴𝐶𝐵 ∈ V))
19 brres 5943 . . . 4 (𝐵 ∈ V → (𝐴( I ↾ 𝐶)𝐵 ↔ (𝐴𝐶𝐴 I 𝐵)))
2019adantl 481 . . 3 ((𝐴𝐶𝐵 ∈ V) → (𝐴( I ↾ 𝐶)𝐵 ↔ (𝐴𝐶𝐴 I 𝐵)))
21 eqeq12 2751 . . . . 5 ((𝑥 = 𝐴𝑦 = 𝐵) → (𝑥 = 𝑦𝐴 = 𝐵))
22 df-id 5517 . . . . 5 I = {⟨𝑥, 𝑦⟩ ∣ 𝑥 = 𝑦}
2321, 22brabga 5480 . . . 4 ((𝐴𝐶𝐵 ∈ V) → (𝐴 I 𝐵𝐴 = 𝐵))
2423anbi2d 630 . . 3 ((𝐴𝐶𝐵 ∈ V) → ((𝐴𝐶𝐴 I 𝐵) ↔ (𝐴𝐶𝐴 = 𝐵)))
25 simp3 1138 . . . . 5 (((𝐴𝐶𝐵 ∈ V) ∧ 𝐴𝐶𝐴 = 𝐵) → 𝐴 = 𝐵)
26253expib 1122 . . . 4 ((𝐴𝐶𝐵 ∈ V) → ((𝐴𝐶𝐴 = 𝐵) → 𝐴 = 𝐵))
27 3simpb 1149 . . . . 5 ((𝐴𝐶𝐵 ∈ V ∧ 𝐴 = 𝐵) → (𝐴𝐶𝐴 = 𝐵))
28273expia 1121 . . . 4 ((𝐴𝐶𝐵 ∈ V) → (𝐴 = 𝐵 → (𝐴𝐶𝐴 = 𝐵)))
2926, 28impbid 212 . . 3 ((𝐴𝐶𝐵 ∈ V) → ((𝐴𝐶𝐴 = 𝐵) ↔ 𝐴 = 𝐵))
3020, 24, 293bitrd 305 . 2 ((𝐴𝐶𝐵 ∈ V) → (𝐴( I ↾ 𝐶)𝐵𝐴 = 𝐵))
315, 18, 30pm5.21nd 801 1 ((𝐴𝐵) ∈ 𝐶 → (𝐴( I ↾ 𝐶)𝐵𝐴 = 𝐵))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 206  wa 395   = wceq 1541  wcel 2113  Vcvv 3438  cin 3898  wss 3899   class class class wbr 5096   I cid 5516  cres 5624
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-8 2115  ax-9 2123  ax-ext 2706  ax-sep 5239  ax-nul 5249  ax-pr 5375
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1544  df-fal 1554  df-ex 1781  df-sb 2068  df-clab 2713  df-cleq 2726  df-clel 2809  df-ral 3050  df-rex 3059  df-rab 3398  df-v 3440  df-dif 3902  df-un 3904  df-in 3906  df-ss 3916  df-nul 4284  df-if 4478  df-sn 4579  df-pr 4581  df-op 4585  df-br 5097  df-opab 5159  df-id 5517  df-xp 5628  df-rel 5629  df-res 5634
This theorem is referenced by: (None)
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