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Theorem funeldmb 7305
Description: If is not part of the range of a function 𝐹, then 𝐴 is in the domain of 𝐹 iff (𝐹𝐴) ≠ ∅. (Contributed by Scott Fenton, 7-Dec-2021.)
Assertion
Ref Expression
funeldmb ((Fun 𝐹 ∧ ¬ ∅ ∈ ran 𝐹) → (𝐴 ∈ dom 𝐹 ↔ (𝐹𝐴) ≠ ∅))

Proof of Theorem funeldmb
StepHypRef Expression
1 fvelrn 7021 . . . . . . . 8 ((Fun 𝐹𝐴 ∈ dom 𝐹) → (𝐹𝐴) ∈ ran 𝐹)
21ex 412 . . . . . . 7 (Fun 𝐹 → (𝐴 ∈ dom 𝐹 → (𝐹𝐴) ∈ ran 𝐹))
32adantr 480 . . . . . 6 ((Fun 𝐹 ∧ (𝐹𝐴) = ∅) → (𝐴 ∈ dom 𝐹 → (𝐹𝐴) ∈ ran 𝐹))
4 eleq1 2824 . . . . . . 7 ((𝐹𝐴) = ∅ → ((𝐹𝐴) ∈ ran 𝐹 ↔ ∅ ∈ ran 𝐹))
54adantl 481 . . . . . 6 ((Fun 𝐹 ∧ (𝐹𝐴) = ∅) → ((𝐹𝐴) ∈ ran 𝐹 ↔ ∅ ∈ ran 𝐹))
63, 5sylibd 239 . . . . 5 ((Fun 𝐹 ∧ (𝐹𝐴) = ∅) → (𝐴 ∈ dom 𝐹 → ∅ ∈ ran 𝐹))
76con3d 152 . . . 4 ((Fun 𝐹 ∧ (𝐹𝐴) = ∅) → (¬ ∅ ∈ ran 𝐹 → ¬ 𝐴 ∈ dom 𝐹))
87impancom 451 . . 3 ((Fun 𝐹 ∧ ¬ ∅ ∈ ran 𝐹) → ((𝐹𝐴) = ∅ → ¬ 𝐴 ∈ dom 𝐹))
9 ndmfv 6866 . . 3 𝐴 ∈ dom 𝐹 → (𝐹𝐴) = ∅)
108, 9impbid1 225 . 2 ((Fun 𝐹 ∧ ¬ ∅ ∈ ran 𝐹) → ((𝐹𝐴) = ∅ ↔ ¬ 𝐴 ∈ dom 𝐹))
1110necon2abid 2974 1 ((Fun 𝐹 ∧ ¬ ∅ ∈ ran 𝐹) → (𝐴 ∈ dom 𝐹 ↔ (𝐹𝐴) ≠ ∅))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wi 4  wb 206  wa 395   = wceq 1541  wcel 2113  wne 2932  c0 4285  dom cdm 5624  ran crn 5625  Fun wfun 6486  cfv 6492
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-8 2115  ax-9 2123  ax-10 2146  ax-12 2184  ax-ext 2708  ax-sep 5241  ax-nul 5251  ax-pr 5377
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1544  df-fal 1554  df-ex 1781  df-nf 1785  df-sb 2068  df-mo 2539  df-eu 2569  df-clab 2715  df-cleq 2728  df-clel 2811  df-ne 2933  df-ral 3052  df-rex 3061  df-rab 3400  df-v 3442  df-dif 3904  df-un 3906  df-ss 3918  df-nul 4286  df-if 4480  df-sn 4581  df-pr 4583  df-op 4587  df-uni 4864  df-br 5099  df-opab 5161  df-id 5519  df-xp 5630  df-rel 5631  df-cnv 5632  df-co 5633  df-dm 5634  df-rn 5635  df-iota 6448  df-fun 6494  df-fn 6495  df-fv 6500
This theorem is referenced by:  nosepssdm  27654
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