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Theorem pgindlem 49960
Description: Lemma for pgind 49962. (Contributed by Emmett Weisz, 27-May-2024.) (New usage is discouraged.)
Assertion
Ref Expression
pgindlem (𝑥 ∈ (𝒫 𝑧 × 𝒫 𝑧) → ((1st𝑥) ∪ (2nd𝑥)) ⊆ 𝑧)

Proof of Theorem pgindlem
StepHypRef Expression
1 xp1st 7965 . . 3 (𝑥 ∈ (𝒫 𝑧 × 𝒫 𝑧) → (1st𝑥) ∈ 𝒫 𝑧)
21elpwid 4563 . 2 (𝑥 ∈ (𝒫 𝑧 × 𝒫 𝑧) → (1st𝑥) ⊆ 𝑧)
3 xp2nd 7966 . . 3 (𝑥 ∈ (𝒫 𝑧 × 𝒫 𝑧) → (2nd𝑥) ∈ 𝒫 𝑧)
43elpwid 4563 . 2 (𝑥 ∈ (𝒫 𝑧 × 𝒫 𝑧) → (2nd𝑥) ⊆ 𝑧)
52, 4unssd 4144 1 (𝑥 ∈ (𝒫 𝑧 × 𝒫 𝑧) → ((1st𝑥) ∪ (2nd𝑥)) ⊆ 𝑧)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wcel 2113  cun 3899  wss 3901  𝒫 cpw 4554   × cxp 5622  cfv 6492  1st c1st 7931  2nd c2nd 7932
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-8 2115  ax-9 2123  ax-10 2146  ax-11 2162  ax-12 2184  ax-ext 2708  ax-sep 5241  ax-nul 5251  ax-pr 5377  ax-un 7680
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1544  df-fal 1554  df-ex 1781  df-nf 1785  df-sb 2068  df-mo 2539  df-eu 2569  df-clab 2715  df-cleq 2728  df-clel 2811  df-nfc 2885  df-ne 2933  df-ral 3052  df-rex 3061  df-rab 3400  df-v 3442  df-dif 3904  df-un 3906  df-in 3908  df-ss 3918  df-nul 4286  df-if 4480  df-pw 4556  df-sn 4581  df-pr 4583  df-op 4587  df-uni 4864  df-br 5099  df-opab 5161  df-mpt 5180  df-id 5519  df-xp 5630  df-rel 5631  df-cnv 5632  df-co 5633  df-dm 5634  df-rn 5635  df-iota 6448  df-fun 6494  df-fv 6500  df-1st 7933  df-2nd 7934
This theorem is referenced by:  pgindnf  49961
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