Theorem pgindnf 50642

Description: Version of pgind 50643 with extraneous not-free requirements. (Contributed by Emmett Weisz, 27-May-2024.) (New usage is discouraged.)

Hypotheses

Ref	Expression
pgindnf.1	⊢ Ⅎ𝑥𝜑
pgindnf.2	⊢ Ⅎ𝑦𝜑
pgindnf.3	⊢ (𝑥 = 𝑦 → (𝜓 ↔ 𝜒))
pgindnf.4	⊢ (𝑦 = 𝐴 → (𝜒 ↔ 𝜃))
pgindnf.5	⊢ (𝜑 → ∀𝑥(∀𝑦 ∈ ((1st ‘𝑥) ∪ (2nd ‘𝑥))𝜒 → 𝜓))

Assertion

Ref	Expression
pgindnf	⊢ (𝜑 → (𝐴 ∈ Pg → 𝜃))

Distinct variable groups:   𝑦,𝐴   𝑥,𝑦   𝜒,𝑥   𝜓,𝑦   𝜃,𝑦

Allowed substitution hints:   𝜑(𝑥, 𝑦)   𝜓(𝑥)   𝜒(𝑦)   𝜃(𝑥)   𝐴(𝑥)

Proof of Theorem pgindnf

Dummy variables 𝑎 𝑧 are mutually distinct and distinct from all other variables.

Step	Hyp	Ref	Expression
1		df-pg 50636	. 2 ⊢ Pg = setrecs((𝑎 ∈ V ↦ (𝒫 𝑎 × 𝒫 𝑎)))
2		pgindnf.4	. 2 ⊢ (𝑦 = 𝐴 → (𝜒 ↔ 𝜃))
3		pgindnf.1	. . . . . . 7 ⊢ Ⅎ𝑥𝜑
4		nfv 1947	. . . . . . 7 ⊢ Ⅎ𝑥∀𝑦 ∈ 𝑧 𝜒
5	3, 4	nfan 1932	. . . . . 6 ⊢ Ⅎ𝑥(𝜑 ∧ ∀𝑦 ∈ 𝑧 𝜒)
6		pgindlem 50641	. . . . . . . . . . 11 ⊢ (𝑥 ∈ (𝒫 𝑧 × 𝒫 𝑧) → ((1st ‘𝑥) ∪ (2nd ‘𝑥)) ⊆ 𝑧)
7	6	sseld 3930	. . . . . . . . . 10 ⊢ (𝑥 ∈ (𝒫 𝑧 × 𝒫 𝑧) → (𝑦 ∈ ((1st ‘𝑥) ∪ (2nd ‘𝑥)) → 𝑦 ∈ 𝑧))
8	7	imim1d 83	. . . . . . . . 9 ⊢ (𝑥 ∈ (𝒫 𝑧 × 𝒫 𝑧) → ((𝑦 ∈ 𝑧 → 𝜒) → (𝑦 ∈ ((1st ‘𝑥) ∪ (2nd ‘𝑥)) → 𝜒)))
9	8	ralimdv2 3171	. . . . . . . 8 ⊢ (𝑥 ∈ (𝒫 𝑧 × 𝒫 𝑧) → (∀𝑦 ∈ 𝑧 𝜒 → ∀𝑦 ∈ ((1st ‘𝑥) ∪ (2nd ‘𝑥))𝜒))
10		pgindnf.5	. . . . . . . . 9 ⊢ (𝜑 → ∀𝑥(∀𝑦 ∈ ((1st ‘𝑥) ∪ (2nd ‘𝑥))𝜒 → 𝜓))
11	10	19.21bi 2225	. . . . . . . 8 ⊢ (𝜑 → (∀𝑦 ∈ ((1st ‘𝑥) ∪ (2nd ‘𝑥))𝜒 → 𝜓))
12	9, 11	sylan9r 518	. . . . . . 7 ⊢ ((𝜑 ∧ 𝑥 ∈ (𝒫 𝑧 × 𝒫 𝑧)) → (∀𝑦 ∈ 𝑧 𝜒 → 𝜓))
13	12	impancom 457	. . . . . 6 ⊢ ((𝜑 ∧ ∀𝑦 ∈ 𝑧 𝜒) → (𝑥 ∈ (𝒫 𝑧 × 𝒫 𝑧) → 𝜓))
14	5, 13	ralrimi 3260	. . . . 5 ⊢ ((𝜑 ∧ ∀𝑦 ∈ 𝑧 𝜒) → ∀𝑥 ∈ (𝒫 𝑧 × 𝒫 𝑧)𝜓)
15		pgindnf.3	. . . . . 6 ⊢ (𝑥 = 𝑦 → (𝜓 ↔ 𝜒))
16		vex 3454	. . . . . . . . 9 ⊢ 𝑧 ∈ V
17		pweq 4571	. . . . . . . . . . 11 ⊢ (𝑎 = 𝑧 → 𝒫 𝑎 = 𝒫 𝑧)
18	17	sqxpeqd 5687	. . . . . . . . . 10 ⊢ (𝑎 = 𝑧 → (𝒫 𝑎 × 𝒫 𝑎) = (𝒫 𝑧 × 𝒫 𝑧))
19		eqid 2760	. . . . . . . . . 10 ⊢ (𝑎 ∈ V ↦ (𝒫 𝑎 × 𝒫 𝑎)) = (𝑎 ∈ V ↦ (𝒫 𝑎 × 𝒫 𝑎))
20		vpwex 5342	. . . . . . . . . . 11 ⊢ 𝒫 𝑧 ∈ V
21	20, 20	xpex 7752	. . . . . . . . . 10 ⊢ (𝒫 𝑧 × 𝒫 𝑧) ∈ V
22	18, 19, 21	fvmpt 6986	. . . . . . . . 9 ⊢ (𝑧 ∈ V → ((𝑎 ∈ V ↦ (𝒫 𝑎 × 𝒫 𝑎))‘𝑧) = (𝒫 𝑧 × 𝒫 𝑧))
23	16, 22	ax-mp 5	. . . . . . . 8 ⊢ ((𝑎 ∈ V ↦ (𝒫 𝑎 × 𝒫 𝑎))‘𝑧) = (𝒫 𝑧 × 𝒫 𝑧)
24	23	eqcomi 2769	. . . . . . 7 ⊢ (𝒫 𝑧 × 𝒫 𝑧) = ((𝑎 ∈ V ↦ (𝒫 𝑎 × 𝒫 𝑎))‘𝑧)
25	24	a1i 11	. . . . . 6 ⊢ (𝑥 = 𝑦 → (𝒫 𝑧 × 𝒫 𝑧) = ((𝑎 ∈ V ↦ (𝒫 𝑎 × 𝒫 𝑎))‘𝑧))
26	15, 25	cbvralv2 3893	. . . . 5 ⊢ (∀𝑥 ∈ (𝒫 𝑧 × 𝒫 𝑧)𝜓 ↔ ∀𝑦 ∈ ((𝑎 ∈ V ↦ (𝒫 𝑎 × 𝒫 𝑎))‘𝑧)𝜒)
27	14, 26	sylib 221	. . . 4 ⊢ ((𝜑 ∧ ∀𝑦 ∈ 𝑧 𝜒) → ∀𝑦 ∈ ((𝑎 ∈ V ↦ (𝒫 𝑎 × 𝒫 𝑎))‘𝑧)𝜒)
28	27	ex 418	. . 3 ⊢ (𝜑 → (∀𝑦 ∈ 𝑧 𝜒 → ∀𝑦 ∈ ((𝑎 ∈ V ↦ (𝒫 𝑎 × 𝒫 𝑎))‘𝑧)𝜒))
29	28	alrimiv 1960	. 2 ⊢ (𝜑 → ∀𝑧(∀𝑦 ∈ 𝑧 𝜒 → ∀𝑦 ∈ ((𝑎 ∈ V ↦ (𝒫 𝑎 × 𝒫 𝑎))‘𝑧)𝜒))
30	1, 2, 29	setis 50624	1 ⊢ (𝜑 → (𝐴 ∈ Pg → 𝜃))

This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401  ∀wal 1568   = wceq 1570  Ⅎwnf 1816   ∈ wcel 2145  ∀wral 3076  Vcvv 3450   ∪ cun 3897  𝒫 cpw 4557   ↦ cmpt 5186   × cxp 5653  ‘cfv 6533  1^st c1st 7984  2^nd c2nd 7985  Pgcpg 50635

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-10 2178  ax-11 2194  ax-12 2213  ax-13 2401  ax-ext 2732  ax-rep 5232  ax-sep 5251  ax-nul 5263  ax-pow 5330  ax-pr 5398  ax-un 7736

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2100  df-mo 2564  df-eu 2594  df-clab 2739  df-cleq 2752  df-clel 2835  df-nfc 2909  df-ne 2956  df-ral 3077  df-rex 3087  df-rab 3413  df-v 3452  df-sbc 3740  df-csb 3848  df-dif 3902  df-un 3904  df-in 3906  df-ss 3916  df-nul 4280  df-if 4483  df-pw 4559  df-sn 4585  df-pr 4587  df-op 4591  df-uni 4868  df-br 5104  df-opab 5168  df-mpt 5187  df-id 5550  df-xp 5661  df-rel 5662  df-cnv 5663  df-co 5664  df-dm 5665  df-rn 5666  df-res 5667  df-ima 5668  df-iota 6489  df-fun 6535  df-fv 6541  df-1st 7986  df-2nd 7987  df-setrecs 50610  df-pg 50636

This theorem is used by:  pgind  50643