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Theorem sspss 4061
Description: Subclass in terms of proper subclass. (Contributed by NM, 25-Feb-1996.)
Assertion
Ref Expression
sspss (𝐴𝐵 ↔ (𝐴𝐵𝐴 = 𝐵))

Proof of Theorem sspss
StepHypRef Expression
1 dfpss2 4047 . . . . 5 (𝐴𝐵 ↔ (𝐴𝐵 ∧ ¬ 𝐴 = 𝐵))
21simplbi2 500 . . . 4 (𝐴𝐵 → (¬ 𝐴 = 𝐵𝐴𝐵))
32con1d 145 . . 3 (𝐴𝐵 → (¬ 𝐴𝐵𝐴 = 𝐵))
43orrd 863 . 2 (𝐴𝐵 → (𝐴𝐵𝐴 = 𝐵))
5 pssss 4057 . . 3 (𝐴𝐵𝐴𝐵)
6 eqimss 4002 . . 3 (𝐴 = 𝐵𝐴𝐵)
75, 6jaoi 857 . 2 ((𝐴𝐵𝐴 = 𝐵) → 𝐴𝐵)
84, 7impbii 209 1 (𝐴𝐵 ↔ (𝐴𝐵𝐴 = 𝐵))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wb 206  wo 847   = wceq 1540  wss 3911  wpss 3912
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2008  ax-9 2119  ax-ext 2701
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-ex 1780  df-cleq 2721  df-ne 2926  df-ss 3928  df-pss 3931
This theorem is referenced by:  sspsstri  4064  sspsstr  4067  psssstr  4068  ordsseleq  6349  sorpssuni  7688  sorpssint  7689  ssnnfi  9110  ackbij1b  10167  fin23lem40  10280  zorng  10433  psslinpr  10960  suplem2pr  10982  ressval3d  17192  mrissmrcd  17581  pgpssslw  19528  pgpfac1lem5  19995  idnghm  24664  slelss  27858  dfon2lem4  35767  finminlem  36299  lkrss2N  39155  dvh3dim3N  41436  ordsssucb  43317
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