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Theorem sspss 4054
Description: Subclass in terms of proper subclass. (Contributed by NM, 25-Feb-1996.)
Assertion
Ref Expression
sspss (𝐴𝐵 ↔ (𝐴𝐵𝐴 = 𝐵))

Proof of Theorem sspss
StepHypRef Expression
1 dfpss2 4040 . . . . 5 (𝐴𝐵 ↔ (𝐴𝐵 ∧ ¬ 𝐴 = 𝐵))
21simplbi2 500 . . . 4 (𝐴𝐵 → (¬ 𝐴 = 𝐵𝐴𝐵))
32con1d 145 . . 3 (𝐴𝐵 → (¬ 𝐴𝐵𝐴 = 𝐵))
43orrd 863 . 2 (𝐴𝐵 → (𝐴𝐵𝐴 = 𝐵))
5 pssss 4050 . . 3 (𝐴𝐵𝐴𝐵)
6 eqimss 3992 . . 3 (𝐴 = 𝐵𝐴𝐵)
75, 6jaoi 857 . 2 ((𝐴𝐵𝐴 = 𝐵) → 𝐴𝐵)
84, 7impbii 209 1 (𝐴𝐵 ↔ (𝐴𝐵𝐴 = 𝐵))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wb 206  wo 847   = wceq 1541  wss 3901  wpss 3902
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-9 2123  ax-ext 2708
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-ex 1781  df-cleq 2728  df-ne 2933  df-ss 3918  df-pss 3921
This theorem is referenced by:  sspsstri  4057  sspsstr  4060  psssstr  4061  ordsseleq  6346  sorpssuni  7677  sorpssint  7678  ssnnfi  9096  ackbij1b  10150  fin23lem40  10263  zorng  10416  psslinpr  10944  suplem2pr  10966  ressval3d  17175  mrissmrcd  17565  pgpssslw  19545  pgpfac1lem5  20012  idnghm  24689  leslss  27907  dfon2lem4  35980  finminlem  36514  lkrss2N  39451  dvh3dim3N  41731  ordsssucb  43598
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