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Theorem sspss 4042
Description: Subclass in terms of proper subclass. (Contributed by NM, 25-Feb-1996.)
Assertion
Ref Expression
sspss (𝐴𝐵 ↔ (𝐴𝐵𝐴 = 𝐵))

Proof of Theorem sspss
StepHypRef Expression
1 dfpss2 4028 . . . . 5 (𝐴𝐵 ↔ (𝐴𝐵 ∧ ¬ 𝐴 = 𝐵))
21simplbi2 500 . . . 4 (𝐴𝐵 → (¬ 𝐴 = 𝐵𝐴𝐵))
32con1d 145 . . 3 (𝐴𝐵 → (¬ 𝐴𝐵𝐴 = 𝐵))
43orrd 864 . 2 (𝐴𝐵 → (𝐴𝐵𝐴 = 𝐵))
5 pssss 4038 . . 3 (𝐴𝐵𝐴𝐵)
6 eqimss 3980 . . 3 (𝐴 = 𝐵𝐴𝐵)
75, 6jaoi 858 . 2 ((𝐴𝐵𝐴 = 𝐵) → 𝐴𝐵)
84, 7impbii 209 1 (𝐴𝐵 ↔ (𝐴𝐵𝐴 = 𝐵))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wb 206  wo 848   = wceq 1542  wss 3889  wpss 3890
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-9 2124  ax-ext 2708
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-ex 1782  df-cleq 2728  df-ne 2933  df-ss 3906  df-pss 3909
This theorem is referenced by:  sspsstri  4045  sspsstr  4048  psssstr  4049  ordsseleq  6352  sorpssuni  7686  sorpssint  7687  ssnnfi  9104  ackbij1b  10160  fin23lem40  10273  zorng  10426  psslinpr  10954  suplem2pr  10976  ressval3d  17216  mrissmrcd  17606  pgpssslw  19589  pgpfac1lem5  20056  idnghm  24708  leslss  27901  dfon2lem4  35966  finminlem  36500  lkrss2N  39615  dvh3dim3N  41895  ordsssucb  43763
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