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Theorem sspss 4043
Description: Subclass in terms of proper subclass. (Contributed by NM, 25-Feb-1996.)
Assertion
Ref Expression
sspss (𝐴𝐵 ↔ (𝐴𝐵𝐴 = 𝐵))

Proof of Theorem sspss
StepHypRef Expression
1 dfpss2 4029 . . . . 5 (𝐴𝐵 ↔ (𝐴𝐵 ∧ ¬ 𝐴 = 𝐵))
21simplbi2 500 . . . 4 (𝐴𝐵 → (¬ 𝐴 = 𝐵𝐴𝐵))
32con1d 145 . . 3 (𝐴𝐵 → (¬ 𝐴𝐵𝐴 = 𝐵))
43orrd 864 . 2 (𝐴𝐵 → (𝐴𝐵𝐴 = 𝐵))
5 pssss 4039 . . 3 (𝐴𝐵𝐴𝐵)
6 eqimss 3981 . . 3 (𝐴 = 𝐵𝐴𝐵)
75, 6jaoi 858 . 2 ((𝐴𝐵𝐴 = 𝐵) → 𝐴𝐵)
84, 7impbii 209 1 (𝐴𝐵 ↔ (𝐴𝐵𝐴 = 𝐵))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wb 206  wo 848   = wceq 1542  wss 3890  wpss 3891
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-9 2124  ax-ext 2709
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-ex 1782  df-cleq 2729  df-ne 2934  df-ss 3907  df-pss 3910
This theorem is referenced by:  sspsstri  4046  sspsstr  4049  psssstr  4050  ordsseleq  6347  sorpssuni  7680  sorpssint  7681  ssnnfi  9098  ackbij1b  10154  fin23lem40  10267  zorng  10420  psslinpr  10948  suplem2pr  10970  ressval3d  17210  mrissmrcd  17600  pgpssslw  19583  pgpfac1lem5  20050  idnghm  24721  leslss  27918  dfon2lem4  35985  finminlem  36519  lkrss2N  39632  dvh3dim3N  41912  ordsssucb  43784
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