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Theorem sspss 4052
Description: Subclass in terms of proper subclass. (Contributed by NM, 25-Feb-1996.)
Assertion
Ref Expression
sspss (𝐴𝐵 ↔ (𝐴𝐵𝐴 = 𝐵))

Proof of Theorem sspss
StepHypRef Expression
1 dfpss2 4038 . . . . 5 (𝐴𝐵 ↔ (𝐴𝐵 ∧ ¬ 𝐴 = 𝐵))
21simplbi2 500 . . . 4 (𝐴𝐵 → (¬ 𝐴 = 𝐵𝐴𝐵))
32con1d 145 . . 3 (𝐴𝐵 → (¬ 𝐴𝐵𝐴 = 𝐵))
43orrd 863 . 2 (𝐴𝐵 → (𝐴𝐵𝐴 = 𝐵))
5 pssss 4048 . . 3 (𝐴𝐵𝐴𝐵)
6 eqimss 3990 . . 3 (𝐴 = 𝐵𝐴𝐵)
75, 6jaoi 857 . 2 ((𝐴𝐵𝐴 = 𝐵) → 𝐴𝐵)
84, 7impbii 209 1 (𝐴𝐵 ↔ (𝐴𝐵𝐴 = 𝐵))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wb 206  wo 847   = wceq 1541  wss 3899  wpss 3900
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-9 2123  ax-ext 2706
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-ex 1781  df-cleq 2726  df-ne 2931  df-ss 3916  df-pss 3919
This theorem is referenced by:  sspsstri  4055  sspsstr  4058  psssstr  4059  ordsseleq  6344  sorpssuni  7675  sorpssint  7676  ssnnfi  9092  ackbij1b  10146  fin23lem40  10259  zorng  10412  psslinpr  10940  suplem2pr  10962  ressval3d  17171  mrissmrcd  17561  pgpssslw  19541  pgpfac1lem5  20008  idnghm  24685  slelss  27881  dfon2lem4  35927  finminlem  36461  lkrss2N  39368  dvh3dim3N  41648  ordsssucb  43519
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