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Theorem sspss 4056
Description: Subclass in terms of proper subclass. (Contributed by NM, 25-Feb-1996.)
Assertion
Ref Expression
sspss (𝐴𝐵 ↔ (𝐴𝐵𝐴 = 𝐵))

Proof of Theorem sspss
StepHypRef Expression
1 dfpss2 4042 . . . . 5 (𝐴𝐵 ↔ (𝐴𝐵 ∧ ¬ 𝐴 = 𝐵))
21simplbi2 500 . . . 4 (𝐴𝐵 → (¬ 𝐴 = 𝐵𝐴𝐵))
32con1d 145 . . 3 (𝐴𝐵 → (¬ 𝐴𝐵𝐴 = 𝐵))
43orrd 864 . 2 (𝐴𝐵 → (𝐴𝐵𝐴 = 𝐵))
5 pssss 4052 . . 3 (𝐴𝐵𝐴𝐵)
6 eqimss 3994 . . 3 (𝐴 = 𝐵𝐴𝐵)
75, 6jaoi 858 . 2 ((𝐴𝐵𝐴 = 𝐵) → 𝐴𝐵)
84, 7impbii 209 1 (𝐴𝐵 ↔ (𝐴𝐵𝐴 = 𝐵))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wb 206  wo 848   = wceq 1542  wss 3903  wpss 3904
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-9 2124  ax-ext 2709
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-ex 1782  df-cleq 2729  df-ne 2934  df-ss 3920  df-pss 3923
This theorem is referenced by:  sspsstri  4059  sspsstr  4062  psssstr  4063  ordsseleq  6354  sorpssuni  7687  sorpssint  7688  ssnnfi  9106  ackbij1b  10160  fin23lem40  10273  zorng  10426  psslinpr  10954  suplem2pr  10976  ressval3d  17185  mrissmrcd  17575  pgpssslw  19558  pgpfac1lem5  20025  idnghm  24702  leslss  27920  dfon2lem4  36004  finminlem  36538  lkrss2N  39549  dvh3dim3N  41829  ordsssucb  43696
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