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Theorem dfeldisj5a 39155
Description: Alternate definition of the disjoint elementhood predicate. Members of 𝐴 are pairwise disjoint: if two members overlap, they are equal. (Contributed by Peter Mazsa, 19-Sep-2021.)
Assertion
Ref Expression
dfeldisj5a ( ElDisj 𝐴 ↔ ∀𝑢𝐴𝑣𝐴 ((𝑢𝑣) ≠ ∅ → 𝑢 = 𝑣))
Distinct variable group:   𝑢,𝐴,𝑣

Proof of Theorem dfeldisj5a
StepHypRef Expression
1 dfeldisj5 39154 . 2 ( ElDisj 𝐴 ↔ ∀𝑢𝐴𝑣𝐴 (𝑢 = 𝑣 ∨ (𝑢𝑣) = ∅))
2 orcom 871 . . . 4 ((𝑢 = 𝑣 ∨ (𝑢𝑣) = ∅) ↔ ((𝑢𝑣) = ∅ ∨ 𝑢 = 𝑣))
3 neor 3025 . . . 4 (((𝑢𝑣) = ∅ ∨ 𝑢 = 𝑣) ↔ ((𝑢𝑣) ≠ ∅ → 𝑢 = 𝑣))
42, 3bitri 275 . . 3 ((𝑢 = 𝑣 ∨ (𝑢𝑣) = ∅) ↔ ((𝑢𝑣) ≠ ∅ → 𝑢 = 𝑣))
542ralbii 3113 . 2 (∀𝑢𝐴𝑣𝐴 (𝑢 = 𝑣 ∨ (𝑢𝑣) = ∅) ↔ ∀𝑢𝐴𝑣𝐴 ((𝑢𝑣) ≠ ∅ → 𝑢 = 𝑣))
61, 5bitri 275 1 ( ElDisj 𝐴 ↔ ∀𝑢𝐴𝑣𝐴 ((𝑢𝑣) ≠ ∅ → 𝑢 = 𝑣))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 206  wo 848   = wceq 1542  wne 2933  wral 3052  cin 3889  c0 4274   ElDisj weldisj 38562
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-8 2116  ax-9 2124  ax-10 2147  ax-11 2163  ax-12 2185  ax-ext 2709  ax-sep 5232  ax-pr 5372
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-3an 1089  df-tru 1545  df-fal 1555  df-ex 1782  df-nf 1786  df-sb 2069  df-mo 2540  df-eu 2570  df-clab 2716  df-cleq 2729  df-clel 2812  df-nfc 2886  df-ne 2934  df-ral 3053  df-rex 3063  df-rmo 3343  df-rab 3391  df-v 3432  df-dif 3893  df-un 3895  df-in 3897  df-ss 3907  df-nul 4275  df-if 4468  df-sn 4569  df-pr 4571  df-op 4575  df-br 5087  df-opab 5149  df-id 5521  df-eprel 5526  df-xp 5632  df-rel 5633  df-cnv 5634  df-co 5635  df-dm 5636  df-rn 5637  df-res 5638  df-ima 5639  df-ec 8640  df-coss 38842  df-cnvrefrel 38948  df-disjALTV 39131  df-eldisj 39133
This theorem is referenced by:  eldisjim3  39156
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