Proof of Theorem clsk1indlem2
Step | Hyp | Ref
| Expression |
1 | | id 22 |
. . . . . . . . . 10
⊢ (𝑠 = {∅} → 𝑠 = {∅}) |
2 | | snsspr1 4727 |
. . . . . . . . . 10
⊢ {∅}
⊆ {∅, 1o} |
3 | 1, 2 | eqsstrdi 3955 |
. . . . . . . . 9
⊢ (𝑠 = {∅} → 𝑠 ⊆ {∅,
1o}) |
4 | 3 | ancli 552 |
. . . . . . . 8
⊢ (𝑠 = {∅} → (𝑠 = {∅} ∧ 𝑠 ⊆ {∅,
1o})) |
5 | 4 | con3i 157 |
. . . . . . 7
⊢ (¬
(𝑠 = {∅} ∧ 𝑠 ⊆ {∅,
1o}) → ¬ 𝑠 = {∅}) |
6 | | ssid 3923 |
. . . . . . 7
⊢ 𝑠 ⊆ 𝑠 |
7 | 5, 6 | jctir 524 |
. . . . . 6
⊢ (¬
(𝑠 = {∅} ∧ 𝑠 ⊆ {∅,
1o}) → (¬ 𝑠 = {∅} ∧ 𝑠 ⊆ 𝑠)) |
8 | 7 | orri 862 |
. . . . 5
⊢ ((𝑠 = {∅} ∧ 𝑠 ⊆ {∅,
1o}) ∨ (¬ 𝑠 = {∅} ∧ 𝑠 ⊆ 𝑠)) |
9 | 8 | a1i 11 |
. . . 4
⊢ (𝑠 ∈ 𝒫 3o
→ ((𝑠 = {∅}
∧ 𝑠 ⊆ {∅,
1o}) ∨ (¬ 𝑠 = {∅} ∧ 𝑠 ⊆ 𝑠))) |
10 | | sseq2 3927 |
. . . . 5
⊢ (if(𝑠 = {∅}, {∅,
1o}, 𝑠) =
{∅, 1o} → (𝑠 ⊆ if(𝑠 = {∅}, {∅, 1o}, 𝑠) ↔ 𝑠 ⊆ {∅,
1o})) |
11 | | sseq2 3927 |
. . . . 5
⊢ (if(𝑠 = {∅}, {∅,
1o}, 𝑠) = 𝑠 → (𝑠 ⊆ if(𝑠 = {∅}, {∅, 1o}, 𝑠) ↔ 𝑠 ⊆ 𝑠)) |
12 | 10, 11 | elimif 4476 |
. . . 4
⊢ (𝑠 ⊆ if(𝑠 = {∅}, {∅, 1o}, 𝑠) ↔ ((𝑠 = {∅} ∧ 𝑠 ⊆ {∅, 1o}) ∨
(¬ 𝑠 = {∅} ∧
𝑠 ⊆ 𝑠))) |
13 | 9, 12 | sylibr 237 |
. . 3
⊢ (𝑠 ∈ 𝒫 3o
→ 𝑠 ⊆ if(𝑠 = {∅}, {∅,
1o}, 𝑠)) |
14 | | eqeq1 2741 |
. . . . 5
⊢ (𝑟 = 𝑠 → (𝑟 = {∅} ↔ 𝑠 = {∅})) |
15 | | id 22 |
. . . . 5
⊢ (𝑟 = 𝑠 → 𝑟 = 𝑠) |
16 | 14, 15 | ifbieq2d 4465 |
. . . 4
⊢ (𝑟 = 𝑠 → if(𝑟 = {∅}, {∅, 1o}, 𝑟) = if(𝑠 = {∅}, {∅, 1o}, 𝑠)) |
17 | | clsk1indlem.k |
. . . 4
⊢ 𝐾 = (𝑟 ∈ 𝒫 3o ↦
if(𝑟 = {∅}, {∅,
1o}, 𝑟)) |
18 | | prex 5325 |
. . . . 5
⊢ {∅,
1o} ∈ V |
19 | | vex 3412 |
. . . . 5
⊢ 𝑠 ∈ V |
20 | 18, 19 | ifex 4489 |
. . . 4
⊢ if(𝑠 = {∅}, {∅,
1o}, 𝑠) ∈
V |
21 | 16, 17, 20 | fvmpt 6818 |
. . 3
⊢ (𝑠 ∈ 𝒫 3o
→ (𝐾‘𝑠) = if(𝑠 = {∅}, {∅, 1o}, 𝑠)) |
22 | 13, 21 | sseqtrrd 3942 |
. 2
⊢ (𝑠 ∈ 𝒫 3o
→ 𝑠 ⊆ (𝐾‘𝑠)) |
23 | 22 | rgen 3071 |
1
⊢
∀𝑠 ∈
𝒫 3o𝑠
⊆ (𝐾‘𝑠) |