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Theorem csbopeq1a 8032
Description: Equality theorem for substitution of a class 𝐴 for an ordered pair 𝑥, 𝑦 in 𝐵 (analogue of csbeq1a 3879). (Contributed by NM, 19-Aug-2006.) (Revised by Mario Carneiro, 31-Aug-2015.)
Assertion
Ref Expression
csbopeq1a (𝐴 = ⟨𝑥, 𝑦⟩ → (1st𝐴) / 𝑥(2nd𝐴) / 𝑦𝐵 = 𝐵)

Proof of Theorem csbopeq1a
StepHypRef Expression
1 vex 3454 . . . . 5 𝑥 ∈ V
2 vex 3454 . . . . 5 𝑦 ∈ V
31, 2op2ndd 7982 . . . 4 (𝐴 = ⟨𝑥, 𝑦⟩ → (2nd𝐴) = 𝑦)
43eqcomd 2736 . . 3 (𝐴 = ⟨𝑥, 𝑦⟩ → 𝑦 = (2nd𝐴))
5 csbeq1a 3879 . . 3 (𝑦 = (2nd𝐴) → 𝐵 = (2nd𝐴) / 𝑦𝐵)
64, 5syl 17 . 2 (𝐴 = ⟨𝑥, 𝑦⟩ → 𝐵 = (2nd𝐴) / 𝑦𝐵)
71, 2op1std 7981 . . . 4 (𝐴 = ⟨𝑥, 𝑦⟩ → (1st𝐴) = 𝑥)
87eqcomd 2736 . . 3 (𝐴 = ⟨𝑥, 𝑦⟩ → 𝑥 = (1st𝐴))
9 csbeq1a 3879 . . 3 (𝑥 = (1st𝐴) → (2nd𝐴) / 𝑦𝐵 = (1st𝐴) / 𝑥(2nd𝐴) / 𝑦𝐵)
108, 9syl 17 . 2 (𝐴 = ⟨𝑥, 𝑦⟩ → (2nd𝐴) / 𝑦𝐵 = (1st𝐴) / 𝑥(2nd𝐴) / 𝑦𝐵)
116, 10eqtr2d 2766 1 (𝐴 = ⟨𝑥, 𝑦⟩ → (1st𝐴) / 𝑥(2nd𝐴) / 𝑦𝐵 = 𝐵)
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1540  csb 3865  cop 4598  cfv 6514  1st c1st 7969  2nd c2nd 7970
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2008  ax-8 2111  ax-9 2119  ax-10 2142  ax-11 2158  ax-12 2178  ax-ext 2702  ax-sep 5254  ax-nul 5264  ax-pr 5390  ax-un 7714
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1543  df-fal 1553  df-ex 1780  df-nf 1784  df-sb 2066  df-mo 2534  df-eu 2563  df-clab 2709  df-cleq 2722  df-clel 2804  df-nfc 2879  df-ral 3046  df-rex 3055  df-rab 3409  df-v 3452  df-sbc 3757  df-csb 3866  df-dif 3920  df-un 3922  df-in 3924  df-ss 3934  df-nul 4300  df-if 4492  df-sn 4593  df-pr 4595  df-op 4599  df-uni 4875  df-br 5111  df-opab 5173  df-mpt 5192  df-id 5536  df-xp 5647  df-rel 5648  df-cnv 5649  df-co 5650  df-dm 5651  df-rn 5652  df-iota 6467  df-fun 6516  df-fv 6522  df-1st 7971  df-2nd 7972
This theorem is referenced by:  dfmpo  8084  f1od2  32651  wdom2d2  43031
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