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Theorem csbopeq1a 6422
Description: Equality theorem for substitution of a class 𝐴 for an ordered pair 𝑥, 𝑦 in 𝐵 (analog of csbeq1a 3156). (Contributed by NM, 19-Aug-2006.) (Revised by Mario Carneiro, 31-Aug-2015.)
Assertion
Ref Expression
csbopeq1a (𝐴 = ⟨𝑥, 𝑦⟩ → (1st𝐴) / 𝑥(2nd𝐴) / 𝑦𝐵 = 𝐵)

Proof of Theorem csbopeq1a
StepHypRef Expression
1 vex 2824 . . . . 5 𝑥 ∈ V
2 vex 2824 . . . . 5 𝑦 ∈ V
31, 2op2ndd 6383 . . . 4 (𝐴 = ⟨𝑥, 𝑦⟩ → (2nd𝐴) = 𝑦)
43eqcomd 2244 . . 3 (𝐴 = ⟨𝑥, 𝑦⟩ → 𝑦 = (2nd𝐴))
5 csbeq1a 3156 . . 3 (𝑦 = (2nd𝐴) → 𝐵 = (2nd𝐴) / 𝑦𝐵)
64, 5syl 14 . 2 (𝐴 = ⟨𝑥, 𝑦⟩ → 𝐵 = (2nd𝐴) / 𝑦𝐵)
71, 2op1std 6382 . . . 4 (𝐴 = ⟨𝑥, 𝑦⟩ → (1st𝐴) = 𝑥)
87eqcomd 2244 . . 3 (𝐴 = ⟨𝑥, 𝑦⟩ → 𝑥 = (1st𝐴))
9 csbeq1a 3156 . . 3 (𝑥 = (1st𝐴) → (2nd𝐴) / 𝑦𝐵 = (1st𝐴) / 𝑥(2nd𝐴) / 𝑦𝐵)
108, 9syl 14 . 2 (𝐴 = ⟨𝑥, 𝑦⟩ → (2nd𝐴) / 𝑦𝐵 = (1st𝐴) / 𝑥(2nd𝐴) / 𝑦𝐵)
116, 10eqtr2d 2272 1 (𝐴 = ⟨𝑥, 𝑦⟩ → (1st𝐴) / 𝑥(2nd𝐴) / 𝑦𝐵 = 𝐵)
Colors of variables:    wff set class
This proof depends on syntax axioms:  wi 4   = wceq 1402  csb 3147  cop 3712  cfv 5377  1st c1st 6372  2nd c2nd 6373
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 721  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-10 1558  ax-11 1559  ax-i12 1560  ax-bndl 1562  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-14 2212  ax-ext 2220  ax-sep 4249  ax-pow 4311  ax-pr 4346  ax-un 4578
This proof depends on definitions:  df-bi 117  df-3an 1011  df-tru 1405  df-nf 1514  df-sb 1816  df-eu 2089  df-mo 2090  df-clab 2225  df-cleq 2231  df-clel 2234  df-nfc 2381  df-ral 2533  df-rex 2534  df-v 2823  df-sbc 3052  df-csb 3148  df-un 3224  df-in 3226  df-ss 3233  df-pw 3690  df-sn 3715  df-pr 3716  df-op 3718  df-uni 3936  df-br 4131  df-opab 4193  df-mpt 4194  df-id 4438  df-xp 4780  df-rel 4781  df-cnv 4782  df-co 4783  df-dm 4784  df-rn 4785  df-iota 5337  df-fun 5379  df-fv 5385  df-1st 6374  df-2nd 6375
This theorem is used by:  dfmpo  6459  f1od2  6471
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