Proof of Theorem f1resrcmplf1dlem
| Step | Hyp | Ref
| Expression |
| 1 | | f1resrcmplf1dlem.5 |
. 2
⊢ (𝜑 → (𝐹‘𝑋) = (𝐹‘𝑌)) |
| 2 | | f1resrcmplf1dlem.x |
. . . 4
⊢ (𝜑 → 𝑋 ∈ 𝐶) |
| 3 | | f1resrcmplf1dlem.y |
. . . 4
⊢ (𝜑 → 𝑌 ∈ 𝐷) |
| 4 | 2, 3 | jca 521 |
. . 3
⊢ (𝜑 → (𝑋 ∈ 𝐶 ∧ 𝑌 ∈ 𝐷)) |
| 5 | | f1resrcmplf1dlem.1 |
. . . . . . 7
⊢ (𝜑 → 𝐶 ⊆ 𝐴) |
| 6 | | f1resrcmplf1dlem.3 |
. . . . . . . . 9
⊢ (𝜑 → 𝐹:𝐴⟶𝐵) |
| 7 | 6 | ffnd 6710 |
. . . . . . . 8
⊢ (𝜑 → 𝐹 Fn 𝐴) |
| 8 | | fnfvima 7235 |
. . . . . . . 8
⊢ ((𝐹 Fn 𝐴 ∧ 𝐶 ⊆ 𝐴 ∧ 𝑋 ∈ 𝐶) → (𝐹‘𝑋) ∈ (𝐹 “ 𝐶)) |
| 9 | 7, 8 | syl3an1 1181 |
. . . . . . 7
⊢ ((𝜑 ∧ 𝐶 ⊆ 𝐴 ∧ 𝑋 ∈ 𝐶) → (𝐹‘𝑋) ∈ (𝐹 “ 𝐶)) |
| 10 | 5, 9 | syl3an2 1182 |
. . . . . 6
⊢ ((𝜑 ∧ 𝜑 ∧ 𝑋 ∈ 𝐶) → (𝐹‘𝑋) ∈ (𝐹 “ 𝐶)) |
| 11 | 10 | 3anidm12 1446 |
. . . . 5
⊢ ((𝜑 ∧ 𝑋 ∈ 𝐶) → (𝐹‘𝑋) ∈ (𝐹 “ 𝐶)) |
| 12 | 11 | ex 418 |
. . . 4
⊢ (𝜑 → (𝑋 ∈ 𝐶 → (𝐹‘𝑋) ∈ (𝐹 “ 𝐶))) |
| 13 | | f1resrcmplf1dlem.2 |
. . . . . . 7
⊢ (𝜑 → 𝐷 ⊆ 𝐴) |
| 14 | | fnfvima 7235 |
. . . . . . . 8
⊢ ((𝐹 Fn 𝐴 ∧ 𝐷 ⊆ 𝐴 ∧ 𝑌 ∈ 𝐷) → (𝐹‘𝑌) ∈ (𝐹 “ 𝐷)) |
| 15 | 7, 14 | syl3an1 1181 |
. . . . . . 7
⊢ ((𝜑 ∧ 𝐷 ⊆ 𝐴 ∧ 𝑌 ∈ 𝐷) → (𝐹‘𝑌) ∈ (𝐹 “ 𝐷)) |
| 16 | 13, 15 | syl3an2 1182 |
. . . . . 6
⊢ ((𝜑 ∧ 𝜑 ∧ 𝑌 ∈ 𝐷) → (𝐹‘𝑌) ∈ (𝐹 “ 𝐷)) |
| 17 | 16 | 3anidm12 1446 |
. . . . 5
⊢ ((𝜑 ∧ 𝑌 ∈ 𝐷) → (𝐹‘𝑌) ∈ (𝐹 “ 𝐷)) |
| 18 | 17 | ex 418 |
. . . 4
⊢ (𝜑 → (𝑌 ∈ 𝐷 → (𝐹‘𝑌) ∈ (𝐹 “ 𝐷))) |
| 19 | | f1resrcmplf1dlem.4 |
. . . . . . 7
⊢ (𝜑 → ((𝐹 “ 𝐶) ∩ (𝐹 “ 𝐷)) = ∅) |
| 20 | | disjne 4415 |
. . . . . . 7
⊢ ((((𝐹 “ 𝐶) ∩ (𝐹 “ 𝐷)) = ∅ ∧ (𝐹‘𝑋) ∈ (𝐹 “ 𝐶) ∧ (𝐹‘𝑌) ∈ (𝐹 “ 𝐷)) → (𝐹‘𝑋) ≠ (𝐹‘𝑌)) |
| 21 | 19, 20 | syl3an1 1181 |
. . . . . 6
⊢ ((𝜑 ∧ (𝐹‘𝑋) ∈ (𝐹 “ 𝐶) ∧ (𝐹‘𝑌) ∈ (𝐹 “ 𝐷)) → (𝐹‘𝑋) ≠ (𝐹‘𝑌)) |
| 22 | 21 | 3expib 1140 |
. . . . 5
⊢ (𝜑 → (((𝐹‘𝑋) ∈ (𝐹 “ 𝐶) ∧ (𝐹‘𝑌) ∈ (𝐹 “ 𝐷)) → (𝐹‘𝑋) ≠ (𝐹‘𝑌))) |
| 23 | | neneq 2966 |
. . . . . 6
⊢ ((𝐹‘𝑋) ≠ (𝐹‘𝑌) → ¬ (𝐹‘𝑋) = (𝐹‘𝑌)) |
| 24 | 23 | pm2.21d 122 |
. . . . 5
⊢ ((𝐹‘𝑋) ≠ (𝐹‘𝑌) → ((𝐹‘𝑋) = (𝐹‘𝑌) → 𝑋 = 𝑌)) |
| 25 | 22, 24 | syl6 36 |
. . . 4
⊢ (𝜑 → (((𝐹‘𝑋) ∈ (𝐹 “ 𝐶) ∧ (𝐹‘𝑌) ∈ (𝐹 “ 𝐷)) → ((𝐹‘𝑋) = (𝐹‘𝑌) → 𝑋 = 𝑌))) |
| 26 | 12, 18, 25 | syl2and 620 |
. . 3
⊢ (𝜑 → ((𝑋 ∈ 𝐶 ∧ 𝑌 ∈ 𝐷) → ((𝐹‘𝑋) = (𝐹‘𝑌) → 𝑋 = 𝑌))) |
| 27 | 4, 26 | mpd 16 |
. 2
⊢ (𝜑 → ((𝐹‘𝑋) = (𝐹‘𝑌) → 𝑋 = 𝑌)) |
| 28 | 1, 27 | mpd 16 |
1
⊢ (𝜑 → 𝑋 = 𝑌) |