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Theorem nnuni 36588
Description: The union of a finite ordinal is a finite ordinal. (Contributed by Scott Fenton, 17-Oct-2024.)
Assertion
Ref Expression
nnuni (𝐴 ∈ ω → ∪ 𝐴 ∈ ω)

Proof of Theorem nnuni
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 nn0suc 7910 . 2 (𝐴 ∈ ω → (𝐴 = ∅ ∨ ∃𝑥 ∈ ω 𝐴 = suc 𝑥))
2 unieq 4877 . . . . 5 (𝐴 = ∅ → ∪ 𝐴 = ∪ ∅)
3 uni0 4895 . . . . 5 ∪ ∅ = ∅
42, 3eqtrdi 2811 . . . 4 (𝐴 = ∅ → ∪ 𝐴 = ∅)
5 peano1 7904 . . . 4 ∅ ∈ ω
64, 5eqeltrdi 2868 . . 3 (𝐴 = ∅ → ∪ 𝐴 ∈ ω)
7 nnord 7889 . . . . . . 7 (𝑥 ∈ ω → Ord 𝑥)
8 ordunisuc 7847 . . . . . . 7 (Ord 𝑥 → ∪ suc 𝑥 = 𝑥)
97, 8syl 18 . . . . . 6 (𝑥 ∈ ω → ∪ suc 𝑥 = 𝑥)
10 id 23 . . . . . 6 (𝑥 ∈ ω → 𝑥 ∈ ω)
119, 10eqeltrd 2860 . . . . 5 (𝑥 ∈ ω → ∪ suc 𝑥 ∈ ω)
12 unieq 4877 . . . . . 6 (𝐴 = suc 𝑥 → ∪ 𝐴 = ∪ suc 𝑥)
1312eleq1d 2845 . . . . 5 (𝐴 = suc 𝑥 → (∪ 𝐴 ∈ ω ↔ ∪ suc 𝑥 ∈ ω))
1411, 13syl5ibrcom 250 . . . 4 (𝑥 ∈ ω → (𝐴 = suc 𝑥 → ∪ 𝐴 ∈ ω))
1514rexlimiv 3156 . . 3 (∃𝑥 ∈ ω 𝐴 = suc 𝑥 → ∪ 𝐴 ∈ ω)
166, 15jaoi 871 . 2 ((𝐴 = ∅ ∨ ∃𝑥 ∈ ω 𝐴 = suc 𝑥) → ∪ 𝐴 ∈ ω)
171, 16syl 18 1 (𝐴 ∈ ω → ∪ 𝐴 ∈ ω)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ∨ wo 861   = wceq 1569   ∈ wcel 2144  ∃wrex 3086  ∅c0 4277  ∪ cuni 4866  Ord word 6364  suc csuc 6367  ωcom 7881
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-ext 2732  ax-sep 5248  ax-nul 5259  ax-pr 5391  ax-un 7755
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3or 1104  df-3an 1105  df-tru 1572  df-fal 1582  df-ex 1812  df-sb 2099  df-clab 2739  df-cleq 2752  df-clel 2835  df-ne 2956  df-ral 3077  df-rex 3087  df-rab 3413  df-v 3452  df-ss 3897  df-pss 4013  df-dif 4046  df-in 4090  df-un 4150  df-nul 4278  df-if 4482  df-pw 4558  df-sn 4585  df-pr 4587  df-op 4835  df-uni 4867  df-br 5103  df-opab 5167  df-tr 5212  df-eprel 5551  df-po 5559  df-so 5560  df-fr 5604  df-we 5606  df-ord 6368  df-on 6369  df-lim 6370  df-suc 6371  df-om 7882
This theorem is used by: (None)
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