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Theorem nnuni 36471
Description: The union of a finite ordinal is a finite ordinal. (Contributed by Scott Fenton, 17-Oct-2024.)
Assertion
Ref Expression
nnuni (𝐴 ∈ ω → ∪ 𝐴 ∈ ω)

Proof of Theorem nnuni
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 nn0suc 7904 . 2 (𝐴 ∈ ω → (𝐴 = ∅ ∨ ∃𝑥 ∈ ω 𝐴 = suc 𝑥))
2 unieq 4878 . . . . 5 (𝐴 = ∅ → ∪ 𝐴 = ∪ ∅)
3 uni0 4896 . . . . 5 ∪ ∅ = ∅
42, 3eqtrdi 2812 . . . 4 (𝐴 = ∅ → ∪ 𝐴 = ∅)
5 peano1 7898 . . . 4 ∅ ∈ ω
64, 5eqeltrdi 2869 . . 3 (𝐴 = ∅ → ∪ 𝐴 ∈ ω)
7 nnord 7883 . . . . . . 7 (𝑥 ∈ ω → Ord 𝑥)
8 ordunisuc 7841 . . . . . . 7 (Ord 𝑥 → ∪ suc 𝑥 = 𝑥)
97, 8syl 18 . . . . . 6 (𝑥 ∈ ω → ∪ suc 𝑥 = 𝑥)
10 id 23 . . . . . 6 (𝑥 ∈ ω → 𝑥 ∈ ω)
119, 10eqeltrd 2861 . . . . 5 (𝑥 ∈ ω → ∪ suc 𝑥 ∈ ω)
12 unieq 4878 . . . . . 6 (𝐴 = suc 𝑥 → ∪ 𝐴 = ∪ suc 𝑥)
1312eleq1d 2846 . . . . 5 (𝐴 = suc 𝑥 → (∪ 𝐴 ∈ ω ↔ ∪ suc 𝑥 ∈ ω))
1411, 13syl5ibrcom 250 . . . 4 (𝑥 ∈ ω → (𝐴 = suc 𝑥 → ∪ 𝐴 ∈ ω))
1514rexlimiv 3157 . . 3 (∃𝑥 ∈ ω 𝐴 = suc 𝑥 → ∪ 𝐴 ∈ ω)
166, 15jaoi 871 . 2 ((𝐴 = ∅ ∨ ∃𝑥 ∈ ω 𝐴 = suc 𝑥) → ∪ 𝐴 ∈ ω)
171, 16syl 18 1 (𝐴 ∈ ω → ∪ 𝐴 ∈ ω)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ∨ wo 861   = wceq 1570   ∈ wcel 2145  ∃wrex 3087  ∅c0 4279  ∪ cuni 4867  Ord word 6360  suc csuc 6363  ωcom 7875
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2733  ax-sep 5249  ax-nul 5260  ax-pr 5391  ax-un 7749
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3or 1104  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2740  df-cleq 2753  df-clel 2836  df-ne 2957  df-ral 3078  df-rex 3088  df-rab 3414  df-v 3453  df-dif 3902  df-un 3904  df-in 3906  df-ss 3916  df-pss 3919  df-nul 4280  df-if 4483  df-pw 4559  df-sn 4585  df-pr 4587  df-op 4591  df-uni 4868  df-br 5104  df-opab 5168  df-tr 5213  df-eprel 5551  df-po 5559  df-so 5560  df-fr 5604  df-we 5606  df-ord 6364  df-on 6365  df-lim 6366  df-suc 6367  df-om 7876
This theorem is used by: (None)
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