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Theorem nnuni 36707
Description: The union of a finite ordinal is a finite ordinal. (Contributed by Scott Fenton, 17-Oct-2024.)
Assertion
Ref Expression
nnuni (𝐴 ∈ ω → ∪ 𝐴 ∈ ω)

Proof of Theorem nnuni
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 nn0suc 7940 . 2 (𝐴 ∈ ω → (𝐴 = ∅ ∨ ∃𝑥 ∈ ω 𝐴 = suc 𝑥))
2 unieq 4883 . . . . 5 (𝐴 = ∅ → ∪ 𝐴 = ∪ ∅)
3 uni0 4901 . . . . 5 ∪ ∅ = ∅
42, 3eqtrdi 2814 . . . 4 (𝐴 = ∅ → ∪ 𝐴 = ∅)
5 peano1 7934 . . . 4 ∅ ∈ ω
64, 5eqeltrdi 2872 . . 3 (𝐴 = ∅ → ∪ 𝐴 ∈ ω)
7 nnord 7919 . . . . . . 7 (𝑥 ∈ ω → Ord 𝑥)
8 ordunisuc 7877 . . . . . . 7 (Ord 𝑥 → ∪ suc 𝑥 = 𝑥)
97, 8syl 18 . . . . . 6 (𝑥 ∈ ω → ∪ suc 𝑥 = 𝑥)
10 id 23 . . . . . 6 (𝑥 ∈ ω → 𝑥 ∈ ω)
119, 10eqeltrd 2864 . . . . 5 (𝑥 ∈ ω → ∪ suc 𝑥 ∈ ω)
12 unieq 4883 . . . . . 6 (𝐴 = suc 𝑥 → ∪ 𝐴 = ∪ suc 𝑥)
1312eleq1d 2849 . . . . 5 (𝐴 = suc 𝑥 → (∪ 𝐴 ∈ ω ↔ ∪ suc 𝑥 ∈ ω))
1411, 13syl5ibrcom 250 . . . 4 (𝑥 ∈ ω → (𝐴 = suc 𝑥 → ∪ 𝐴 ∈ ω))
1514rexlimiv 3160 . . 3 (∃𝑥 ∈ ω 𝐴 = suc 𝑥 → ∪ 𝐴 ∈ ω)
166, 15jaoi 871 . 2 ((𝐴 = ∅ ∨ ∃𝑥 ∈ ω 𝐴 = suc 𝑥) → ∪ 𝐴 ∈ ω)
171, 16syl 18 1 (𝐴 ∈ ω → ∪ 𝐴 ∈ ω)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ∨ wo 861   = wceq 1570   ∈ wcel 2147  ∃wrex 3090  ∅c0 4281  ∪ cuni 4872  Ord word 6387  suc csuc 6390  ωcom 7911
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-ext 2735  ax-sep 5255  ax-nul 5266  ax-pr 5398  ax-un 7783
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3or 1104  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2102  df-clab 2742  df-cleq 2755  df-clel 2839  df-ne 2960  df-ral 3081  df-rex 3091  df-rab 3417  df-v 3456  df-ss 3901  df-pss 4017  df-dif 4050  df-in 4094  df-un 4154  df-nul 4282  df-if 4486  df-pw 4562  df-sn 4589  df-pr 4591  df-op 4841  df-uni 4873  df-br 5109  df-opab 5174  df-tr 5219  df-eprel 5558  df-po 5566  df-so 5567  df-fr 5611  df-we 5613  df-ord 6391  df-on 6392  df-lim 6393  df-suc 6394  df-om 7912
This theorem is used by: (None)
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