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Theorem onsucunipr 43396
Description: The successor to the union of any pair of ordinals is the union of the successors of the elements. (Contributed by RP, 12-Feb-2025.)
Assertion
Ref Expression
onsucunipr ((𝐴 ∈ On ∧ 𝐵 ∈ On) → suc {𝐴, 𝐵} = {suc 𝐴, suc 𝐵})

Proof of Theorem onsucunipr
StepHypRef Expression
1 ssequn1 4161 . . . . . 6 (𝐴𝐵 ↔ (𝐴𝐵) = 𝐵)
2 suceq 6419 . . . . . 6 ((𝐴𝐵) = 𝐵 → suc (𝐴𝐵) = suc 𝐵)
31, 2sylbi 217 . . . . 5 (𝐴𝐵 → suc (𝐴𝐵) = suc 𝐵)
43adantl 481 . . . 4 (((𝐴 ∈ On ∧ 𝐵 ∈ On) ∧ 𝐴𝐵) → suc (𝐴𝐵) = suc 𝐵)
5 onsucwordi 43312 . . . . . 6 ((𝐴 ∈ On ∧ 𝐵 ∈ On) → (𝐴𝐵 → suc 𝐴 ⊆ suc 𝐵))
65imp 406 . . . . 5 (((𝐴 ∈ On ∧ 𝐵 ∈ On) ∧ 𝐴𝐵) → suc 𝐴 ⊆ suc 𝐵)
7 ssequn1 4161 . . . . 5 (suc 𝐴 ⊆ suc 𝐵 ↔ (suc 𝐴 ∪ suc 𝐵) = suc 𝐵)
86, 7sylib 218 . . . 4 (((𝐴 ∈ On ∧ 𝐵 ∈ On) ∧ 𝐴𝐵) → (suc 𝐴 ∪ suc 𝐵) = suc 𝐵)
94, 8eqtr4d 2773 . . 3 (((𝐴 ∈ On ∧ 𝐵 ∈ On) ∧ 𝐴𝐵) → suc (𝐴𝐵) = (suc 𝐴 ∪ suc 𝐵))
10 ssequn2 4164 . . . . . 6 (𝐵𝐴 ↔ (𝐴𝐵) = 𝐴)
11 suceq 6419 . . . . . 6 ((𝐴𝐵) = 𝐴 → suc (𝐴𝐵) = suc 𝐴)
1210, 11sylbi 217 . . . . 5 (𝐵𝐴 → suc (𝐴𝐵) = suc 𝐴)
1312adantl 481 . . . 4 (((𝐴 ∈ On ∧ 𝐵 ∈ On) ∧ 𝐵𝐴) → suc (𝐴𝐵) = suc 𝐴)
14 onsucwordi 43312 . . . . . . 7 ((𝐵 ∈ On ∧ 𝐴 ∈ On) → (𝐵𝐴 → suc 𝐵 ⊆ suc 𝐴))
1514ancoms 458 . . . . . 6 ((𝐴 ∈ On ∧ 𝐵 ∈ On) → (𝐵𝐴 → suc 𝐵 ⊆ suc 𝐴))
1615imp 406 . . . . 5 (((𝐴 ∈ On ∧ 𝐵 ∈ On) ∧ 𝐵𝐴) → suc 𝐵 ⊆ suc 𝐴)
17 ssequn2 4164 . . . . 5 (suc 𝐵 ⊆ suc 𝐴 ↔ (suc 𝐴 ∪ suc 𝐵) = suc 𝐴)
1816, 17sylib 218 . . . 4 (((𝐴 ∈ On ∧ 𝐵 ∈ On) ∧ 𝐵𝐴) → (suc 𝐴 ∪ suc 𝐵) = suc 𝐴)
1913, 18eqtr4d 2773 . . 3 (((𝐴 ∈ On ∧ 𝐵 ∈ On) ∧ 𝐵𝐴) → suc (𝐴𝐵) = (suc 𝐴 ∪ suc 𝐵))
20 eloni 6362 . . . 4 (𝐴 ∈ On → Ord 𝐴)
21 eloni 6362 . . . 4 (𝐵 ∈ On → Ord 𝐵)
22 ordtri2or2 6453 . . . 4 ((Ord 𝐴 ∧ Ord 𝐵) → (𝐴𝐵𝐵𝐴))
2320, 21, 22syl2an 596 . . 3 ((𝐴 ∈ On ∧ 𝐵 ∈ On) → (𝐴𝐵𝐵𝐴))
249, 19, 23mpjaodan 960 . 2 ((𝐴 ∈ On ∧ 𝐵 ∈ On) → suc (𝐴𝐵) = (suc 𝐴 ∪ suc 𝐵))
25 uniprg 4899 . . 3 ((𝐴 ∈ On ∧ 𝐵 ∈ On) → {𝐴, 𝐵} = (𝐴𝐵))
26 suceq 6419 . . 3 ( {𝐴, 𝐵} = (𝐴𝐵) → suc {𝐴, 𝐵} = suc (𝐴𝐵))
2725, 26syl 17 . 2 ((𝐴 ∈ On ∧ 𝐵 ∈ On) → suc {𝐴, 𝐵} = suc (𝐴𝐵))
28 onsuc 7805 . . 3 (𝐴 ∈ On → suc 𝐴 ∈ On)
29 onsuc 7805 . . 3 (𝐵 ∈ On → suc 𝐵 ∈ On)
30 uniprg 4899 . . 3 ((suc 𝐴 ∈ On ∧ suc 𝐵 ∈ On) → {suc 𝐴, suc 𝐵} = (suc 𝐴 ∪ suc 𝐵))
3128, 29, 30syl2an 596 . 2 ((𝐴 ∈ On ∧ 𝐵 ∈ On) → {suc 𝐴, suc 𝐵} = (suc 𝐴 ∪ suc 𝐵))
3224, 27, 313eqtr4d 2780 1 ((𝐴 ∈ On ∧ 𝐵 ∈ On) → suc {𝐴, 𝐵} = {suc 𝐴, suc 𝐵})
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 395  wo 847   = wceq 1540  wcel 2108  cun 3924  wss 3926  {cpr 4603   cuni 4883  Ord word 6351  Oncon0 6352  suc csuc 6354
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2007  ax-8 2110  ax-9 2118  ax-ext 2707  ax-sep 5266  ax-nul 5276  ax-pr 5402  ax-un 7729
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3or 1087  df-3an 1088  df-tru 1543  df-fal 1553  df-ex 1780  df-sb 2065  df-clab 2714  df-cleq 2727  df-clel 2809  df-ne 2933  df-ral 3052  df-rex 3061  df-rab 3416  df-v 3461  df-dif 3929  df-un 3931  df-in 3933  df-ss 3943  df-pss 3946  df-nul 4309  df-if 4501  df-pw 4577  df-sn 4602  df-pr 4604  df-op 4608  df-uni 4884  df-br 5120  df-opab 5182  df-tr 5230  df-eprel 5553  df-po 5561  df-so 5562  df-fr 5606  df-we 5608  df-ord 6355  df-on 6356  df-suc 6358
This theorem is referenced by:  onsucunitp  43397
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