Theorem opelco3 36275

Description: Alternate way of saying that an ordered pair is in a composition. (Contributed by Scott Fenton, 6-May-2018.)

Assertion

Ref	Expression
opelco3	⊢ (⟨𝐴, 𝐵⟩ ∈ (𝐶 ∘ 𝐷) ↔ 𝐵 ∈ (𝐶 “ (𝐷 “ {𝐴})))

Proof of Theorem opelco3

Dummy variable 𝑧 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		df-br 5109	. 2 ⊢ (𝐴(𝐶 ∘ 𝐷)𝐵 ↔ ⟨𝐴, 𝐵⟩ ∈ (𝐶 ∘ 𝐷))
2		relco 6109	. . . 4 ⊢ Rel (𝐶 ∘ 𝐷)
3	2	brrelex12i 5715	. . 3 ⊢ (𝐴(𝐶 ∘ 𝐷)𝐵 → (𝐴 ∈ V ∧ 𝐵 ∈ V))
4		snprc 4682	. . . . . 6 ⊢ (¬ 𝐴 ∈ V ↔ {𝐴} = ∅)
5		noel 4290	. . . . . . 7 ⊢ ¬ 𝐵 ∈ ∅
6		imaeq2 6057	. . . . . . . . . 10 ⊢ ({𝐴} = ∅ → (𝐷 “ {𝐴}) = (𝐷 “ ∅))
7	6	imaeq2d 6061	. . . . . . . . 9 ⊢ ({𝐴} = ∅ → (𝐶 “ (𝐷 “ {𝐴})) = (𝐶 “ (𝐷 “ ∅)))
8		ima0 6078	. . . . . . . . . . 11 ⊢ (𝐷 “ ∅) = ∅
9	8	imaeq2i 6059	. . . . . . . . . 10 ⊢ (𝐶 “ (𝐷 “ ∅)) = (𝐶 “ ∅)
10		ima0 6078	. . . . . . . . . 10 ⊢ (𝐶 “ ∅) = ∅
11	9, 10	eqtri 2785	. . . . . . . . 9 ⊢ (𝐶 “ (𝐷 “ ∅)) = ∅
12	7, 11	eqtrdi 2813	. . . . . . . 8 ⊢ ({𝐴} = ∅ → (𝐶 “ (𝐷 “ {𝐴})) = ∅)
13	12	eleq2d 2848	. . . . . . 7 ⊢ ({𝐴} = ∅ → (𝐵 ∈ (𝐶 “ (𝐷 “ {𝐴})) ↔ 𝐵 ∈ ∅))
14	5, 13	mtbiri 330	. . . . . 6 ⊢ ({𝐴} = ∅ → ¬ 𝐵 ∈ (𝐶 “ (𝐷 “ {𝐴})))
15	4, 14	sylbi 220	. . . . 5 ⊢ (¬ 𝐴 ∈ V → ¬ 𝐵 ∈ (𝐶 “ (𝐷 “ {𝐴})))
16	15	con4i 115	. . . 4 ⊢ (𝐵 ∈ (𝐶 “ (𝐷 “ {𝐴})) → 𝐴 ∈ V)
17		elex 3475	. . . 4 ⊢ (𝐵 ∈ (𝐶 “ (𝐷 “ {𝐴})) → 𝐵 ∈ V)
18	16, 17	jca 520	. . 3 ⊢ (𝐵 ∈ (𝐶 “ (𝐷 “ {𝐴})) → (𝐴 ∈ V ∧ 𝐵 ∈ V))
19		df-rex 3089	. . . . 5 ⊢ (∃𝑧 ∈ (𝐷 “ {𝐴})𝑧𝐶𝐵 ↔ ∃𝑧(𝑧 ∈ (𝐷 “ {𝐴}) ∧ 𝑧𝐶𝐵))
20		elimasng 6090	. . . . . . . . . 10 ⊢ ((𝐴 ∈ V ∧ 𝑧 ∈ V) → (𝑧 ∈ (𝐷 “ {𝐴}) ↔ ⟨𝐴, 𝑧⟩ ∈ 𝐷))
21	20	elvd 3460	. . . . . . . . 9 ⊢ (𝐴 ∈ V → (𝑧 ∈ (𝐷 “ {𝐴}) ↔ ⟨𝐴, 𝑧⟩ ∈ 𝐷))
22		df-br 5109	. . . . . . . . 9 ⊢ (𝐴𝐷𝑧 ↔ ⟨𝐴, 𝑧⟩ ∈ 𝐷)
23	21, 22	bitr4di 292	. . . . . . . 8 ⊢ (𝐴 ∈ V → (𝑧 ∈ (𝐷 “ {𝐴}) ↔ 𝐴𝐷𝑧))
24	23	adantr 485	. . . . . . 7 ⊢ ((𝐴 ∈ V ∧ 𝐵 ∈ V) → (𝑧 ∈ (𝐷 “ {𝐴}) ↔ 𝐴𝐷𝑧))
25	24	anbi1d 642	. . . . . 6 ⊢ ((𝐴 ∈ V ∧ 𝐵 ∈ V) → ((𝑧 ∈ (𝐷 “ {𝐴}) ∧ 𝑧𝐶𝐵) ↔ (𝐴𝐷𝑧 ∧ 𝑧𝐶𝐵)))
26	25	exbidv 1950	. . . . 5 ⊢ ((𝐴 ∈ V ∧ 𝐵 ∈ V) → (∃𝑧(𝑧 ∈ (𝐷 “ {𝐴}) ∧ 𝑧𝐶𝐵) ↔ ∃𝑧(𝐴𝐷𝑧 ∧ 𝑧𝐶𝐵)))
27	19, 26	bitr2id 287	. . . 4 ⊢ ((𝐴 ∈ V ∧ 𝐵 ∈ V) → (∃𝑧(𝐴𝐷𝑧 ∧ 𝑧𝐶𝐵) ↔ ∃𝑧 ∈ (𝐷 “ {𝐴})𝑧𝐶𝐵))
28		brcog 5851	. . . 4 ⊢ ((𝐴 ∈ V ∧ 𝐵 ∈ V) → (𝐴(𝐶 ∘ 𝐷)𝐵 ↔ ∃𝑧(𝐴𝐷𝑧 ∧ 𝑧𝐶𝐵)))
29		elimag 6065	. . . . 5 ⊢ (𝐵 ∈ V → (𝐵 ∈ (𝐶 “ (𝐷 “ {𝐴})) ↔ ∃𝑧 ∈ (𝐷 “ {𝐴})𝑧𝐶𝐵))
30	29	adantl 486	. . . 4 ⊢ ((𝐴 ∈ V ∧ 𝐵 ∈ V) → (𝐵 ∈ (𝐶 “ (𝐷 “ {𝐴})) ↔ ∃𝑧 ∈ (𝐷 “ {𝐴})𝑧𝐶𝐵))
31	27, 28, 30	3bitr4d 314	. . 3 ⊢ ((𝐴 ∈ V ∧ 𝐵 ∈ V) → (𝐴(𝐶 ∘ 𝐷)𝐵 ↔ 𝐵 ∈ (𝐶 “ (𝐷 “ {𝐴}))))
32	3, 18, 31	pm5.21nii 381	. 2 ⊢ (𝐴(𝐶 ∘ 𝐷)𝐵 ↔ 𝐵 ∈ (𝐶 “ (𝐷 “ {𝐴})))
33	1, 32	bitr3i 280	1 ⊢ (⟨𝐴, 𝐵⟩ ∈ (𝐶 ∘ 𝐷) ↔ 𝐵 ∈ (𝐶 “ (𝐷 “ {𝐴})))

This proof depends on syntax axioms:  ¬ wn 3   ↔ wb 209   ∧ wa 400   = wceq 1569  ∃wex 1808   ∈ wcel 2142  ∃wrex 3088  Vcvv 3454  ∅c0 4285  {csn 4588  ⟨cop 4594   class class class wbr 5108   “ cima 5663   ∘ ccom 5664

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1824  ax-4 1838  ax-5 1939  ax-6 1996  ax-7 2037  ax-8 2144  ax-9 2152  ax-ext 2734  ax-sep 5256  ax-pr 5403

This proof depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1104  df-tru 1572  df-fal 1582  df-ex 1809  df-sb 2096  df-clab 2741  df-cleq 2754  df-clel 2837  df-ral 3079  df-rex 3089  df-rab 3416  df-v 3456  df-dif 3907  df-un 3909  df-in 3911  df-ss 3921  df-nul 4286  df-if 4487  df-sn 4589  df-pr 4591  df-op 4595  df-br 5109  df-opab 5173  df-xp 5666  df-rel 5667  df-cnv 5668  df-co 5669  df-dm 5670  df-rn 5671  df-res 5672  df-ima 5673

This theorem is used by: (None)