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Theorem sbcan 3857
Description: Distribution of class substitution over conjunction. (Contributed by NM, 31-Dec-2016.) (Revised by NM, 17-Aug-2018.)
Assertion
Ref Expression
sbcan ([𝐴 / 𝑥](𝜑𝜓) ↔ ([𝐴 / 𝑥]𝜑[𝐴 / 𝑥]𝜓))

Proof of Theorem sbcan
Dummy variable 𝑦 is distinct from all other variables.
StepHypRef Expression
1 sbcex 3814 . 2 ([𝐴 / 𝑥](𝜑𝜓) → 𝐴 ∈ V)
2 sbcex 3814 . . 3 ([𝐴 / 𝑥]𝜓𝐴 ∈ V)
32adantl 481 . 2 (([𝐴 / 𝑥]𝜑[𝐴 / 𝑥]𝜓) → 𝐴 ∈ V)
4 dfsbcq2 3807 . . 3 (𝑦 = 𝐴 → ([𝑦 / 𝑥](𝜑𝜓) ↔ [𝐴 / 𝑥](𝜑𝜓)))
5 dfsbcq2 3807 . . . 4 (𝑦 = 𝐴 → ([𝑦 / 𝑥]𝜑[𝐴 / 𝑥]𝜑))
6 dfsbcq2 3807 . . . 4 (𝑦 = 𝐴 → ([𝑦 / 𝑥]𝜓[𝐴 / 𝑥]𝜓))
75, 6anbi12d 631 . . 3 (𝑦 = 𝐴 → (([𝑦 / 𝑥]𝜑 ∧ [𝑦 / 𝑥]𝜓) ↔ ([𝐴 / 𝑥]𝜑[𝐴 / 𝑥]𝜓)))
8 sban 2080 . . 3 ([𝑦 / 𝑥](𝜑𝜓) ↔ ([𝑦 / 𝑥]𝜑 ∧ [𝑦 / 𝑥]𝜓))
94, 7, 8vtoclbg 3569 . 2 (𝐴 ∈ V → ([𝐴 / 𝑥](𝜑𝜓) ↔ ([𝐴 / 𝑥]𝜑[𝐴 / 𝑥]𝜓)))
101, 3, 9pm5.21nii 378 1 ([𝐴 / 𝑥](𝜑𝜓) ↔ ([𝐴 / 𝑥]𝜑[𝐴 / 𝑥]𝜓))
Colors of variables: wff setvar class
Syntax hints:  wb 206  wa 395   = wceq 1537  [wsb 2064  wcel 2108  Vcvv 3488  [wsbc 3804
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1793  ax-4 1807  ax-5 1909  ax-6 1967  ax-7 2007  ax-8 2110  ax-9 2118  ax-ext 2711
This theorem depends on definitions:  df-bi 207  df-an 396  df-tru 1540  df-ex 1778  df-sb 2065  df-clab 2718  df-cleq 2732  df-clel 2819  df-v 3490  df-sbc 3805
This theorem is referenced by:  sbc3an  3874  sbcabel  3900  2nreu  4467  csbopg  4915  csbuni  4960  csbmpt12  5576  csbxp  5799  difopabOLD  5855  sbcfung  6602  sbcfng  6744  sbcfg  6745  fmptsnd  7203  csbfrecsg  8325  f1od2  32735  esum2dlem  34056  bnj976  34753  bnj110  34834  bnj1040  34948  csboprabg  37296  csbmpo123  37297  f1omptsnlem  37302  mptsnunlem  37304  relowlpssretop  37330  csbfinxpg  37354  sbcani  38068  sbccom2lem  38084  minregex  43496  brtrclfv2  43689  cotrclrcl  43704  frege124d  43723  sbiota1  44403  onfrALTlem5  44513  onfrALTlem4  44514  csbingVD  44855  onfrALTlem5VD  44856  onfrALTlem4VD  44857  csbxpgVD  44865  csbunigVD  44869
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