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Theorem sbcan 3806
Description: Distribution of class substitution over conjunction. (Contributed by NM, 31-Dec-2016.) (Revised by NM, 17-Aug-2018.)
Assertion
Ref Expression
sbcan ([𝐴 / 𝑥](𝜑𝜓) ↔ ([𝐴 / 𝑥]𝜑[𝐴 / 𝑥]𝜓))

Proof of Theorem sbcan
Dummy variable 𝑦 is distinct from all other variables.
StepHypRef Expression
1 sbcex 3766 . 2 ([𝐴 / 𝑥](𝜑𝜓) → 𝐴 ∈ V)
2 sbcex 3766 . . 3 ([𝐴 / 𝑥]𝜓𝐴 ∈ V)
32adantl 481 . 2 (([𝐴 / 𝑥]𝜑[𝐴 / 𝑥]𝜓) → 𝐴 ∈ V)
4 dfsbcq2 3759 . . 3 (𝑦 = 𝐴 → ([𝑦 / 𝑥](𝜑𝜓) ↔ [𝐴 / 𝑥](𝜑𝜓)))
5 dfsbcq2 3759 . . . 4 (𝑦 = 𝐴 → ([𝑦 / 𝑥]𝜑[𝐴 / 𝑥]𝜑))
6 dfsbcq2 3759 . . . 4 (𝑦 = 𝐴 → ([𝑦 / 𝑥]𝜓[𝐴 / 𝑥]𝜓))
75, 6anbi12d 632 . . 3 (𝑦 = 𝐴 → (([𝑦 / 𝑥]𝜑 ∧ [𝑦 / 𝑥]𝜓) ↔ ([𝐴 / 𝑥]𝜑[𝐴 / 𝑥]𝜓)))
8 sban 2081 . . 3 ([𝑦 / 𝑥](𝜑𝜓) ↔ ([𝑦 / 𝑥]𝜑 ∧ [𝑦 / 𝑥]𝜓))
94, 7, 8vtoclbg 3526 . 2 (𝐴 ∈ V → ([𝐴 / 𝑥](𝜑𝜓) ↔ ([𝐴 / 𝑥]𝜑[𝐴 / 𝑥]𝜓)))
101, 3, 9pm5.21nii 378 1 ([𝐴 / 𝑥](𝜑𝜓) ↔ ([𝐴 / 𝑥]𝜑[𝐴 / 𝑥]𝜓))
Colors of variables: wff setvar class
Syntax hints:  wb 206  wa 395   = wceq 1540  [wsb 2065  wcel 2109  Vcvv 3450  [wsbc 3756
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2008  ax-8 2111  ax-9 2119  ax-ext 2702
This theorem depends on definitions:  df-bi 207  df-an 396  df-tru 1543  df-ex 1780  df-sb 2066  df-clab 2709  df-cleq 2722  df-clel 2804  df-v 3452  df-sbc 3757
This theorem is referenced by:  sbc3an  3821  sbcabel  3844  2nreu  4410  csbopg  4858  csbuni  4903  csbmpt12  5520  csbxp  5741  difopabOLD  5797  sbcfung  6543  sbcfng  6688  sbcfg  6689  fmptsnd  7146  csbfrecsg  8266  f1od2  32651  esum2dlem  34089  bnj976  34774  bnj110  34855  bnj1040  34969  csboprabg  37325  csbmpo123  37326  f1omptsnlem  37331  mptsnunlem  37333  relowlpssretop  37359  csbfinxpg  37383  sbcani  38109  sbccom2lem  38125  minregex  43530  brtrclfv2  43723  cotrclrcl  43738  frege124d  43757  sbiota1  44430  onfrALTlem5  44539  onfrALTlem4  44540  csbingVD  44880  onfrALTlem5VD  44881  onfrALTlem4VD  44882  csbxpgVD  44890  csbunigVD  44894  rspesbcd  44934
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