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Theorem sbcan 3788
Description: Distribution of class substitution over conjunction. (Contributed by NM, 31-Dec-2016.) (Revised by NM, 17-Aug-2018.)
Assertion
Ref Expression
sbcan ([𝐴 / 𝑥](𝜑𝜓) ↔ ([𝐴 / 𝑥]𝜑[𝐴 / 𝑥]𝜓))

Proof of Theorem sbcan
Dummy variable 𝑦 is distinct from all other variables.
StepHypRef Expression
1 sbcex 3749 . 2 ([𝐴 / 𝑥](𝜑𝜓) → 𝐴 ∈ V)
2 sbcex 3749 . . 3 ([𝐴 / 𝑥]𝜓𝐴 ∈ V)
32adantl 487 . 2 (([𝐴 / 𝑥]𝜑[𝐴 / 𝑥]𝜓) → 𝐴 ∈ V)
4 dfsbcq2 3742 . . 3 (𝑦 = 𝐴 → ([𝑦 / 𝑥](𝜑𝜓) ↔ [𝐴 / 𝑥](𝜑𝜓)))
5 dfsbcq2 3742 . . . 4 (𝑦 = 𝐴 → ([𝑦 / 𝑥]𝜑[𝐴 / 𝑥]𝜑))
6 dfsbcq2 3742 . . . 4 (𝑦 = 𝐴 → ([𝑦 / 𝑥]𝜓[𝐴 / 𝑥]𝜓))
75, 6anbi12d 644 . . 3 (𝑦 = 𝐴 → (([𝑦 / 𝑥]𝜑 ∧ [𝑦 / 𝑥]𝜓) ↔ ([𝐴 / 𝑥]𝜑[𝐴 / 𝑥]𝜓)))
8 sban 2117 . . 3 ([𝑦 / 𝑥](𝜑𝜓) ↔ ([𝑦 / 𝑥]𝜑 ∧ [𝑦 / 𝑥]𝜓))
94, 7, 8vtoclbg 3519 . 2 (𝐴 ∈ V → ([𝐴 / 𝑥](𝜑𝜓) ↔ ([𝐴 / 𝑥]𝜑[𝐴 / 𝑥]𝜓)))
101, 3, 9pm5.21nii 381 1 ([𝐴 / 𝑥](𝜑𝜓) ↔ ([𝐴 / 𝑥]𝜑[𝐴 / 𝑥]𝜓))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wb 209  wa 401   = wceq 1570  [wsb 2099  wcel 2145  Vcvv 3450  [wsbc 3739
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2732
This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-ex 1813  df-sb 2100  df-clab 2739  df-cleq 2752  df-clel 2835  df-v 3452  df-sbc 3740
This theorem is used by:  sbc3an  3803  sbcabel  3825  2nreu  4402  csbopg  4851  csbuni  4898  csbmpt12  5536  csbxp  5756  sbcfung  6557  sbcfng  6699  sbcfg  6700  fmptsnd  7167  csbfrecsg  8283  f1od2  33190  esum2dlem  34602  bnj976  35287  bnj110  35367  bnj1040  35481  csboprabg  38084  csbmpo123  38085  f1omptsnlem  38090  mptsnunlem  38092  relowlpssretop  38118  csbfinxpg  38142  sbcani  38856  sbccom2lem  38872  minregex  44374  brtrclfv2  44567  cotrclrcl  44582  frege124d  44601  sbiota1  45258  onfrALTlem5  45365  onfrALTlem4  45366  csbingVD  45706  onfrALTlem5VD  45707  onfrALTlem4VD  45708  csbxpgVD  45716  csbunigVD  45720  rspesbcd  45760
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