Theorem fneq1d 5445

Description: Equality deduction for function predicate with domain. (Contributed by Paul Chapman, 22-Jun-2011.)

Hypothesis

Ref	Expression
fneq1d.1	⊢ (𝜑 → 𝐹 = 𝐺)

Assertion

Ref	Expression
fneq1d	⊢ (𝜑 → (𝐹 Fn 𝐴 ↔ 𝐺 Fn 𝐴))

Proof of Theorem fneq1d

Step	Hyp	Ref	Expression
1		fneq1d.1	. 2 ⊢ (𝜑 → 𝐹 = 𝐺)
2		fneq1 5443	. 2 ⊢ (𝐹 = 𝐺 → (𝐹 Fn 𝐴 ↔ 𝐺 Fn 𝐴))
3	1, 2	syl 14	1 ⊢ (𝜑 → (𝐹 Fn 𝐴 ↔ 𝐺 Fn 𝐴))

Syntax hints:   → wi 4   ↔ wb 105   = wceq 1398   Fn wfn 5346

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-ext 2214

This theorem depends on definitions:  df-bi 117  df-3an 1007  df-tru 1401  df-nf 1510  df-sb 1812  df-clab 2219  df-cleq 2225  df-clel 2228  df-nfc 2373  df-v 2814  df-un 3214  df-in 3216  df-ss 3223  df-sn 3694  df-pr 3695  df-op 3697  df-br 4109  df-opab 4171  df-rel 4755  df-cnv 4756  df-co 4757  df-dm 4758  df-fun 5353  df-fn 5354

This theorem is referenced by:  fneq12d  5447  f1o00  5650  f1ompt  5827  fmpt2d  5838  f1ocnvd  6256  offval2  6281  ofrfval2  6282  caofinvl  6291  f1od2  6430  cc3  7581  ccatvalfn  11285  swrdlen  11340  plusffng  13570  grpinvfng  13749  grpinvf1o  13775  mulgfng  13833  srg1zr  14123  rrgsupp  14403  scaffng  14449  neif  14998  fnmptd  16568