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Theorem 1stinr 9824
Description: The first component of the value of a right injection is 1o. (Contributed by AV, 27-Jun-2022.)
Assertion
Ref Expression
1stinr (𝑋𝑉 → (1st ‘(inr‘𝑋)) = 1o)

Proof of Theorem 1stinr
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 df-inr 9798 . . . 4 inr = (𝑥 ∈ V ↦ ⟨1o, 𝑥⟩)
2 opeq2 4830 . . . 4 (𝑥 = 𝑋 → ⟨1o, 𝑥⟩ = ⟨1o, 𝑋⟩)
3 elex 3462 . . . 4 (𝑋𝑉𝑋 ∈ V)
4 opex 5420 . . . . 5 ⟨1o, 𝑋⟩ ∈ V
54a1i 11 . . . 4 (𝑋𝑉 → ⟨1o, 𝑋⟩ ∈ V)
61, 2, 3, 5fvmptd3 6969 . . 3 (𝑋𝑉 → (inr‘𝑋) = ⟨1o, 𝑋⟩)
76fveq2d 6844 . 2 (𝑋𝑉 → (1st ‘(inr‘𝑋)) = (1st ‘⟨1o, 𝑋⟩))
8 1oex 8415 . . 3 1o ∈ V
9 op1stg 7926 . . 3 ((1o ∈ V ∧ 𝑋𝑉) → (1st ‘⟨1o, 𝑋⟩) = 1o)
108, 9mpan 689 . 2 (𝑋𝑉 → (1st ‘⟨1o, 𝑋⟩) = 1o)
117, 10eqtrd 2778 1 (𝑋𝑉 → (1st ‘(inr‘𝑋)) = 1o)
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1542  wcel 2107  Vcvv 3444  cop 4591  cfv 6494  1st c1st 7912  1oc1o 8398  inrcinr 9795
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1798  ax-4 1812  ax-5 1914  ax-6 1972  ax-7 2012  ax-8 2109  ax-9 2117  ax-10 2138  ax-11 2155  ax-12 2172  ax-ext 2709  ax-sep 5255  ax-nul 5262  ax-pr 5383  ax-un 7665
This theorem depends on definitions:  df-bi 206  df-an 398  df-or 847  df-3an 1090  df-tru 1545  df-fal 1555  df-ex 1783  df-nf 1787  df-sb 2069  df-mo 2540  df-eu 2569  df-clab 2716  df-cleq 2730  df-clel 2816  df-nfc 2888  df-ral 3064  df-rex 3073  df-rab 3407  df-v 3446  df-dif 3912  df-un 3914  df-in 3916  df-ss 3926  df-nul 4282  df-if 4486  df-sn 4586  df-pr 4588  df-op 4592  df-uni 4865  df-br 5105  df-opab 5167  df-mpt 5188  df-id 5530  df-xp 5638  df-rel 5639  df-cnv 5640  df-co 5641  df-dm 5642  df-rn 5643  df-suc 6322  df-iota 6446  df-fun 6496  df-fv 6502  df-1st 7914  df-1o 8405  df-inr 9798
This theorem is referenced by:  updjudhcoinrg  9828
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