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Theorem 1stinr 9889
Description: The first component of the value of a right injection is 1o. (Contributed by AV, 27-Jun-2022.)
Assertion
Ref Expression
1stinr (𝑋𝑉 → (1st ‘(inr‘𝑋)) = 1o)

Proof of Theorem 1stinr
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 df-inr 9863 . . . 4 inr = (𝑥 ∈ V ↦ ⟨1o, 𝑥⟩)
2 opeq2 4834 . . . 4 (𝑥 = 𝑋 → ⟨1o, 𝑥⟩ = ⟨1o, 𝑋⟩)
3 elex 3477 . . . 4 (𝑋𝑉𝑋 ∈ V)
4 opex 5433 . . . . 5 ⟨1o, 𝑋⟩ ∈ V
54a1i 11 . . . 4 (𝑋𝑉 → ⟨1o, 𝑋⟩ ∈ V)
61, 2, 3, 5fvmptd3 7001 . . 3 (𝑋𝑉 → (inr‘𝑋) = ⟨1o, 𝑋⟩)
76fveq2d 6873 . 2 (𝑋𝑉 → (1st ‘(inr‘𝑋)) = (1st ‘⟨1o, 𝑋⟩))
8 1oex 8449 . . 3 1o ∈ V
9 op1stg 7984 . . 3 ((1o ∈ V ∧ 𝑋𝑉) → (1st ‘⟨1o, 𝑋⟩) = 1o)
108, 9mpan 700 . 2 (𝑋𝑉 → (1st ‘⟨1o, 𝑋⟩) = 1o)
117, 10eqtrd 2799 1 (𝑋𝑉 → (1st ‘(inr‘𝑋)) = 1o)
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1562  wcel 2144  Vcvv 3456  cop 4590  cfv 6523  1st c1st 7970  1oc1o 8432  inrcinr 9860
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1817  ax-4 1831  ax-5 1932  ax-6 1989  ax-7 2030  ax-8 2146  ax-9 2154  ax-10 2177  ax-11 2193  ax-12 2214  ax-ext 2736  ax-sep 5248  ax-nul 5258  ax-pr 5392  ax-un 7720
This theorem depends on definitions:  df-bi 209  df-an 400  df-or 859  df-3an 1101  df-tru 1565  df-fal 1575  df-ex 1802  df-nf 1806  df-sb 2093  df-mo 2568  df-eu 2598  df-clab 2743  df-cleq 2756  df-clel 2839  df-nfc 2913  df-ne 2960  df-ral 3079  df-rex 3089  df-rab 3417  df-v 3458  df-dif 3909  df-un 3911  df-in 3913  df-ss 3923  df-nul 4288  df-if 4483  df-sn 4585  df-pr 4587  df-op 4591  df-uni 4868  df-br 5103  df-opab 5165  df-mpt 5184  df-id 5544  df-xp 5655  df-rel 5656  df-cnv 5657  df-co 5658  df-dm 5659  df-rn 5660  df-suc 6354  df-iota 6479  df-fun 6525  df-fv 6531  df-1st 7972  df-1o 8439  df-inr 9863
This theorem is referenced by:  updjudhcoinrg  9893
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