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Theorem 1stinr 9848
Description: The first component of the value of a right injection is 1o. (Contributed by AV, 27-Jun-2022.)
Assertion
Ref Expression
1stinr (𝑋𝑉 → (1st ‘(inr‘𝑋)) = 1o)

Proof of Theorem 1stinr
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 df-inr 9822 . . . 4 inr = (𝑥 ∈ V ↦ ⟨1o, 𝑥⟩)
2 opeq2 4807 . . . 4 (𝑥 = 𝑋 → ⟨1o, 𝑥⟩ = ⟨1o, 𝑋⟩)
3 elex 3454 . . . 4 (𝑋𝑉𝑋 ∈ V)
4 opex 5405 . . . . 5 ⟨1o, 𝑋⟩ ∈ V
54a1i 11 . . . 4 (𝑋𝑉 → ⟨1o, 𝑋⟩ ∈ V)
61, 2, 3, 5fvmptd3 6962 . . 3 (𝑋𝑉 → (inr‘𝑋) = ⟨1o, 𝑋⟩)
76fveq2d 6834 . 2 (𝑋𝑉 → (1st ‘(inr‘𝑋)) = (1st ‘⟨1o, 𝑋⟩))
8 1oex 8409 . . 3 1o ∈ V
9 op1stg 7945 . . 3 ((1o ∈ V ∧ 𝑋𝑉) → (1st ‘⟨1o, 𝑋⟩) = 1o)
108, 9mpan 697 . 2 (𝑋𝑉 → (1st ‘⟨1o, 𝑋⟩) = 1o)
117, 10eqtrd 2776 1 (𝑋𝑉 → (1st ‘(inr‘𝑋)) = 1o)
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1548  wcel 2121  Vcvv 3433  cop 4563  cfv 6488  1st c1st 7931  1oc1o 8392  inrcinr 9819
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1803  ax-4 1817  ax-5 1918  ax-6 1975  ax-7 2016  ax-8 2123  ax-9 2131  ax-10 2154  ax-11 2170  ax-12 2191  ax-ext 2713  ax-sep 5220  ax-nul 5230  ax-pr 5364  ax-un 7681
This theorem depends on definitions:  df-bi 209  df-an 398  df-or 855  df-3an 1095  df-tru 1551  df-fal 1561  df-ex 1788  df-nf 1792  df-sb 2075  df-mo 2545  df-eu 2575  df-clab 2720  df-cleq 2733  df-clel 2816  df-nfc 2890  df-ne 2937  df-ral 3056  df-rex 3066  df-rab 3394  df-v 3435  df-dif 3887  df-un 3889  df-in 3891  df-ss 3901  df-nul 4264  df-if 4457  df-sn 4558  df-pr 4560  df-op 4564  df-uni 4841  df-br 5075  df-opab 5137  df-mpt 5156  df-id 5515  df-xp 5626  df-rel 5627  df-cnv 5628  df-co 5629  df-dm 5630  df-rn 5631  df-suc 6319  df-iota 6444  df-fun 6490  df-fv 6496  df-1st 7933  df-1o 8399  df-inr 9822
This theorem is referenced by:  updjudhcoinrg  9852
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