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Theorem 1stinr 9350
Description: The first component of the value of a right injection is 1o. (Contributed by AV, 27-Jun-2022.)
Assertion
Ref Expression
1stinr (𝑋𝑉 → (1st ‘(inr‘𝑋)) = 1o)

Proof of Theorem 1stinr
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 df-inr 9324 . . . 4 inr = (𝑥 ∈ V ↦ ⟨1o, 𝑥⟩)
2 opeq2 4796 . . . 4 (𝑥 = 𝑋 → ⟨1o, 𝑥⟩ = ⟨1o, 𝑋⟩)
3 elex 3511 . . . 4 (𝑋𝑉𝑋 ∈ V)
4 opex 5347 . . . . 5 ⟨1o, 𝑋⟩ ∈ V
54a1i 11 . . . 4 (𝑋𝑉 → ⟨1o, 𝑋⟩ ∈ V)
61, 2, 3, 5fvmptd3 6784 . . 3 (𝑋𝑉 → (inr‘𝑋) = ⟨1o, 𝑋⟩)
76fveq2d 6667 . 2 (𝑋𝑉 → (1st ‘(inr‘𝑋)) = (1st ‘⟨1o, 𝑋⟩))
8 1oex 8102 . . 3 1o ∈ V
9 op1stg 7693 . . 3 ((1o ∈ V ∧ 𝑋𝑉) → (1st ‘⟨1o, 𝑋⟩) = 1o)
108, 9mpan 688 . 2 (𝑋𝑉 → (1st ‘⟨1o, 𝑋⟩) = 1o)
117, 10eqtrd 2854 1 (𝑋𝑉 → (1st ‘(inr‘𝑋)) = 1o)
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1531  wcel 2108  Vcvv 3493  cop 4565  cfv 6348  1st c1st 7679  1oc1o 8087  inrcinr 9321
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1790  ax-4 1804  ax-5 1905  ax-6 1964  ax-7 2009  ax-8 2110  ax-9 2118  ax-10 2139  ax-11 2154  ax-12 2170  ax-ext 2791  ax-sep 5194  ax-nul 5201  ax-pow 5257  ax-pr 5320  ax-un 7453
This theorem depends on definitions:  df-bi 209  df-an 399  df-or 844  df-3or 1083  df-3an 1084  df-tru 1534  df-ex 1775  df-nf 1779  df-sb 2064  df-mo 2616  df-eu 2648  df-clab 2798  df-cleq 2812  df-clel 2891  df-nfc 2961  df-ne 3015  df-ral 3141  df-rex 3142  df-rab 3145  df-v 3495  df-sbc 3771  df-dif 3937  df-un 3939  df-in 3941  df-ss 3950  df-pss 3952  df-nul 4290  df-if 4466  df-pw 4539  df-sn 4560  df-pr 4562  df-tp 4564  df-op 4566  df-uni 4831  df-br 5058  df-opab 5120  df-mpt 5138  df-tr 5164  df-id 5453  df-eprel 5458  df-po 5467  df-so 5468  df-fr 5507  df-we 5509  df-xp 5554  df-rel 5555  df-cnv 5556  df-co 5557  df-dm 5558  df-rn 5559  df-ord 6187  df-on 6188  df-suc 6190  df-iota 6307  df-fun 6350  df-fv 6356  df-1st 7681  df-1o 8094  df-inr 9324
This theorem is referenced by:  updjudhcoinrg  9354
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