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Theorem ralxpes 8138
Description: A version of ralxp 5825 with explicit substitution. (Contributed by Scott Fenton, 21-Aug-2024.)
Assertion
Ref Expression
ralxpes (∀𝑥 ∈ (𝐴 × 𝐵)[(1st𝑥) / 𝑦][(2nd𝑥) / 𝑧]𝜑 ↔ ∀𝑦𝐴𝑧𝐵 𝜑)
Distinct variable groups:   𝑥,𝐴,𝑦   𝑥,𝐵,𝑦,𝑧   𝜑,𝑥
Allowed substitution hints:   𝜑(𝑦, 𝑧)   𝐴(𝑧)

Proof of Theorem ralxpes
StepHypRef Expression
1 nfsbc1v 3762 . 2 𝑦[(1st𝑥) / 𝑦][(2nd𝑥) / 𝑧]𝜑
2 nfcv 2924 . . 3 𝑧(1st𝑥)
3 nfsbc1v 3762 . . 3 𝑧[(2nd𝑥) / 𝑧]𝜑
42, 3nfsbcw 3764 . 2 𝑧[(1st𝑥) / 𝑦][(2nd𝑥) / 𝑧]𝜑
5 nfv 1947 . 2 𝑥𝜑
6 sbcopeq1a 8050 . 2 (𝑥 = ⟨𝑦, 𝑧⟩ → ([(1st𝑥) / 𝑦][(2nd𝑥) / 𝑧]𝜑𝜑))
71, 4, 5, 6ralxpf 5830 1 (∀𝑥 ∈ (𝐴 × 𝐵)[(1st𝑥) / 𝑦][(2nd𝑥) / 𝑧]𝜑 ↔ ∀𝑦𝐴𝑧𝐵 𝜑)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wb 209  wral 3078  [wsbc 3742   × cxp 5657  cfv 6537  1st c1st 7988  2nd c2nd 7989
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-10 2178  ax-11 2194  ax-12 2215  ax-ext 2734  ax-sep 5255  ax-nul 5267  ax-pr 5402  ax-un 7740
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2100  df-mo 2566  df-eu 2596  df-clab 2741  df-cleq 2754  df-clel 2837  df-nfc 2911  df-ne 2958  df-ral 3079  df-rex 3089  df-rab 3415  df-v 3455  df-sbc 3743  df-csb 3851  df-dif 3905  df-un 3907  df-in 3909  df-ss 3919  df-nul 4283  df-if 4486  df-sn 4588  df-pr 4590  df-op 4594  df-uni 4871  df-iun 4956  df-br 5108  df-opab 5172  df-mpt 5191  df-id 5554  df-xp 5665  df-rel 5666  df-cnv 5667  df-co 5668  df-dm 5669  df-rn 5670  df-iota 6493  df-fun 6539  df-fv 6545  df-1st 7990  df-2nd 7991
This theorem is used by:  frpoins3xpg  8142
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