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Theorem tposco 8209
Description: Transposition of a composition. (Contributed by Mario Carneiro, 4-Oct-2015.)
Assertion
Ref Expression
tposco tpos (𝐹𝐺) = (𝐹 ∘ tpos 𝐺)

Proof of Theorem tposco
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 coass 6232 . 2 ((𝐹𝐺) ∘ (𝑥 ∈ ((V × V) ∪ {∅}) ↦ {𝑥})) = (𝐹 ∘ (𝐺 ∘ (𝑥 ∈ ((V × V) ∪ {∅}) ↦ {𝑥})))
2 dftpos4 8197 . 2 tpos (𝐹𝐺) = ((𝐹𝐺) ∘ (𝑥 ∈ ((V × V) ∪ {∅}) ↦ {𝑥}))
3 dftpos4 8197 . . 3 tpos 𝐺 = (𝐺 ∘ (𝑥 ∈ ((V × V) ∪ {∅}) ↦ {𝑥}))
43coeq2i 5817 . 2 (𝐹 ∘ tpos 𝐺) = (𝐹 ∘ (𝐺 ∘ (𝑥 ∈ ((V × V) ∪ {∅}) ↦ {𝑥})))
51, 2, 43eqtr4i 2770 1 tpos (𝐹𝐺) = (𝐹 ∘ tpos 𝐺)
Colors of variables: wff setvar class
Syntax hints:   = wceq 1542  Vcvv 3442  cun 3901  c0 4287  {csn 4582   cuni 4865  cmpt 5181   × cxp 5630  ccnv 5631  ccom 5636  tpos ctpos 8177
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-8 2116  ax-9 2124  ax-10 2147  ax-11 2163  ax-12 2185  ax-ext 2709  ax-sep 5243  ax-nul 5253  ax-pow 5312  ax-pr 5379  ax-un 7690
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-3an 1089  df-tru 1545  df-fal 1555  df-ex 1782  df-nf 1786  df-sb 2069  df-mo 2540  df-eu 2570  df-clab 2716  df-cleq 2729  df-clel 2812  df-nfc 2886  df-ne 2934  df-ral 3053  df-rex 3063  df-rab 3402  df-v 3444  df-dif 3906  df-un 3908  df-in 3910  df-ss 3920  df-nul 4288  df-if 4482  df-pw 4558  df-sn 4583  df-pr 4585  df-op 4589  df-uni 4866  df-br 5101  df-opab 5163  df-mpt 5182  df-id 5527  df-xp 5638  df-rel 5639  df-cnv 5640  df-co 5641  df-dm 5642  df-rn 5643  df-res 5644  df-ima 5645  df-iota 6456  df-fun 6502  df-fn 6503  df-fv 6508  df-tpos 8178
This theorem is referenced by: (None)
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