Theorem uncom 3225

Description: Commutative law for union of classes. Exercise 6 of [TakeutiZaring] p. 17. (Contributed by NM, 25-Jun-1998.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)

Assertion

Ref	Expression
uncom	⊢ (𝐴 ∪ 𝐵) = (𝐵 ∪ 𝐴)

Proof of Theorem uncom

Dummy variable 𝑥 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		orcom 718	. . 3 ⊢ ((𝑥 ∈ 𝐴 ∨ 𝑥 ∈ 𝐵) ↔ (𝑥 ∈ 𝐵 ∨ 𝑥 ∈ 𝐴))
2		elun 3222	. . 3 ⊢ (𝑥 ∈ (𝐵 ∪ 𝐴) ↔ (𝑥 ∈ 𝐵 ∨ 𝑥 ∈ 𝐴))
3	1, 2	bitr4i 186	. 2 ⊢ ((𝑥 ∈ 𝐴 ∨ 𝑥 ∈ 𝐵) ↔ 𝑥 ∈ (𝐵 ∪ 𝐴))
4	3	uneqri 3223	1 ⊢ (𝐴 ∪ 𝐵) = (𝐵 ∪ 𝐴)

Syntax hints:   ∨ wo 698   = wceq 1332   ∈ wcel 1481   ∪ cun 3074

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 699  ax-5 1424  ax-7 1425  ax-gen 1426  ax-ie1 1470  ax-ie2 1471  ax-8 1483  ax-10 1484  ax-11 1485  ax-i12 1486  ax-bndl 1487  ax-4 1488  ax-17 1507  ax-i9 1511  ax-ial 1515  ax-i5r 1516  ax-ext 2122

This theorem depends on definitions:  df-bi 116  df-tru 1335  df-nf 1438  df-sb 1737  df-clab 2127  df-cleq 2133  df-clel 2136  df-nfc 2271  df-v 2691  df-un 3080

This theorem is referenced by:  equncom  3226  uneq2  3229  un12  3239  un23  3240  ssun2  3245  unss2  3252  ssequn2  3254  undir  3331  dif32  3344  undif2ss  3443  uneqdifeqim  3453  prcom  3607  tpass  3627  prprc1  3639  difsnss  3674  suc0  4341  fvun2  5496  fmptpr  5620  fvsnun2  5626  fsnunfv  5629  omv2  6369  phplem2  6755  undifdc  6820  endjusym  6989  fzsuc2  9890  fseq1p1m1  9905  ennnfonelem1  11956  setsslid  12048  exmid1stab  13368