Step | Hyp | Ref
| Expression |
1 | | fcoinvbr.e |
. . . . 5
⊢ ∼ =
(◡𝐹 ∘ 𝐹) |
2 | 1 | breqi 5046 |
. . . 4
⊢ (𝑋 ∼ 𝑌 ↔ 𝑋(◡𝐹 ∘ 𝐹)𝑌) |
3 | | brcog 5719 |
. . . 4
⊢ ((𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴) → (𝑋(◡𝐹 ∘ 𝐹)𝑌 ↔ ∃𝑧(𝑋𝐹𝑧 ∧ 𝑧◡𝐹𝑌))) |
4 | 2, 3 | syl5bb 286 |
. . 3
⊢ ((𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴) → (𝑋 ∼ 𝑌 ↔ ∃𝑧(𝑋𝐹𝑧 ∧ 𝑧◡𝐹𝑌))) |
5 | 4 | 3adant1 1131 |
. 2
⊢ ((𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴) → (𝑋 ∼ 𝑌 ↔ ∃𝑧(𝑋𝐹𝑧 ∧ 𝑧◡𝐹𝑌))) |
6 | | fvex 6700 |
. . . . 5
⊢ (𝐹‘𝑋) ∈ V |
7 | 6 | eqvinc 3548 |
. . . 4
⊢ ((𝐹‘𝑋) = (𝐹‘𝑌) ↔ ∃𝑧(𝑧 = (𝐹‘𝑋) ∧ 𝑧 = (𝐹‘𝑌))) |
8 | | eqcom 2746 |
. . . . . 6
⊢ (𝑧 = (𝐹‘𝑋) ↔ (𝐹‘𝑋) = 𝑧) |
9 | | eqcom 2746 |
. . . . . 6
⊢ (𝑧 = (𝐹‘𝑌) ↔ (𝐹‘𝑌) = 𝑧) |
10 | 8, 9 | anbi12i 630 |
. . . . 5
⊢ ((𝑧 = (𝐹‘𝑋) ∧ 𝑧 = (𝐹‘𝑌)) ↔ ((𝐹‘𝑋) = 𝑧 ∧ (𝐹‘𝑌) = 𝑧)) |
11 | 10 | exbii 1854 |
. . . 4
⊢
(∃𝑧(𝑧 = (𝐹‘𝑋) ∧ 𝑧 = (𝐹‘𝑌)) ↔ ∃𝑧((𝐹‘𝑋) = 𝑧 ∧ (𝐹‘𝑌) = 𝑧)) |
12 | 7, 11 | bitri 278 |
. . 3
⊢ ((𝐹‘𝑋) = (𝐹‘𝑌) ↔ ∃𝑧((𝐹‘𝑋) = 𝑧 ∧ (𝐹‘𝑌) = 𝑧)) |
13 | | fnbrfvb 6735 |
. . . . . . 7
⊢ ((𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝐴) → ((𝐹‘𝑋) = 𝑧 ↔ 𝑋𝐹𝑧)) |
14 | 13 | 3adant3 1133 |
. . . . . 6
⊢ ((𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴) → ((𝐹‘𝑋) = 𝑧 ↔ 𝑋𝐹𝑧)) |
15 | | fnbrfvb 6735 |
. . . . . . 7
⊢ ((𝐹 Fn 𝐴 ∧ 𝑌 ∈ 𝐴) → ((𝐹‘𝑌) = 𝑧 ↔ 𝑌𝐹𝑧)) |
16 | 15 | 3adant2 1132 |
. . . . . 6
⊢ ((𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴) → ((𝐹‘𝑌) = 𝑧 ↔ 𝑌𝐹𝑧)) |
17 | 14, 16 | anbi12d 634 |
. . . . 5
⊢ ((𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴) → (((𝐹‘𝑋) = 𝑧 ∧ (𝐹‘𝑌) = 𝑧) ↔ (𝑋𝐹𝑧 ∧ 𝑌𝐹𝑧))) |
18 | | vex 3404 |
. . . . . . . 8
⊢ 𝑧 ∈ V |
19 | | brcnvg 5732 |
. . . . . . . 8
⊢ ((𝑧 ∈ V ∧ 𝑌 ∈ 𝐴) → (𝑧◡𝐹𝑌 ↔ 𝑌𝐹𝑧)) |
20 | 18, 19 | mpan 690 |
. . . . . . 7
⊢ (𝑌 ∈ 𝐴 → (𝑧◡𝐹𝑌 ↔ 𝑌𝐹𝑧)) |
21 | 20 | 3ad2ant3 1136 |
. . . . . 6
⊢ ((𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴) → (𝑧◡𝐹𝑌 ↔ 𝑌𝐹𝑧)) |
22 | 21 | anbi2d 632 |
. . . . 5
⊢ ((𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴) → ((𝑋𝐹𝑧 ∧ 𝑧◡𝐹𝑌) ↔ (𝑋𝐹𝑧 ∧ 𝑌𝐹𝑧))) |
23 | 17, 22 | bitr4d 285 |
. . . 4
⊢ ((𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴) → (((𝐹‘𝑋) = 𝑧 ∧ (𝐹‘𝑌) = 𝑧) ↔ (𝑋𝐹𝑧 ∧ 𝑧◡𝐹𝑌))) |
24 | 23 | exbidv 1928 |
. . 3
⊢ ((𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴) → (∃𝑧((𝐹‘𝑋) = 𝑧 ∧ (𝐹‘𝑌) = 𝑧) ↔ ∃𝑧(𝑋𝐹𝑧 ∧ 𝑧◡𝐹𝑌))) |
25 | 12, 24 | syl5bb 286 |
. 2
⊢ ((𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴) → ((𝐹‘𝑋) = (𝐹‘𝑌) ↔ ∃𝑧(𝑋𝐹𝑧 ∧ 𝑧◡𝐹𝑌))) |
26 | 5, 25 | bitr4d 285 |
1
⊢ ((𝐹 Fn 𝐴 ∧ 𝑋 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴) → (𝑋 ∼ 𝑌 ↔ (𝐹‘𝑋) = (𝐹‘𝑌))) |