Theorem lssn0 19145

Description: A subspace is not empty. (Contributed by NM, 12-Jan-2014.) (Revised by Mario Carneiro, 8-Jan-2015.)

Hypothesis

Ref	Expression
lssn0.s	⊢ 𝑆 = (LSubSp‘𝑊)

Assertion

Ref	Expression
lssn0	⊢ (𝑈 ∈ 𝑆 → 𝑈 ≠ ∅)

Proof of Theorem lssn0

Dummy variables 𝑎 𝑏 𝑥 are mutually distinct and distinct from all other variables.

Step	Hyp	Ref	Expression
1		eqid 2806	. . 3 ⊢ (Scalar‘𝑊) = (Scalar‘𝑊)
2		eqid 2806	. . 3 ⊢ (Base‘(Scalar‘𝑊)) = (Base‘(Scalar‘𝑊))
3		eqid 2806	. . 3 ⊢ (Base‘𝑊) = (Base‘𝑊)
4		eqid 2806	. . 3 ⊢ (+g‘𝑊) = (+g‘𝑊)
5		eqid 2806	. . 3 ⊢ ( ·𝑠 ‘𝑊) = ( ·𝑠 ‘𝑊)
6		lssn0.s	. . 3 ⊢ 𝑆 = (LSubSp‘𝑊)
7	1, 2, 3, 4, 5, 6	islss 19139	. 2 ⊢ (𝑈 ∈ 𝑆 ↔ (𝑈 ⊆ (Base‘𝑊) ∧ 𝑈 ≠ ∅ ∧ ∀𝑥 ∈ (Base‘(Scalar‘𝑊))∀𝑎 ∈ 𝑈 ∀𝑏 ∈ 𝑈 ((𝑥( ·𝑠 ‘𝑊)𝑎)(+g‘𝑊)𝑏) ∈ 𝑈))
8	7	simp2bi 1169	1 ⊢ (𝑈 ∈ 𝑆 → 𝑈 ≠ ∅)

Syntax hints:   → wi 4   = wceq 1637   ∈ wcel 2156   ≠ wne 2978  ∀wral 3096   ⊆ wss 3769  ∅c0 4116  ‘cfv 6101  (class class class)co 6874  Basecbs 16068  +_gcplusg 16153  Scalarcsca 16156   ·_𝑠 cvsca 16157  LSubSpclss 19136

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1877  ax-4 1894  ax-5 2001  ax-6 2068  ax-7 2104  ax-8 2158  ax-9 2165  ax-10 2185  ax-11 2201  ax-12 2214  ax-13 2420  ax-ext 2784  ax-sep 4975  ax-nul 4983  ax-pow 5035  ax-pr 5096

This theorem depends on definitions:  df-bi 198  df-an 385  df-or 866  df-3an 1102  df-tru 1641  df-ex 1860  df-nf 1864  df-sb 2061  df-eu 2634  df-mo 2635  df-clab 2793  df-cleq 2799  df-clel 2802  df-nfc 2937  df-ne 2979  df-ral 3101  df-rex 3102  df-rab 3105  df-v 3393  df-sbc 3634  df-dif 3772  df-un 3774  df-in 3776  df-ss 3783  df-nul 4117  df-if 4280  df-pw 4353  df-sn 4371  df-pr 4373  df-op 4377  df-uni 4631  df-br 4845  df-opab 4907  df-mpt 4924  df-id 5219  df-xp 5317  df-rel 5318  df-cnv 5319  df-co 5320  df-dm 5321  df-iota 6064  df-fun 6103  df-fv 6109  df-ov 6877  df-lss 19137

This theorem is referenced by:  00lss  19146  lss0cl  19151  lssne0  19155  lsssubg  19164  lbsextlem2  19368  minveclem1  23407