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Theorem s3eqd 15043
Description: Equality theorem for a length 3 word. (Contributed by Mario Carneiro, 27-Feb-2016.)
Hypotheses
Ref Expression
s2eqd.1 (𝜑 → 𝐴 = 𝑁)
s2eqd.2 (𝜑 → 𝐵 = 𝑂)
s3eqd.3 (𝜑 → 𝐶 = 𝑃)
Assertion
Ref Expression
s3eqd (𝜑 → ⟨“𝐴𝐵𝐶”⟩ = ⟨“𝑁𝑂𝑃”⟩)

Proof of Theorem s3eqd
StepHypRef Expression
1 s2eqd.1 . . . 4 (𝜑 → 𝐴 = 𝑁)
2 s2eqd.2 . . . 4 (𝜑 → 𝐵 = 𝑂)
31, 2s2eqd 15042 . . 3 (𝜑 → ⟨“𝐴𝐵”⟩ = ⟨“𝑁𝑂”⟩)
4 s3eqd.3 . . . 4 (𝜑 → 𝐶 = 𝑃)
54s1eqd 14775 . . 3 (𝜑 → ⟨“𝐶”⟩ = ⟨“𝑃”⟩)
63, 5oveq12d 7461 . 2 (𝜑 → (⟨“𝐴𝐵”⟩ ++ ⟨“𝐶”⟩) = (⟨“𝑁𝑂”⟩ ++ ⟨“𝑃”⟩))
7 df-s3 15028 . 2 ⟨“𝐴𝐵𝐶”⟩ = (⟨“𝐴𝐵”⟩ ++ ⟨“𝐶”⟩)
8 df-s3 15028 . 2 ⟨“𝑁𝑂𝑃”⟩ = (⟨“𝑁𝑂”⟩ ++ ⟨“𝑃”⟩)
96, 7, 83eqtr4g 2823 1 (𝜑 → ⟨“𝐴𝐵𝐶”⟩ = ⟨“𝑁𝑂𝑃”⟩)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   = wceq 1570  (class class class)co 7443   ++ cconcat 14742  ⟨“cs1 14769  ⟨“cs2 15020  ⟨“cs3 15021
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-ext 2735
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2102  df-clab 2742  df-cleq 2755  df-clel 2839  df-rab 3417  df-v 3456  df-ss 3901  df-dif 4050  df-un 4154  df-nul 4282  df-if 4486  df-sn 4589  df-pr 4591  df-op 4839  df-uni 4871  df-br 5107  df-iota 6512  df-fv 6566  df-ov 7446  df-s1 14770  df-s2 15027  df-s3 15028
This theorem is used by:  s4eqd  15044  s3eq2  15049  s3rex  15130  s3sndisj  15149  s3iunsndisj  15150  ragcgr  29212  perpneq  29219  isperp2  29220  isperp2d  29221  footexALT  29223  footexlem2  29225  foot  29227  perprag  29232  perpdragALT  29233  colperpexlem1  29236  lmiisolem  29331  hypcgrlem1  29335  hypcgrlem2  29336  trgcopyeu  29343  iscgra  29346  iscgra1  29347  iscgrad  29348  sacgr  29369  isleag  29396  isleagd  29397  elcgrabasi  29405  angmgmaddov1  29418  angmgmaddov2  29419  angmgmaddcl  29421  angmgmval  29424  iseqlg  29442  prlngmid2  29469  inagcgrasubhl  33079  inagcgratrgw  33085
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