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| Mirrors > Home > MPE Home > Th. List > wess | Structured version Visualization version GIF version | ||
| Description: Subset theorem for the well-ordering predicate. Exercise 4 of [TakeutiZaring] p. 31. (Contributed by NM, 19-Apr-1994.) |
| Ref | Expression |
|---|---|
| wess | ⊢ (𝐴 ⊆ 𝐵 → (𝑅 We 𝐵 → 𝑅 We 𝐴)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | frss 5619 | . . 3 ⊢ (𝐴 ⊆ 𝐵 → (𝑅 Fr 𝐵 → 𝑅 Fr 𝐴)) | |
| 2 | soss 5583 | . . 3 ⊢ (𝐴 ⊆ 𝐵 → (𝑅 Or 𝐵 → 𝑅 Or 𝐴)) | |
| 3 | 1, 2 | anim12d 621 | . 2 ⊢ (𝐴 ⊆ 𝐵 → ((𝑅 Fr 𝐵 ∧ 𝑅 Or 𝐵) → (𝑅 Fr 𝐴 ∧ 𝑅 Or 𝐴))) |
| 4 | df-we 5610 | . 2 ⊢ (𝑅 We 𝐵 ↔ (𝑅 Fr 𝐵 ∧ 𝑅 Or 𝐵)) | |
| 5 | df-we 5610 | . 2 ⊢ (𝑅 We 𝐴 ↔ (𝑅 Fr 𝐴 ∧ 𝑅 Or 𝐴)) | |
| 6 | 3, 4, 5 | 3imtr4g 299 | 1 ⊢ (𝐴 ⊆ 𝐵 → (𝑅 We 𝐵 → 𝑅 We 𝐴)) |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: → wi 4 ∧ wa 401 ⊆ wss 3900 Or wor 5562 Fr wfr 5605 We wwe 5607 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1828 ax-4 1842 ax-5 1945 |
| This proof depends on definitions: df-bi 210 df-an 402 df-ral 3081 df-ss 3901 df-po 5563 df-so 5564 df-fr 5608 df-we 5610 |
| This theorem is used by: wefrc 5649 trssord 6397 ordelord 6402 f1we 7386 dford5 7822 omsinds 7922 fnwelem 8170 dfrecs3 8408 ordtypelem8 9546 oismo 9561 cantnfcl 9695 infxpenlem 10119 ac10ct 10140 dfac12lem2 10250 cflim2 10368 cofsmo 10374 hsmexlem1 10531 smobeth 10698 canthwelem 10762 gruina 10930 ltwefz 14133 onf1we 35803 wevsev 36041 wevonprcf1o 36042 vonf1onprcf1ac 36044 onprcf1acwevdlem1 36045 onprcf1acwevdlem2 36046 onprcr 36631 welb 38862 aomclem4 44252 dfac11 44257 oaun3lem1 44568 onfrALTlem3 45718 onfrALTlem3VD 46060 |
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