Theorem sseqtrd 3063

Description: Substitution of equality into a subclass relationship. (Contributed by NM, 25-Apr-2004.)

Hypotheses

Ref	Expression
sseqtrd.1	⊢ (𝜑 → 𝐴 ⊆ 𝐵)
sseqtrd.2	⊢ (𝜑 → 𝐵 = 𝐶)

Assertion

Ref	Expression
sseqtrd	⊢ (𝜑 → 𝐴 ⊆ 𝐶)

Proof of Theorem sseqtrd

Step	Hyp	Ref	Expression
1		sseqtrd.1	. 2 ⊢ (𝜑 → 𝐴 ⊆ 𝐵)
2		sseqtrd.2	. . 3 ⊢ (𝜑 → 𝐵 = 𝐶)
3	2	sseq2d 3055	. 2 ⊢ (𝜑 → (𝐴 ⊆ 𝐵 ↔ 𝐴 ⊆ 𝐶))
4	1, 3	mpbid 146	1 ⊢ (𝜑 → 𝐴 ⊆ 𝐶)

Syntax hints:   → wi 4   = wceq 1290   ⊆ wss 3000

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1382  ax-7 1383  ax-gen 1384  ax-ie1 1428  ax-ie2 1429  ax-8 1441  ax-11 1443  ax-4 1446  ax-17 1465  ax-i9 1469  ax-ial 1473  ax-i5r 1474  ax-ext 2071

This theorem depends on definitions:  df-bi 116  df-nf 1396  df-sb 1694  df-clab 2076  df-cleq 2082  df-clel 2085  df-in 3006  df-ss 3013

This theorem is referenced by:  sseqtr4d  3064  fssdmd  5187  resasplitss  5203  nnaword2  6287  erssxp  6329  phpm  6635  ioodisj  9464  tgcl  11818  basgen  11834  bastop1  11837  bastop2  11838  clsss2  11883  nninfalllemn  12164