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Theorem eldju2ndl 10029
Description: The second component of an element of a disjoint union is an element of the left class of the disjoint union if its first component is the empty set. (Contributed by AV, 26-Jun-2022.)
Assertion
Ref Expression
eldju2ndl ((𝑋 ∈ (𝐴 ⊔ 𝐵) ∧ (1st ‘𝑋) = ∅) → (2nd ‘𝑋) ∈ 𝐴)

Proof of Theorem eldju2ndl
StepHypRef Expression
1 df-dju 10006 . . . . 5 (𝐴 ⊔ 𝐵) = (({∅} × 𝐴) ∪ ({1o} × 𝐵))
21eleq2i 2856 . . . 4 (𝑋 ∈ (𝐴 ⊔ 𝐵) ↔ 𝑋 ∈ (({∅} × 𝐴) ∪ ({1o} × 𝐵)))
3 elun 4155 . . . 4 (𝑋 ∈ (({∅} × 𝐴) ∪ ({1o} × 𝐵)) ↔ (𝑋 ∈ ({∅} × 𝐴) ∨ 𝑋 ∈ ({1o} × 𝐵)))
42, 3bitri 278 . . 3 (𝑋 ∈ (𝐴 ⊔ 𝐵) ↔ (𝑋 ∈ ({∅} × 𝐴) ∨ 𝑋 ∈ ({1o} × 𝐵)))
5 elxp6 8056 . . . . 5 (𝑋 ∈ ({∅} × 𝐴) ↔ (𝑋 = ⟨(1st ‘𝑋), (2nd ‘𝑋)⟩ ∧ ((1st ‘𝑋) ∈ {∅} ∧ (2nd ‘𝑋) ∈ 𝐴)))
6 simprr 785 . . . . . 6 ((𝑋 = ⟨(1st ‘𝑋), (2nd ‘𝑋)⟩ ∧ ((1st ‘𝑋) ∈ {∅} ∧ (2nd ‘𝑋) ∈ 𝐴)) → (2nd ‘𝑋) ∈ 𝐴)
76a1d 26 . . . . 5 ((𝑋 = ⟨(1st ‘𝑋), (2nd ‘𝑋)⟩ ∧ ((1st ‘𝑋) ∈ {∅} ∧ (2nd ‘𝑋) ∈ 𝐴)) → ((1st ‘𝑋) = ∅ → (2nd ‘𝑋) ∈ 𝐴))
85, 7sylbi 220 . . . 4 (𝑋 ∈ ({∅} × 𝐴) → ((1st ‘𝑋) = ∅ → (2nd ‘𝑋) ∈ 𝐴))
9 elxp6 8056 . . . . 5 (𝑋 ∈ ({1o} × 𝐵) ↔ (𝑋 = ⟨(1st ‘𝑋), (2nd ‘𝑋)⟩ ∧ ((1st ‘𝑋) ∈ {1o} ∧ (2nd ‘𝑋) ∈ 𝐵)))
10 elsni 4601 . . . . . . 7 ((1st ‘𝑋) ∈ {1o} → (1st ‘𝑋) = 1o)
11 1n0 8520 . . . . . . . 8 1o ≠ ∅
12 neeq1 3021 . . . . . . . 8 ((1st ‘𝑋) = 1o → ((1st ‘𝑋) ≠ ∅ ↔ 1o ≠ ∅))
1311, 12mpbiri 261 . . . . . . 7 ((1st ‘𝑋) = 1o → (1st ‘𝑋) ≠ ∅)
14 eqneqall 2970 . . . . . . . 8 ((1st ‘𝑋) = ∅ → ((1st ‘𝑋) ≠ ∅ → (2nd ‘𝑋) ∈ 𝐴))
1514com12 33 . . . . . . 7 ((1st ‘𝑋) ≠ ∅ → ((1st ‘𝑋) = ∅ → (2nd ‘𝑋) ∈ 𝐴))
1610, 13, 153syl 19 . . . . . 6 ((1st ‘𝑋) ∈ {1o} → ((1st ‘𝑋) = ∅ → (2nd ‘𝑋) ∈ 𝐴))
1716ad2antrl 741 . . . . 5 ((𝑋 = ⟨(1st ‘𝑋), (2nd ‘𝑋)⟩ ∧ ((1st ‘𝑋) ∈ {1o} ∧ (2nd ‘𝑋) ∈ 𝐵)) → ((1st ‘𝑋) = ∅ → (2nd ‘𝑋) ∈ 𝐴))
189, 17sylbi 220 . . . 4 (𝑋 ∈ ({1o} × 𝐵) → ((1st ‘𝑋) = ∅ → (2nd ‘𝑋) ∈ 𝐴))
198, 18jaoi 871 . . 3 ((𝑋 ∈ ({∅} × 𝐴) ∨ 𝑋 ∈ ({1o} × 𝐵)) → ((1st ‘𝑋) = ∅ → (2nd ‘𝑋) ∈ 𝐴))
204, 19sylbi 220 . 2 (𝑋 ∈ (𝐴 ⊔ 𝐵) → ((1st ‘𝑋) = ∅ → (2nd ‘𝑋) ∈ 𝐴))
2120imp 412 1 ((𝑋 ∈ (𝐴 ⊔ 𝐵) ∧ (1st ‘𝑋) = ∅) → (2nd ‘𝑋) ∈ 𝐴)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ∧ wa 401   ∨ wo 861   = wceq 1570   ∈ wcel 2147   ≠ wne 2959   ∪ cun 4152  ∅c0 4281  {csn 4588  ⟨cop 4838   × cxp 5653  ‘cfv 6555  1st c1st 8020  2nd c2nd 8021  1oc1o 8494   ⊔ cdju 10003
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-10 2180  ax-11 2197  ax-12 2216  ax-ext 2735  ax-sep 5252  ax-nul 5263  ax-pr 5395  ax-un 7772
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2102  df-mo 2567  df-eu 2597  df-clab 2742  df-cleq 2755  df-clel 2839  df-nfc 2913  df-ne 2960  df-ral 3081  df-rex 3091  df-rab 3417  df-v 3456  df-ss 3901  df-dif 4050  df-in 4094  df-un 4154  df-nul 4282  df-if 4486  df-sn 4589  df-pr 4591  df-op 4839  df-uni 4871  df-br 5107  df-opab 5171  df-mpt 5190  df-id 5550  df-xp 5661  df-rel 5662  df-cnv 5663  df-co 5664  df-dm 5665  df-rn 5666  df-suc 6383  df-iota 6509  df-fun 6557  df-fv 6563  df-1st 8022  df-2nd 8023  df-1o 8501  df-dju 10006
This theorem is used by:  updjudhf  10036
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