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Theorem ordtri2 6397
Description: A trichotomy law for ordinals. (Contributed by NM, 25-Nov-1995.)
Assertion
Ref Expression
ordtri2 ((Ord 𝐴 ∧ Ord 𝐵) → (𝐴𝐵 ↔ ¬ (𝐴 = 𝐵𝐵𝐴)))

Proof of Theorem ordtri2
StepHypRef Expression
1 ordsseleq 6391 . . . . 5 ((Ord 𝐵 ∧ Ord 𝐴) → (𝐵𝐴 ↔ (𝐵𝐴𝐵 = 𝐴)))
2 eqcom 2776 . . . . . . 7 (𝐵 = 𝐴𝐴 = 𝐵)
32orbi2i 925 . . . . . 6 ((𝐵𝐴𝐵 = 𝐴) ↔ (𝐵𝐴𝐴 = 𝐵))
4 orcom 883 . . . . . 6 ((𝐵𝐴𝐴 = 𝐵) ↔ (𝐴 = 𝐵𝐵𝐴))
53, 4bitri 278 . . . . 5 ((𝐵𝐴𝐵 = 𝐴) ↔ (𝐴 = 𝐵𝐵𝐴))
61, 5bitrdi 290 . . . 4 ((Ord 𝐵 ∧ Ord 𝐴) → (𝐵𝐴 ↔ (𝐴 = 𝐵𝐵𝐴)))
7 ordtri1 6395 . . . 4 ((Ord 𝐵 ∧ Ord 𝐴) → (𝐵𝐴 ↔ ¬ 𝐴𝐵))
86, 7bitr3d 284 . . 3 ((Ord 𝐵 ∧ Ord 𝐴) → ((𝐴 = 𝐵𝐵𝐴) ↔ ¬ 𝐴𝐵))
98ancoms 463 . 2 ((Ord 𝐴 ∧ Ord 𝐵) → ((𝐴 = 𝐵𝐵𝐴) ↔ ¬ 𝐴𝐵))
109con2bid 357 1 ((Ord 𝐴 ∧ Ord 𝐵) → (𝐴𝐵 ↔ ¬ (𝐴 = 𝐵𝐵𝐴)))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wi 4  wb 209  wa 400  wo 860   = wceq 1567  wcel 2149  wss 3913  Ord word 6360
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1822  ax-4 1836  ax-5 1937  ax-6 1994  ax-7 2035  ax-8 2151  ax-9 2159  ax-ext 2741  ax-sep 5261  ax-pr 5405
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3or 1102  df-3an 1103  df-tru 1570  df-fal 1580  df-ex 1807  df-sb 2098  df-clab 2748  df-cleq 2761  df-clel 2844  df-ne 2965  df-ral 3086  df-rex 3096  df-rab 3424  df-v 3465  df-dif 3916  df-un 3918  df-in 3920  df-ss 3930  df-pss 3933  df-nul 4295  df-if 4493  df-pw 4569  df-sn 4595  df-pr 4597  df-op 4601  df-uni 4877  df-br 5114  df-opab 5178  df-tr 5223  df-eprel 5562  df-po 5570  df-so 5571  df-fr 5615  df-we 5617  df-ord 6364
This theorem is referenced by:  ordtri3  6398  ord0eln0  6418  ord1eln01  8480  ord2eln012  8481  oaord  8531  omord2  8551  oeord  8573  nnaord  8604  nnmord  8617  noextenddif  27797
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