Theorem pntrval 25671

Description: Define the residual of the second Chebyshev function. The goal is to have 𝑅(𝑥) ∈ 𝑜(𝑥), or 𝑅(𝑥) / 𝑥 ⇝_𝑟 0. (Contributed by Mario Carneiro, 8-Apr-2016.)

Hypothesis

Ref	Expression
pntrval.r	⊢ 𝑅 = (𝑎 ∈ ℝ+ ↦ ((ψ‘𝑎) − 𝑎))

Assertion

Ref	Expression
pntrval	⊢ (𝐴 ∈ ℝ+ → (𝑅‘𝐴) = ((ψ‘𝐴) − 𝐴))

Distinct variable group:   𝐴,𝑎

Allowed substitution hint:   𝑅(𝑎)

Proof of Theorem pntrval

Step	Hyp	Ref	Expression
1		fveq2 6437	. . 3 ⊢ (𝑎 = 𝐴 → (ψ‘𝑎) = (ψ‘𝐴))
2		id 22	. . 3 ⊢ (𝑎 = 𝐴 → 𝑎 = 𝐴)
3	1, 2	oveq12d 6928	. 2 ⊢ (𝑎 = 𝐴 → ((ψ‘𝑎) − 𝑎) = ((ψ‘𝐴) − 𝐴))
4		pntrval.r	. 2 ⊢ 𝑅 = (𝑎 ∈ ℝ+ ↦ ((ψ‘𝑎) − 𝑎))
5		ovex 6942	. 2 ⊢ ((ψ‘𝐴) − 𝐴) ∈ V
6	3, 4, 5	fvmpt 6533	1 ⊢ (𝐴 ∈ ℝ+ → (𝑅‘𝐴) = ((ψ‘𝐴) − 𝐴))

Syntax hints:   → wi 4   = wceq 1656   ∈ wcel 2164   ↦ cmpt 4954  ‘cfv 6127  (class class class)co 6910   − cmin 10592  ℝ⁺crp 12119  ψcchp 25239

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1894  ax-4 1908  ax-5 2009  ax-6 2075  ax-7 2112  ax-9 2173  ax-10 2192  ax-11 2207  ax-12 2220  ax-13 2389  ax-ext 2803  ax-sep 5007  ax-nul 5015  ax-pr 5129

This theorem depends on definitions:  df-bi 199  df-an 387  df-or 879  df-3an 1113  df-tru 1660  df-ex 1879  df-nf 1883  df-sb 2068  df-mo 2605  df-eu 2640  df-clab 2812  df-cleq 2818  df-clel 2821  df-nfc 2958  df-ral 3122  df-rex 3123  df-rab 3126  df-v 3416  df-sbc 3663  df-dif 3801  df-un 3803  df-in 3805  df-ss 3812  df-nul 4147  df-if 4309  df-sn 4400  df-pr 4402  df-op 4406  df-uni 4661  df-br 4876  df-opab 4938  df-mpt 4955  df-id 5252  df-xp 5352  df-rel 5353  df-cnv 5354  df-co 5355  df-dm 5356  df-iota 6090  df-fun 6129  df-fv 6135  df-ov 6913

This theorem is referenced by:  pntrmax  25673  pntrsumo1  25674  selbergr  25677  selberg3r  25678  selberg4r  25679  pntrlog2bndlem2  25687  pntrlog2bndlem4  25689  pntrlog2bnd  25693  pntpbnd1a  25694  pntibndlem2  25700  pntlem3  25718