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Theorem resubval 39505
Description: Value of real subtraction, which is the (unique) real 𝑥 such that 𝐵 + 𝑥 = 𝐴. (Contributed by Steven Nguyen, 7-Jan-2022.)
Assertion
Ref Expression
resubval ((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 𝐵) = (𝑥 ∈ ℝ (𝐵 + 𝑥) = 𝐴))
Distinct variable groups:   𝑥,𝐴   𝑥,𝐵

Proof of Theorem resubval
Dummy variables 𝑦 𝑧 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 eqeq2 2810 . . 3 (𝑦 = 𝐴 → ((𝑧 + 𝑥) = 𝑦 ↔ (𝑧 + 𝑥) = 𝐴))
21riotabidv 7095 . 2 (𝑦 = 𝐴 → (𝑥 ∈ ℝ (𝑧 + 𝑥) = 𝑦) = (𝑥 ∈ ℝ (𝑧 + 𝑥) = 𝐴))
3 oveq1 7142 . . . 4 (𝑧 = 𝐵 → (𝑧 + 𝑥) = (𝐵 + 𝑥))
43eqeq1d 2800 . . 3 (𝑧 = 𝐵 → ((𝑧 + 𝑥) = 𝐴 ↔ (𝐵 + 𝑥) = 𝐴))
54riotabidv 7095 . 2 (𝑧 = 𝐵 → (𝑥 ∈ ℝ (𝑧 + 𝑥) = 𝐴) = (𝑥 ∈ ℝ (𝐵 + 𝑥) = 𝐴))
6 df-resub 39504 . 2 = (𝑦 ∈ ℝ, 𝑧 ∈ ℝ ↦ (𝑥 ∈ ℝ (𝑧 + 𝑥) = 𝑦))
7 riotaex 7097 . 2 (𝑥 ∈ ℝ (𝐵 + 𝑥) = 𝐴) ∈ V
82, 5, 6, 7ovmpo 7289 1 ((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 𝐵) = (𝑥 ∈ ℝ (𝐵 + 𝑥) = 𝐴))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 399   = wceq 1538  wcel 2111  crio 7092  (class class class)co 7135  cr 10525   + caddc 10529   cresub 39503
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1911  ax-6 1970  ax-7 2015  ax-8 2113  ax-9 2121  ax-10 2142  ax-11 2158  ax-12 2175  ax-ext 2770  ax-sep 5167  ax-nul 5174  ax-pr 5295
This theorem depends on definitions:  df-bi 210  df-an 400  df-or 845  df-3an 1086  df-tru 1541  df-ex 1782  df-nf 1786  df-sb 2070  df-mo 2598  df-eu 2629  df-clab 2777  df-cleq 2791  df-clel 2870  df-nfc 2938  df-ral 3111  df-rex 3112  df-v 3443  df-sbc 3721  df-dif 3884  df-un 3886  df-in 3888  df-ss 3898  df-nul 4244  df-if 4426  df-sn 4526  df-pr 4528  df-op 4532  df-uni 4801  df-br 5031  df-opab 5093  df-id 5425  df-xp 5525  df-rel 5526  df-cnv 5527  df-co 5528  df-dm 5529  df-iota 6283  df-fun 6326  df-fv 6332  df-riota 7093  df-ov 7138  df-oprab 7139  df-mpo 7140  df-resub 39504
This theorem is referenced by:  rernegcl  39509  renegadd  39510  rersubcl  39516  resubadd  39517  resubf  39519  resubeqsub  39566
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