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Theorem xpco2 49478
Description: Composition of a Cartesian product with a function. (Contributed by Zhi Wang, 25-Nov-2025.)
Assertion
Ref Expression
xpco2 (𝐹:𝐴𝐵 → ((𝐵 × 𝐶) ∘ 𝐹) = (𝐴 × 𝐶))

Proof of Theorem xpco2
Dummy variables 𝑥 𝑦 𝑧 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 relco 6097 . 2 Rel ((𝐵 × 𝐶) ∘ 𝐹)
2 relxp 5665 . 2 Rel (𝐴 × 𝐶)
3 vex 3458 . . . . . . . . . . 11 𝑥 ∈ V
4 vex 3458 . . . . . . . . . . 11 𝑧 ∈ V
53, 4breldm 5884 . . . . . . . . . 10 (𝑥𝐹𝑧𝑥 ∈ dom 𝐹)
65ad2antrl 738 . . . . . . . . 9 ((𝐹:𝐴𝐵 ∧ (𝑥𝐹𝑧𝑧(𝐵 × 𝐶)𝑦)) → 𝑥 ∈ dom 𝐹)
7 fdm 6701 . . . . . . . . . 10 (𝐹:𝐴𝐵 → dom 𝐹 = 𝐴)
87adantr 484 . . . . . . . . 9 ((𝐹:𝐴𝐵 ∧ (𝑥𝐹𝑧𝑧(𝐵 × 𝐶)𝑦)) → dom 𝐹 = 𝐴)
96, 8eleqtrd 2864 . . . . . . . 8 ((𝐹:𝐴𝐵 ∧ (𝑥𝐹𝑧𝑧(𝐵 × 𝐶)𝑦)) → 𝑥𝐴)
10 brxp 5696 . . . . . . . . . 10 (𝑧(𝐵 × 𝐶)𝑦 ↔ (𝑧𝐵𝑦𝐶))
1110simprbi 501 . . . . . . . . 9 (𝑧(𝐵 × 𝐶)𝑦𝑦𝐶)
1211ad2antll 739 . . . . . . . 8 ((𝐹:𝐴𝐵 ∧ (𝑥𝐹𝑧𝑧(𝐵 × 𝐶)𝑦)) → 𝑦𝐶)
139, 12jca 519 . . . . . . 7 ((𝐹:𝐴𝐵 ∧ (𝑥𝐹𝑧𝑧(𝐵 × 𝐶)𝑦)) → (𝑥𝐴𝑦𝐶))
1413ex 416 . . . . . 6 (𝐹:𝐴𝐵 → ((𝑥𝐹𝑧𝑧(𝐵 × 𝐶)𝑦) → (𝑥𝐴𝑦𝐶)))
1514exlimdv 1953 . . . . 5 (𝐹:𝐴𝐵 → (∃𝑧(𝑥𝐹𝑧𝑧(𝐵 × 𝐶)𝑦) → (𝑥𝐴𝑦𝐶)))
1615imp 410 . . . 4 ((𝐹:𝐴𝐵 ∧ ∃𝑧(𝑥𝐹𝑧𝑧(𝐵 × 𝐶)𝑦)) → (𝑥𝐴𝑦𝐶))
17 ffvelcdm 7062 . . . . . 6 ((𝐹:𝐴𝐵𝑥𝐴) → (𝐹𝑥) ∈ 𝐵)
1817adantrr 727 . . . . 5 ((𝐹:𝐴𝐵 ∧ (𝑥𝐴𝑦𝐶)) → (𝐹𝑥) ∈ 𝐵)
19 ffvbr 49477 . . . . . . 7 ((𝐹:𝐴𝐵𝑥𝐴) → 𝑥𝐹(𝐹𝑥))
2019adantrr 727 . . . . . 6 ((𝐹:𝐴𝐵 ∧ (𝑥𝐴𝑦𝐶)) → 𝑥𝐹(𝐹𝑥))
21 simprr 782 . . . . . . 7 ((𝐹:𝐴𝐵 ∧ (𝑥𝐴𝑦𝐶)) → 𝑦𝐶)
22 brxp 5696 . . . . . . 7 ((𝐹𝑥)(𝐵 × 𝐶)𝑦 ↔ ((𝐹𝑥) ∈ 𝐵𝑦𝐶))
2318, 21, 22sylanbrc 592 . . . . . 6 ((𝐹:𝐴𝐵 ∧ (𝑥𝐴𝑦𝐶)) → (𝐹𝑥)(𝐵 × 𝐶)𝑦)
2420, 23jca 519 . . . . 5 ((𝐹:𝐴𝐵 ∧ (𝑥𝐴𝑦𝐶)) → (𝑥𝐹(𝐹𝑥) ∧ (𝐹𝑥)(𝐵 × 𝐶)𝑦))
25 breq2 5104 . . . . . 6 (𝑧 = (𝐹𝑥) → (𝑥𝐹𝑧𝑥𝐹(𝐹𝑥)))
26 breq1 5103 . . . . . 6 (𝑧 = (𝐹𝑥) → (𝑧(𝐵 × 𝐶)𝑦 ↔ (𝐹𝑥)(𝐵 × 𝐶)𝑦))
2725, 26anbi12d 641 . . . . 5 (𝑧 = (𝐹𝑥) → ((𝑥𝐹𝑧𝑧(𝐵 × 𝐶)𝑦) ↔ (𝑥𝐹(𝐹𝑥) ∧ (𝐹𝑥)(𝐵 × 𝐶)𝑦)))
2818, 24, 27spcedv 3557 . . . 4 ((𝐹:𝐴𝐵 ∧ (𝑥𝐴𝑦𝐶)) → ∃𝑧(𝑥𝐹𝑧𝑧(𝐵 × 𝐶)𝑦))
2916, 28impbida 810 . . 3 (𝐹:𝐴𝐵 → (∃𝑧(𝑥𝐹𝑧𝑧(𝐵 × 𝐶)𝑦) ↔ (𝑥𝐴𝑦𝐶)))
30 vex 3458 . . . 4 𝑦 ∈ V
313, 30brco 5842 . . 3 (𝑥((𝐵 × 𝐶) ∘ 𝐹)𝑦 ↔ ∃𝑧(𝑥𝐹𝑧𝑧(𝐵 × 𝐶)𝑦))
32 brxp 5696 . . 3 (𝑥(𝐴 × 𝐶)𝑦 ↔ (𝑥𝐴𝑦𝐶))
3329, 31, 323bitr4g 316 . 2 (𝐹:𝐴𝐵 → (𝑥((𝐵 × 𝐶) ∘ 𝐹)𝑦𝑥(𝐴 × 𝐶)𝑦))
341, 2, 33eqbrrdiv 5766 1 (𝐹:𝐴𝐵 → ((𝐵 × 𝐶) ∘ 𝐹) = (𝐴 × 𝐶))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 399   = wceq 1560  wex 1799  wcel 2142   class class class wbr 5100   × cxp 5645  dom cdm 5647  ccom 5651  wf 6517  cfv 6521
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1815  ax-4 1829  ax-5 1930  ax-6 1987  ax-7 2028  ax-8 2144  ax-9 2152  ax-10 2175  ax-12 2212  ax-ext 2734  ax-sep 5246  ax-nul 5256  ax-pr 5390
This theorem depends on definitions:  df-bi 209  df-an 400  df-or 859  df-3an 1100  df-tru 1563  df-fal 1573  df-ex 1800  df-nf 1804  df-sb 2091  df-mo 2566  df-eu 2596  df-clab 2741  df-cleq 2754  df-clel 2837  df-ne 2958  df-ral 3077  df-rex 3087  df-rab 3415  df-v 3456  df-dif 3907  df-un 3909  df-in 3911  df-ss 3921  df-nul 4286  df-if 4481  df-sn 4583  df-pr 4585  df-op 4589  df-uni 4866  df-br 5101  df-opab 5163  df-id 5542  df-xp 5653  df-rel 5654  df-cnv 5655  df-co 5656  df-dm 5657  df-rn 5658  df-iota 6477  df-fun 6523  df-fn 6524  df-f 6525  df-fv 6529
This theorem is referenced by:  prcofdiag  50015
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