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Theorem ordnexbtwnsuc 41950
Description: For any distinct pair of ordinals, if there is no ordinal between the lesser and the greater, the greater is the successor of the lesser. Lemma 1.16 of [Schloeder] p. 2. (Contributed by RP, 16-Jan-2025.)
Assertion
Ref Expression
ordnexbtwnsuc ((𝐴𝐵 ∧ Ord 𝐵) → (∀𝑐 ∈ On ¬ (𝐴𝑐𝑐𝐵) → 𝐵 = suc 𝐴))
Distinct variable groups:   𝐴,𝑐   𝐵,𝑐

Proof of Theorem ordnexbtwnsuc
StepHypRef Expression
1 ordelord 6383 . . . . . 6 ((Ord 𝐵𝐴𝐵) → Ord 𝐴)
2 ordnbtwn 6454 . . . . . . . . . 10 (Ord 𝐴 → ¬ (𝐴𝐵𝐵 ∈ suc 𝐴))
32pm2.21d 121 . . . . . . . . 9 (Ord 𝐴 → ((𝐴𝐵𝐵 ∈ suc 𝐴) → ∃𝑐 ∈ On (𝐴𝑐𝑐𝐵)))
43expd 417 . . . . . . . 8 (Ord 𝐴 → (𝐴𝐵 → (𝐵 ∈ suc 𝐴 → ∃𝑐 ∈ On (𝐴𝑐𝑐𝐵))))
54com12 32 . . . . . . 7 (𝐴𝐵 → (Ord 𝐴 → (𝐵 ∈ suc 𝐴 → ∃𝑐 ∈ On (𝐴𝑐𝑐𝐵))))
65adantl 483 . . . . . 6 ((Ord 𝐵𝐴𝐵) → (Ord 𝐴 → (𝐵 ∈ suc 𝐴 → ∃𝑐 ∈ On (𝐴𝑐𝑐𝐵))))
71, 6mpd 15 . . . . 5 ((Ord 𝐵𝐴𝐵) → (𝐵 ∈ suc 𝐴 → ∃𝑐 ∈ On (𝐴𝑐𝑐𝐵)))
8 sucidg 6442 . . . . . . 7 (𝐴𝐵𝐴 ∈ suc 𝐴)
98adantl 483 . . . . . 6 ((Ord 𝐵𝐴𝐵) → 𝐴 ∈ suc 𝐴)
10 ordelon 6385 . . . . . . . 8 ((Ord 𝐵𝐴𝐵) → 𝐴 ∈ On)
11 onsuc 7794 . . . . . . . 8 (𝐴 ∈ On → suc 𝐴 ∈ On)
1210, 11syl 17 . . . . . . 7 ((Ord 𝐵𝐴𝐵) → suc 𝐴 ∈ On)
13 eleq2 2823 . . . . . . . . 9 (𝑐 = suc 𝐴 → (𝐴𝑐𝐴 ∈ suc 𝐴))
14 eleq1 2822 . . . . . . . . 9 (𝑐 = suc 𝐴 → (𝑐𝐵 ↔ suc 𝐴𝐵))
1513, 14anbi12d 632 . . . . . . . 8 (𝑐 = suc 𝐴 → ((𝐴𝑐𝑐𝐵) ↔ (𝐴 ∈ suc 𝐴 ∧ suc 𝐴𝐵)))
1615adantl 483 . . . . . . 7 (((Ord 𝐵𝐴𝐵) ∧ 𝑐 = suc 𝐴) → ((𝐴𝑐𝑐𝐵) ↔ (𝐴 ∈ suc 𝐴 ∧ suc 𝐴𝐵)))
1712, 16rspcedv 3605 . . . . . 6 ((Ord 𝐵𝐴𝐵) → ((𝐴 ∈ suc 𝐴 ∧ suc 𝐴𝐵) → ∃𝑐 ∈ On (𝐴𝑐𝑐𝐵)))
189, 17mpand 694 . . . . 5 ((Ord 𝐵𝐴𝐵) → (suc 𝐴𝐵 → ∃𝑐 ∈ On (𝐴𝑐𝑐𝐵)))
197, 18jaod 858 . . . 4 ((Ord 𝐵𝐴𝐵) → ((𝐵 ∈ suc 𝐴 ∨ suc 𝐴𝐵) → ∃𝑐 ∈ On (𝐴𝑐𝑐𝐵)))
20 ralnex 3073 . . . . 5 (∀𝑐 ∈ On ¬ (𝐴𝑐𝑐𝐵) ↔ ¬ ∃𝑐 ∈ On (𝐴𝑐𝑐𝐵))
2120biimpi 215 . . . 4 (∀𝑐 ∈ On ¬ (𝐴𝑐𝑐𝐵) → ¬ ∃𝑐 ∈ On (𝐴𝑐𝑐𝐵))
2219, 21nsyli 157 . . 3 ((Ord 𝐵𝐴𝐵) → (∀𝑐 ∈ On ¬ (𝐴𝑐𝑐𝐵) → ¬ (𝐵 ∈ suc 𝐴 ∨ suc 𝐴𝐵)))
23 ordsuci 7791 . . . . 5 (Ord 𝐴 → Ord suc 𝐴)
241, 23syl 17 . . . 4 ((Ord 𝐵𝐴𝐵) → Ord suc 𝐴)
25 ordtri3 6397 . . . 4 ((Ord 𝐵 ∧ Ord suc 𝐴) → (𝐵 = suc 𝐴 ↔ ¬ (𝐵 ∈ suc 𝐴 ∨ suc 𝐴𝐵)))
2624, 25syldan 592 . . 3 ((Ord 𝐵𝐴𝐵) → (𝐵 = suc 𝐴 ↔ ¬ (𝐵 ∈ suc 𝐴 ∨ suc 𝐴𝐵)))
2722, 26sylibrd 259 . 2 ((Ord 𝐵𝐴𝐵) → (∀𝑐 ∈ On ¬ (𝐴𝑐𝑐𝐵) → 𝐵 = suc 𝐴))
2827ancoms 460 1 ((𝐴𝐵 ∧ Ord 𝐵) → (∀𝑐 ∈ On ¬ (𝐴𝑐𝑐𝐵) → 𝐵 = suc 𝐴))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wi 4  wb 205  wa 397  wo 846   = wceq 1542  wcel 2107  wral 3062  wrex 3071  Ord word 6360  Oncon0 6361  suc csuc 6363
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1798  ax-4 1812  ax-5 1914  ax-6 1972  ax-7 2012  ax-8 2109  ax-9 2117  ax-ext 2704  ax-sep 5298  ax-nul 5305  ax-pr 5426  ax-un 7720
This theorem depends on definitions:  df-bi 206  df-an 398  df-or 847  df-3or 1089  df-3an 1090  df-tru 1545  df-fal 1555  df-ex 1783  df-sb 2069  df-clab 2711  df-cleq 2725  df-clel 2811  df-ne 2942  df-ral 3063  df-rex 3072  df-rab 3434  df-v 3477  df-dif 3950  df-un 3952  df-in 3954  df-ss 3964  df-pss 3966  df-nul 4322  df-if 4528  df-pw 4603  df-sn 4628  df-pr 4630  df-op 4634  df-uni 4908  df-br 5148  df-opab 5210  df-tr 5265  df-eprel 5579  df-po 5587  df-so 5588  df-fr 5630  df-we 5632  df-ord 6364  df-on 6365  df-suc 6367
This theorem is referenced by:  orddif0suc  41951
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