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Theorem funelss 8047

Description: If the first component of an element of a function is in the domain of a subset of the function, the element is a member of this subset. (Contributed by AV, 27-Oct-2023.)

**Assertion**
Ref	Expression
funelss	⊢ ((Fun 𝐴 ∧ 𝐵 ⊆ 𝐴 ∧ 𝑋 ∈ 𝐴) → ((1^st ‘𝑋) ∈ dom 𝐵 → 𝑋 ∈ 𝐵))

**Proof of Theorem funelss**
Step	Hyp	Ref	Expression
1		funrel 6548	. . . . . 6 ⊢ (Fun 𝐴 → Rel 𝐴)
2		1st2nd 8039	. . . . . 6 ⊢ ((Rel 𝐴 ∧ 𝑋 ∈ 𝐴) → 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩)
3	1, 2	sylan 592	. . . . 5 ⊢ ((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) → 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩)
4		simpl1l 1243	. . . . . . . . . 10 ⊢ ((((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∧ 𝐵 ⊆ 𝐴) ∧ (1^st ‘𝑋) ∈ dom 𝐵) → Fun 𝐴)
5		simpl3 1212	. . . . . . . . . 10 ⊢ ((((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∧ 𝐵 ⊆ 𝐴) ∧ (1^st ‘𝑋) ∈ dom 𝐵) → 𝐵 ⊆ 𝐴)
6		simpr 490	. . . . . . . . . 10 ⊢ ((((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∧ 𝐵 ⊆ 𝐴) ∧ (1^st ‘𝑋) ∈ dom 𝐵) → (1^st ‘𝑋) ∈ dom 𝐵)
7		funssfv 6898	. . . . . . . . . 10 ⊢ ((Fun 𝐴 ∧ 𝐵 ⊆ 𝐴 ∧ (1^st ‘𝑋) ∈ dom 𝐵) → (𝐴‘(1^st ‘𝑋)) = (𝐵‘(1^st ‘𝑋)))
8	4, 5, 6, 7	syl3anc 1398	. . . . . . . . 9 ⊢ ((((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∧ 𝐵 ⊆ 𝐴) ∧ (1^st ‘𝑋) ∈ dom 𝐵) → (𝐴‘(1^st ‘𝑋)) = (𝐵‘(1^st ‘𝑋)))
9		eleq1 2849	. . . . . . . . . . . . . . 15 ⊢ (𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ → (𝑋 ∈ 𝐴 ↔ ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∈ 𝐴))
10	9	adantl 487	. . . . . . . . . . . . . 14 ⊢ ((Fun 𝐴 ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩) → (𝑋 ∈ 𝐴 ↔ ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∈ 𝐴))
11		funopfv 6926	. . . . . . . . . . . . . . 15 ⊢ (Fun 𝐴 → (⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∈ 𝐴 → (𝐴‘(1^st ‘𝑋)) = (2^nd ‘𝑋)))
12	11	adantr 486	. . . . . . . . . . . . . 14 ⊢ ((Fun 𝐴 ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩) → (⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∈ 𝐴 → (𝐴‘(1^st ‘𝑋)) = (2^nd ‘𝑋)))
13	10, 12	sylbid 243	. . . . . . . . . . . . 13 ⊢ ((Fun 𝐴 ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩) → (𝑋 ∈ 𝐴 → (𝐴‘(1^st ‘𝑋)) = (2^nd ‘𝑋)))
14	13	impancom 457	. . . . . . . . . . . 12 ⊢ ((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) → (𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ → (𝐴‘(1^st ‘𝑋)) = (2^nd ‘𝑋)))
15	14	imp 412	. . . . . . . . . . 11 ⊢ (((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩) → (𝐴‘(1^st ‘𝑋)) = (2^nd ‘𝑋))
16	15	3adant3 1150	. . . . . . . . . 10 ⊢ (((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∧ 𝐵 ⊆ 𝐴) → (𝐴‘(1^st ‘𝑋)) = (2^nd ‘𝑋))
17	16	adantr 486	. . . . . . . . 9 ⊢ ((((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∧ 𝐵 ⊆ 𝐴) ∧ (1^st ‘𝑋) ∈ dom 𝐵) → (𝐴‘(1^st ‘𝑋)) = (2^nd ‘𝑋))
18	8, 17	eqtr3d 2798	. . . . . . . 8 ⊢ ((((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∧ 𝐵 ⊆ 𝐴) ∧ (1^st ‘𝑋) ∈ dom 𝐵) → (𝐵‘(1^st ‘𝑋)) = (2^nd ‘𝑋))
19		funss 6550	. . . . . . . . . . . . . 14 ⊢ (𝐵 ⊆ 𝐴 → (Fun 𝐴 → Fun 𝐵))
20	19	com12 33	. . . . . . . . . . . . 13 ⊢ (Fun 𝐴 → (𝐵 ⊆ 𝐴 → Fun 𝐵))
21	20	adantr 486	. . . . . . . . . . . 12 ⊢ ((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) → (𝐵 ⊆ 𝐴 → Fun 𝐵))
22	21	imp 412	. . . . . . . . . . 11 ⊢ (((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) ∧ 𝐵 ⊆ 𝐴) → Fun 𝐵)
23	22	funfnd 6563	. . . . . . . . . 10 ⊢ (((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) ∧ 𝐵 ⊆ 𝐴) → 𝐵 Fn dom 𝐵)
24	23	3adant2 1149	. . . . . . . . 9 ⊢ (((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∧ 𝐵 ⊆ 𝐴) → 𝐵 Fn dom 𝐵)
25		fnopfvb 6928	. . . . . . . . 9 ⊢ ((𝐵 Fn dom 𝐵 ∧ (1^st ‘𝑋) ∈ dom 𝐵) → ((𝐵‘(1^st ‘𝑋)) = (2^nd ‘𝑋) ↔ ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∈ 𝐵))
26	24, 25	sylan 592	. . . . . . . 8 ⊢ ((((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∧ 𝐵 ⊆ 𝐴) ∧ (1^st ‘𝑋) ∈ dom 𝐵) → ((𝐵‘(1^st ‘𝑋)) = (2^nd ‘𝑋) ↔ ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∈ 𝐵))
27	18, 26	mpbid 235	. . . . . . 7 ⊢ ((((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∧ 𝐵 ⊆ 𝐴) ∧ (1^st ‘𝑋) ∈ dom 𝐵) → ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∈ 𝐵)
28		eleq1 2849	. . . . . . . . 9 ⊢ (𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ → (𝑋 ∈ 𝐵 ↔ ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∈ 𝐵))
29	28	3ad2ant2 1152	. . . . . . . 8 ⊢ (((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∧ 𝐵 ⊆ 𝐴) → (𝑋 ∈ 𝐵 ↔ ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∈ 𝐵))
30	29	adantr 486	. . . . . . 7 ⊢ ((((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∧ 𝐵 ⊆ 𝐴) ∧ (1^st ‘𝑋) ∈ dom 𝐵) → (𝑋 ∈ 𝐵 ↔ ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∈ 𝐵))
31	27, 30	mpbird 260	. . . . . 6 ⊢ ((((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) ∧ 𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ ∧ 𝐵 ⊆ 𝐴) ∧ (1^st ‘𝑋) ∈ dom 𝐵) → 𝑋 ∈ 𝐵)
32	31	3exp1 1371	. . . . 5 ⊢ ((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) → (𝑋 = ⟨(1^st ‘𝑋), (2^nd ‘𝑋)⟩ → (𝐵 ⊆ 𝐴 → ((1^st ‘𝑋) ∈ dom 𝐵 → 𝑋 ∈ 𝐵))))
33	3, 32	mpd 16	. . . 4 ⊢ ((Fun 𝐴 ∧ 𝑋 ∈ 𝐴) → (𝐵 ⊆ 𝐴 → ((1^st ‘𝑋) ∈ dom 𝐵 → 𝑋 ∈ 𝐵)))
34	33	ex 418	. . 3 ⊢ (Fun 𝐴 → (𝑋 ∈ 𝐴 → (𝐵 ⊆ 𝐴 → ((1^st ‘𝑋) ∈ dom 𝐵 → 𝑋 ∈ 𝐵))))
35	34	com23 87	. 2 ⊢ (Fun 𝐴 → (𝐵 ⊆ 𝐴 → (𝑋 ∈ 𝐴 → ((1^st ‘𝑋) ∈ dom 𝐵 → 𝑋 ∈ 𝐵))))
36	35	3imp 1128	1 ⊢ ((Fun 𝐴 ∧ 𝐵 ⊆ 𝐴 ∧ 𝑋 ∈ 𝐴) → ((1^st ‘𝑋) ∈ dom 𝐵 → 𝑋 ∈ 𝐵))

Colors of variables: wff setvar class

This proof depends on syntax axioms: → wi 4 ↔ wb 209 ∧ wa 401 ∧ w3a 1103 = wceq 1570 ∈ wcel 2145 ⊆ wss 3899 ⟨cop 4590 dom cdm 5651 Rel wrel 5656 Fun wfun 6525 Fn wfn 6526 ‘cfv 6531 1^st c1st 7988 2^nd c2nd 7989

This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1828 ax-4 1842 ax-5 1943 ax-6 2000 ax-7 2041 ax-8 2147 ax-9 2155 ax-10 2178 ax-11 2194 ax-12 2213 ax-ext 2733 ax-sep 5249 ax-nul 5260 ax-pr 5391 ax-un 7740

This proof depends on definitions: df-bi 210 df-an 402 df-or 862 df-3an 1105 df-tru 1573 df-fal 1583 df-ex 1813 df-nf 1817 df-sb 2100 df-mo 2565 df-eu 2595 df-clab 2740 df-cleq 2753 df-clel 2836 df-nfc 2910 df-ne 2957 df-ral 3078 df-rex 3088 df-rab 3414 df-v 3453 df-dif 3902 df-un 3904 df-in 3906 df-ss 3916 df-nul 4280 df-if 4483 df-sn 4585 df-pr 4587 df-op 4591 df-uni 4868 df-br 5104 df-opab 5168 df-mpt 5187 df-id 5546 df-xp 5657 df-rel 5658 df-cnv 5659 df-co 5660 df-dm 5661 df-rn 5662 df-res 5663 df-iota 6487 df-fun 6533 df-fn 6534 df-fv 6539 df-1st 7990 df-2nd 7991

This theorem is used by: funeldmdif 8048

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