funssfv - Metamath Proof Explorer

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Theorem funssfv 6666

Description: The value of a member of the domain of a subclass of a function. (Contributed by NM, 15-Aug-1994.)

**Assertion**
Ref	Expression
funssfv	⊢ ((Fun 𝐹 ∧ 𝐺 ⊆ 𝐹 ∧ 𝐴 ∈ dom 𝐺) → (𝐹‘𝐴) = (𝐺‘𝐴))

**Proof of Theorem funssfv**
Step	Hyp	Ref	Expression
1		fvres 6664	. . . 4 ⊢ (𝐴 ∈ dom 𝐺 → ((𝐹 ↾ dom 𝐺)‘𝐴) = (𝐹‘𝐴))
2	1	eqcomd 2804	. . 3 ⊢ (𝐴 ∈ dom 𝐺 → (𝐹‘𝐴) = ((𝐹 ↾ dom 𝐺)‘𝐴))
3		funssres 6368	. . . 4 ⊢ ((Fun 𝐹 ∧ 𝐺 ⊆ 𝐹) → (𝐹 ↾ dom 𝐺) = 𝐺)
4	3	fveq1d 6647	. . 3 ⊢ ((Fun 𝐹 ∧ 𝐺 ⊆ 𝐹) → ((𝐹 ↾ dom 𝐺)‘𝐴) = (𝐺‘𝐴))
5	2, 4	sylan9eqr 2855	. 2 ⊢ (((Fun 𝐹 ∧ 𝐺 ⊆ 𝐹) ∧ 𝐴 ∈ dom 𝐺) → (𝐹‘𝐴) = (𝐺‘𝐴))
6	5	3impa 1107	1 ⊢ ((Fun 𝐹 ∧ 𝐺 ⊆ 𝐹 ∧ 𝐴 ∈ dom 𝐺) → (𝐹‘𝐴) = (𝐺‘𝐴))

Colors of variables: wff setvar class

Syntax hints: → wi 4 ∧ wa 399 ∧ w3a 1084 = wceq 1538 ∈ wcel 2111 ⊆ wss 3881 dom cdm 5519 ↾ cres 5521 Fun wfun 6318 ‘cfv 6324

This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1797 ax-4 1811 ax-5 1911 ax-6 1970 ax-7 2015 ax-8 2113 ax-9 2121 ax-10 2142 ax-11 2158 ax-12 2175 ax-ext 2770 ax-sep 5167 ax-nul 5174 ax-pr 5295

This theorem depends on definitions: df-bi 210 df-an 400 df-or 845 df-3an 1086 df-tru 1541 df-ex 1782 df-nf 1786 df-sb 2070 df-mo 2598 df-eu 2629 df-clab 2777 df-cleq 2791 df-clel 2870 df-nfc 2938 df-ral 3111 df-rex 3112 df-rab 3115 df-v 3443 df-dif 3884 df-un 3886 df-in 3888 df-ss 3898 df-nul 4244 df-if 4426 df-sn 4526 df-pr 4528 df-op 4532 df-uni 4801 df-br 5031 df-opab 5093 df-id 5425 df-xp 5525 df-rel 5526 df-cnv 5527 df-co 5528 df-dm 5529 df-res 5531 df-iota 6283 df-fun 6326 df-fv 6332

This theorem is referenced by: fviunfun 7628 funelss 7728 funsssuppss 7839 wfrlem12 7949 wfrlem14 7951 tfrlem9 8004 tfrlem11 8007 ac6sfi 8746 axdc3lem2 9862 axdc3lem4 9864 imasvscaval 16803 pserdv 25024 subgruhgredgd 27074 subumgredg2 27075 subupgr 27077 sspn 28519 bnj945 32155 bnj1502 32230 bnj545 32277 bnj548 32279 subfacp1lem2a 32540 subfacp1lem2b 32541 subfacp1lem5 32544 cvmliftlem10 32654 cvmliftlem13 32656 frrlem10 33245