Theorem funsneqopb 7167

Description: A singleton of an ordered pair is an ordered pair iff the components are equal. (Contributed by AV, 24-Sep-2020.) (Avoid depending on this detail.)

Hypotheses

Ref	Expression
funsndifnop.a	⊢ 𝐴 ∈ V
funsndifnop.b	⊢ 𝐵 ∈ V
funsndifnop.g	⊢ 𝐺 = {⟨𝐴, 𝐵⟩}

Assertion

Ref	Expression
funsneqopb	⊢ (𝐴 = 𝐵 ↔ 𝐺 ∈ (V × V))

Proof of Theorem funsneqopb

Step	Hyp	Ref	Expression
1		funsndifnop.g	. . . 4 ⊢ 𝐺 = {⟨𝐴, 𝐵⟩}
2		opeq1 4843	. . . . . 6 ⊢ (𝐴 = 𝐵 → ⟨𝐴, 𝐵⟩ = ⟨𝐵, 𝐵⟩)
3	2	sneqd 4596	. . . . 5 ⊢ (𝐴 = 𝐵 → {⟨𝐴, 𝐵⟩} = {⟨𝐵, 𝐵⟩})
4		funsndifnop.b	. . . . . 6 ⊢ 𝐵 ∈ V
5	4	snopeqopsnid 5485	. . . . 5 ⊢ {⟨𝐵, 𝐵⟩} = ⟨{𝐵}, {𝐵}⟩
6	3, 5	eqtrdi 2814	. . . 4 ⊢ (𝐴 = 𝐵 → {⟨𝐴, 𝐵⟩} = ⟨{𝐵}, {𝐵}⟩)
7	1, 6	eqtrid 2810	. . 3 ⊢ (𝐴 = 𝐵 → 𝐺 = ⟨{𝐵}, {𝐵}⟩)
8		snex 5401	. . . 4 ⊢ {𝐵} ∈ V
9	8, 8	opelvv 5695	. . 3 ⊢ ⟨{𝐵}, {𝐵}⟩ ∈ (V × V)
10	7, 9	eqeltrdi 2872	. 2 ⊢ (𝐴 = 𝐵 → 𝐺 ∈ (V × V))
11		funsndifnop.a	. . . 4 ⊢ 𝐴 ∈ V
12	11, 4, 1	funsndifnop 7166	. . 3 ⊢ (𝐴 ≠ 𝐵 → ¬ 𝐺 ∈ (V × V))
13	12	necon4ai 2990	. 2 ⊢ (𝐺 ∈ (V × V) → 𝐴 = 𝐵)
14	10, 13	impbii 212	1 ⊢ (𝐴 = 𝐵 ↔ 𝐺 ∈ (V × V))

This proof depends on syntax axioms:   ↔ wb 209   = wceq 1569   ∈ wcel 2146  Vcvv 3454  {csn 4588  ⟨cop 4838   × cxp 5653

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1944  ax-6 2001  ax-7 2042  ax-8 2148  ax-9 2156  ax-10 2179  ax-11 2196  ax-12 2215  ax-ext 2735  ax-sep 5252  ax-nul 5263  ax-pr 5395

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1572  df-fal 1582  df-ex 1812  df-nf 1816  df-sb 2101  df-mo 2567  df-eu 2597  df-clab 2742  df-cleq 2755  df-clel 2839  df-nfc 2913  df-ne 2960  df-ral 3081  df-rex 3091  df-reu 3370  df-rab 3417  df-v 3456  df-sbc 3743  df-csb 3852  df-ss 3901  df-dif 4050  df-in 4094  df-un 4154  df-nul 4282  df-if 4486  df-sn 4589  df-pr 4591  df-op 4839  df-uni 4871  df-iun 4956  df-br 5107  df-opab 5171  df-mpt 5190  df-id 5550  df-xp 5661  df-rel 5662  df-cnv 5663  df-co 5664  df-dm 5665  df-rn 5666  df-iota 6501  df-fun 6549  df-fn 6550  df-f 6551  df-f1 6552  df-fo 6553  df-f1o 6554  df-fv 6555

This theorem is used by: (None)