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| Mirrors > Home > MPE Home > Th. List > Mathboxes > hvmapvalvalN | Structured version Visualization version GIF version | ||
| Description: Value of value of map (i.e. functional value) from nonzero vectors to nonzero functionals in the closed kernel dual space. (Contributed by NM, 23-Mar-2015.) (New usage is discouraged.) |
| Ref | Expression |
|---|---|
| hvmapval.h | ⊢ 𝐻 = (LHyp‘𝐾) |
| hvmapval.u | ⊢ 𝑈 = ((DVecH‘𝐾)‘𝑊) |
| hvmapval.o | ⊢ 𝑂 = ((ocH‘𝐾)‘𝑊) |
| hvmapval.v | ⊢ 𝑉 = (Base‘𝑈) |
| hvmapval.p | ⊢ + = (+g‘𝑈) |
| hvmapval.t | ⊢ · = ( ·𝑠 ‘𝑈) |
| hvmapval.z | ⊢ 0 = (0g‘𝑈) |
| hvmapval.s | ⊢ 𝑆 = (Scalar‘𝑈) |
| hvmapval.r | ⊢ 𝑅 = (Base‘𝑆) |
| hvmapval.m | ⊢ 𝑀 = ((HVMap‘𝐾)‘𝑊) |
| hvmapval.k | ⊢ (𝜑 → (𝐾 ∈ 𝐴 ∧ 𝑊 ∈ 𝐻)) |
| hvmapval.x | ⊢ (𝜑 → 𝑋 ∈ (𝑉 ∖ { 0 })) |
| hvmapval.y | ⊢ (𝜑 → 𝑌 ∈ 𝑉) |
| Ref | Expression |
|---|---|
| hvmapvalvalN | ⊢ (𝜑 → ((𝑀‘𝑋)‘𝑌) = (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑌 = (𝑡 + (𝑗 · 𝑋)))) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | hvmapval.h | . . . 4 ⊢ 𝐻 = (LHyp‘𝐾) | |
| 2 | hvmapval.u | . . . 4 ⊢ 𝑈 = ((DVecH‘𝐾)‘𝑊) | |
| 3 | hvmapval.o | . . . 4 ⊢ 𝑂 = ((ocH‘𝐾)‘𝑊) | |
| 4 | hvmapval.v | . . . 4 ⊢ 𝑉 = (Base‘𝑈) | |
| 5 | hvmapval.p | . . . 4 ⊢ + = (+g‘𝑈) | |
| 6 | hvmapval.t | . . . 4 ⊢ · = ( ·𝑠 ‘𝑈) | |
| 7 | hvmapval.z | . . . 4 ⊢ 0 = (0g‘𝑈) | |
| 8 | hvmapval.s | . . . 4 ⊢ 𝑆 = (Scalar‘𝑈) | |
| 9 | hvmapval.r | . . . 4 ⊢ 𝑅 = (Base‘𝑆) | |
| 10 | hvmapval.m | . . . 4 ⊢ 𝑀 = ((HVMap‘𝐾)‘𝑊) | |
| 11 | hvmapval.k | . . . 4 ⊢ (𝜑 → (𝐾 ∈ 𝐴 ∧ 𝑊 ∈ 𝐻)) | |
| 12 | hvmapval.x | . . . 4 ⊢ (𝜑 → 𝑋 ∈ (𝑉 ∖ { 0 })) | |
| 13 | 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 | hvmapval 42957 | . . 3 ⊢ (𝜑 → (𝑀‘𝑋) = (𝑦 ∈ 𝑉 ↦ (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑦 = (𝑡 + (𝑗 · 𝑋))))) |
| 14 | 13 | fveq1d 6895 | . 2 ⊢ (𝜑 → ((𝑀‘𝑋)‘𝑌) = ((𝑦 ∈ 𝑉 ↦ (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑦 = (𝑡 + (𝑗 · 𝑋))))‘𝑌)) |
| 15 | hvmapval.y | . . 3 ⊢ (𝜑 → 𝑌 ∈ 𝑉) | |
| 16 | riotaex 7388 | . . 3 ⊢ (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑌 = (𝑡 + (𝑗 · 𝑋))) ∈ V | |
| 17 | eqeq1 2767 | . . . . . 6 ⊢ (𝑦 = 𝑌 → (𝑦 = (𝑡 + (𝑗 · 𝑋)) ↔ 𝑌 = (𝑡 + (𝑗 · 𝑋)))) | |
| 18 | 17 | rexbidv 3189 | . . . . 5 ⊢ (𝑦 = 𝑌 → (∃𝑡 ∈ (𝑂‘{𝑋})𝑦 = (𝑡 + (𝑗 · 𝑋)) ↔ ∃𝑡 ∈ (𝑂‘{𝑋})𝑌 = (𝑡 + (𝑗 · 𝑋)))) |
| 19 | 18 | riotabidv 7386 | . . . 4 ⊢ (𝑦 = 𝑌 → (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑦 = (𝑡 + (𝑗 · 𝑋))) = (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑌 = (𝑡 + (𝑗 · 𝑋)))) |
| 20 | eqid 2763 | . . . 4 ⊢ (𝑦 ∈ 𝑉 ↦ (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑦 = (𝑡 + (𝑗 · 𝑋)))) = (𝑦 ∈ 𝑉 ↦ (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑦 = (𝑡 + (𝑗 · 𝑋)))) | |
| 21 | 19, 20 | fvmptg 6999 | . . 3 ⊢ ((𝑌 ∈ 𝑉 ∧ (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑌 = (𝑡 + (𝑗 · 𝑋))) ∈ V) → ((𝑦 ∈ 𝑉 ↦ (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑦 = (𝑡 + (𝑗 · 𝑋))))‘𝑌) = (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑌 = (𝑡 + (𝑗 · 𝑋)))) |
| 22 | 15, 16, 21 | sylancl 598 | . 2 ⊢ (𝜑 → ((𝑦 ∈ 𝑉 ↦ (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑦 = (𝑡 + (𝑗 · 𝑋))))‘𝑌) = (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑌 = (𝑡 + (𝑗 · 𝑋)))) |
| 23 | 14, 22 | eqtrd 2798 | 1 ⊢ (𝜑 → ((𝑀‘𝑋)‘𝑌) = (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑌 = (𝑡 + (𝑗 · 𝑋)))) |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: → wi 4 ∧ wa 401 = wceq 1569 ∈ wcel 2146 ∃wrex 3089 Vcvv 3453 ∖ cdif 4047 {csn 4587 ↦ cmpt 5188 ‘cfv 6546 ℩crio 7383 (class class class)co 7427 Basecbs 17399 +gcplusg 17440 Scalarcsca 17443 ·𝑠 cvsca 17444 0gc0g 17622 LHypclh 41181 DVecHcdvh 42275 ocHcoch 42544 HVMapchvm 42953 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1827 ax-4 1841 ax-5 1944 ax-6 2001 ax-7 2042 ax-8 2148 ax-9 2156 ax-10 2179 ax-11 2196 ax-12 2215 ax-ext 2735 ax-rep 5234 ax-sep 5251 ax-nul 5262 ax-pr 5394 |
| This proof depends on definitions: df-bi 210 df-an 402 df-or 862 df-3an 1105 df-tru 1572 df-fal 1582 df-ex 1812 df-nf 1816 df-sb 2101 df-mo 2567 df-eu 2597 df-clab 2742 df-cleq 2755 df-clel 2838 df-nfc 2912 df-ne 2959 df-ral 3080 df-rex 3090 df-reu 3369 df-rab 3416 df-v 3455 df-sbc 3742 df-csb 3851 df-ss 3900 df-dif 4049 df-in 4093 df-un 4153 df-nul 4281 df-if 4485 df-sn 4588 df-pr 4590 df-op 4838 df-uni 4870 df-iun 4955 df-br 5106 df-opab 5170 df-mpt 5189 df-id 5549 df-xp 5660 df-rel 5661 df-cnv 5662 df-co 5663 df-dm 5664 df-rn 5665 df-res 5666 df-ima 5667 df-iota 6500 df-fun 6548 df-fn 6549 df-f 6550 df-f1 6551 df-fo 6552 df-f1o 6553 df-fv 6554 df-riota 7384 df-ov 7430 df-hvmap 42954 |
| This theorem is used by: (None) |
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