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| Mirrors > Home > MPE Home > Th. List > Mathboxes > hvmapvalvalN | Structured version Visualization version GIF version | ||
| Description: Value of value of map (i.e. functional value) from nonzero vectors to nonzero functionals in the closed kernel dual space. (Contributed by NM, 23-Mar-2015.) (New usage is discouraged.) |
| Ref | Expression |
|---|---|
| hvmapval.h | ⊢ 𝐻 = (LHyp‘𝐾) |
| hvmapval.u | ⊢ 𝑈 = ((DVecH‘𝐾)‘𝑊) |
| hvmapval.o | ⊢ 𝑂 = ((ocH‘𝐾)‘𝑊) |
| hvmapval.v | ⊢ 𝑉 = (Base‘𝑈) |
| hvmapval.p | ⊢ + = (+g‘𝑈) |
| hvmapval.t | ⊢ · = ( ·𝑠 ‘𝑈) |
| hvmapval.z | ⊢ 0 = (0g‘𝑈) |
| hvmapval.s | ⊢ 𝑆 = (Scalar‘𝑈) |
| hvmapval.r | ⊢ 𝑅 = (Base‘𝑆) |
| hvmapval.m | ⊢ 𝑀 = ((HVMap‘𝐾)‘𝑊) |
| hvmapval.k | ⊢ (𝜑 → (𝐾 ∈ 𝐴 ∧ 𝑊 ∈ 𝐻)) |
| hvmapval.x | ⊢ (𝜑 → 𝑋 ∈ (𝑉 ∖ { 0 })) |
| hvmapval.y | ⊢ (𝜑 → 𝑌 ∈ 𝑉) |
| Ref | Expression |
|---|---|
| hvmapvalvalN | ⊢ (𝜑 → ((𝑀‘𝑋)‘𝑌) = (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑌 = (𝑡 + (𝑗 · 𝑋)))) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | hvmapval.h | . . . 4 ⊢ 𝐻 = (LHyp‘𝐾) | |
| 2 | hvmapval.u | . . . 4 ⊢ 𝑈 = ((DVecH‘𝐾)‘𝑊) | |
| 3 | hvmapval.o | . . . 4 ⊢ 𝑂 = ((ocH‘𝐾)‘𝑊) | |
| 4 | hvmapval.v | . . . 4 ⊢ 𝑉 = (Base‘𝑈) | |
| 5 | hvmapval.p | . . . 4 ⊢ + = (+g‘𝑈) | |
| 6 | hvmapval.t | . . . 4 ⊢ · = ( ·𝑠 ‘𝑈) | |
| 7 | hvmapval.z | . . . 4 ⊢ 0 = (0g‘𝑈) | |
| 8 | hvmapval.s | . . . 4 ⊢ 𝑆 = (Scalar‘𝑈) | |
| 9 | hvmapval.r | . . . 4 ⊢ 𝑅 = (Base‘𝑆) | |
| 10 | hvmapval.m | . . . 4 ⊢ 𝑀 = ((HVMap‘𝐾)‘𝑊) | |
| 11 | hvmapval.k | . . . 4 ⊢ (𝜑 → (𝐾 ∈ 𝐴 ∧ 𝑊 ∈ 𝐻)) | |
| 12 | hvmapval.x | . . . 4 ⊢ (𝜑 → 𝑋 ∈ (𝑉 ∖ { 0 })) | |
| 13 | 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 | hvmapval 42634 | . . 3 ⊢ (𝜑 → (𝑀‘𝑋) = (𝑦 ∈ 𝑉 ↦ (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑦 = (𝑡 + (𝑗 · 𝑋))))) |
| 14 | 13 | fveq1d 6881 | . 2 ⊢ (𝜑 → ((𝑀‘𝑋)‘𝑌) = ((𝑦 ∈ 𝑉 ↦ (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑦 = (𝑡 + (𝑗 · 𝑋))))‘𝑌)) |
| 15 | hvmapval.y | . . 3 ⊢ (𝜑 → 𝑌 ∈ 𝑉) | |
| 16 | riotaex 7375 | . . 3 ⊢ (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑌 = (𝑡 + (𝑗 · 𝑋))) ∈ V | |
| 17 | eqeq1 2764 | . . . . . 6 ⊢ (𝑦 = 𝑌 → (𝑦 = (𝑡 + (𝑗 · 𝑋)) ↔ 𝑌 = (𝑡 + (𝑗 · 𝑋)))) | |
| 18 | 17 | rexbidv 3186 | . . . . 5 ⊢ (𝑦 = 𝑌 → (∃𝑡 ∈ (𝑂‘{𝑋})𝑦 = (𝑡 + (𝑗 · 𝑋)) ↔ ∃𝑡 ∈ (𝑂‘{𝑋})𝑌 = (𝑡 + (𝑗 · 𝑋)))) |
| 19 | 18 | riotabidv 7373 | . . . 4 ⊢ (𝑦 = 𝑌 → (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑦 = (𝑡 + (𝑗 · 𝑋))) = (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑌 = (𝑡 + (𝑗 · 𝑋)))) |
| 20 | eqid 2760 | . . . 4 ⊢ (𝑦 ∈ 𝑉 ↦ (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑦 = (𝑡 + (𝑗 · 𝑋)))) = (𝑦 ∈ 𝑉 ↦ (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑦 = (𝑡 + (𝑗 · 𝑋)))) | |
| 21 | 19, 20 | fvmptg 6985 | . . 3 ⊢ ((𝑌 ∈ 𝑉 ∧ (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑌 = (𝑡 + (𝑗 · 𝑋))) ∈ V) → ((𝑦 ∈ 𝑉 ↦ (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑦 = (𝑡 + (𝑗 · 𝑋))))‘𝑌) = (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑌 = (𝑡 + (𝑗 · 𝑋)))) |
| 22 | 15, 16, 21 | sylancl 598 | . 2 ⊢ (𝜑 → ((𝑦 ∈ 𝑉 ↦ (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑦 = (𝑡 + (𝑗 · 𝑋))))‘𝑌) = (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑌 = (𝑡 + (𝑗 · 𝑋)))) |
| 23 | 14, 22 | eqtrd 2795 | 1 ⊢ (𝜑 → ((𝑀‘𝑋)‘𝑌) = (℩𝑗 ∈ 𝑅 ∃𝑡 ∈ (𝑂‘{𝑋})𝑌 = (𝑡 + (𝑗 · 𝑋)))) |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: → wi 4 ∧ wa 401 = wceq 1570 ∈ wcel 2145 ∃wrex 3086 Vcvv 3450 ∖ cdif 3896 {csn 4584 ↦ cmpt 5186 ‘cfv 6533 ℩crio 7370 (class class class)co 7414 Basecbs 17302 +gcplusg 17343 Scalarcsca 17346 ·𝑠 cvsca 17347 0gc0g 17525 LHypclh 40858 DVecHcdvh 41952 ocHcoch 42221 HVMapchvm 42630 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1828 ax-4 1842 ax-5 1943 ax-6 2000 ax-7 2041 ax-8 2147 ax-9 2155 ax-10 2178 ax-11 2194 ax-12 2213 ax-ext 2732 ax-rep 5232 ax-sep 5251 ax-nul 5263 ax-pr 5398 |
| This proof depends on definitions: df-bi 210 df-an 402 df-or 862 df-3an 1105 df-tru 1573 df-fal 1583 df-ex 1813 df-nf 1817 df-sb 2100 df-mo 2564 df-eu 2594 df-clab 2739 df-cleq 2752 df-clel 2835 df-nfc 2909 df-ne 2956 df-ral 3077 df-rex 3087 df-reu 3366 df-rab 3413 df-v 3452 df-sbc 3740 df-csb 3848 df-dif 3902 df-un 3904 df-in 3906 df-ss 3916 df-nul 4280 df-if 4483 df-sn 4585 df-pr 4587 df-op 4591 df-uni 4868 df-iun 4953 df-br 5104 df-opab 5168 df-mpt 5187 df-id 5550 df-xp 5661 df-rel 5662 df-cnv 5663 df-co 5664 df-dm 5665 df-rn 5666 df-res 5667 df-ima 5668 df-iota 6489 df-fun 6535 df-fn 6536 df-f 6537 df-f1 6538 df-fo 6539 df-f1o 6540 df-fv 6541 df-riota 7371 df-ov 7417 df-hvmap 42631 |
| This theorem is used by: (None) |
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