Theorem suppvalbrOLD 8184

Description: Obsolete version of suppvalbr 8183 as of 14-Oct-2026. The value of the operation constructing the support of a function expressed by binary relations. (Contributed by AV, 7-Apr-2019.) (Proof modification is discouraged.) (New usage is discouraged.)

Assertion

Ref	Expression
suppvalbrOLD	⊢ ((𝑅 ∈ 𝑉 ∧ 𝑍 ∈ 𝑊) → (𝑅 supp 𝑍) = {𝑥 ∣ (∃𝑦 𝑥𝑅𝑦 ∧ ∃𝑦(𝑥𝑅𝑦 ↔ 𝑦 ≠ 𝑍))})

Distinct variable groups:   𝑥,𝑅,𝑦   𝑥,𝑍,𝑦

Allowed substitution hints:   𝑉(𝑥, 𝑦)   𝑊(𝑥, 𝑦)

Proof of Theorem suppvalbrOLD

Step	Hyp	Ref	Expression
1		df-rab 3413	. . . 4 ⊢ {𝑥 ∈ dom 𝑅 ∣ (𝑅 “ {𝑥}) ≠ {𝑍}} = {𝑥 ∣ (𝑥 ∈ dom 𝑅 ∧ (𝑅 “ {𝑥}) ≠ {𝑍})}
2		vex 3454	. . . . . . 7 ⊢ 𝑥 ∈ V
3	2	eldm 5881	. . . . . 6 ⊢ (𝑥 ∈ dom 𝑅 ↔ ∃𝑦 𝑥𝑅𝑦)
4		imasng 6081	. . . . . . . . 9 ⊢ (𝑥 ∈ V → (𝑅 “ {𝑥}) = {𝑦 ∣ 𝑥𝑅𝑦})
5	4	elv 3455	. . . . . . . 8 ⊢ (𝑅 “ {𝑥}) = {𝑦 ∣ 𝑥𝑅𝑦}
6	5	neeq1i 3019	. . . . . . 7 ⊢ ((𝑅 “ {𝑥}) ≠ {𝑍} ↔ {𝑦 ∣ 𝑥𝑅𝑦} ≠ {𝑍})
7		df-sn 4585	. . . . . . . 8 ⊢ {𝑍} = {𝑦 ∣ 𝑦 = 𝑍}
8	7	neeq2i 3020	. . . . . . 7 ⊢ ({𝑦 ∣ 𝑥𝑅𝑦} ≠ {𝑍} ↔ {𝑦 ∣ 𝑥𝑅𝑦} ≠ {𝑦 ∣ 𝑦 = 𝑍})
9		nabbib 3060	. . . . . . 7 ⊢ ({𝑦 ∣ 𝑥𝑅𝑦} ≠ {𝑦 ∣ 𝑦 = 𝑍} ↔ ∃𝑦(𝑥𝑅𝑦 ↔ ¬ 𝑦 = 𝑍))
10	6, 8, 9	3bitri 300	. . . . . 6 ⊢ ((𝑅 “ {𝑥}) ≠ {𝑍} ↔ ∃𝑦(𝑥𝑅𝑦 ↔ ¬ 𝑦 = 𝑍))
11	3, 10	anbi12i 640	. . . . 5 ⊢ ((𝑥 ∈ dom 𝑅 ∧ (𝑅 “ {𝑥}) ≠ {𝑍}) ↔ (∃𝑦 𝑥𝑅𝑦 ∧ ∃𝑦(𝑥𝑅𝑦 ↔ ¬ 𝑦 = 𝑍)))
12	11	abbii 2827	. . . 4 ⊢ {𝑥 ∣ (𝑥 ∈ dom 𝑅 ∧ (𝑅 “ {𝑥}) ≠ {𝑍})} = {𝑥 ∣ (∃𝑦 𝑥𝑅𝑦 ∧ ∃𝑦(𝑥𝑅𝑦 ↔ ¬ 𝑦 = 𝑍))}
13	1, 12	eqtr2i 2784	. . 3 ⊢ {𝑥 ∣ (∃𝑦 𝑥𝑅𝑦 ∧ ∃𝑦(𝑥𝑅𝑦 ↔ ¬ 𝑦 = 𝑍))} = {𝑥 ∈ dom 𝑅 ∣ (𝑅 “ {𝑥}) ≠ {𝑍}}
14	13	a1i 11	. 2 ⊢ ((𝑅 ∈ 𝑉 ∧ 𝑍 ∈ 𝑊) → {𝑥 ∣ (∃𝑦 𝑥𝑅𝑦 ∧ ∃𝑦(𝑥𝑅𝑦 ↔ ¬ 𝑦 = 𝑍))} = {𝑥 ∈ dom 𝑅 ∣ (𝑅 “ {𝑥}) ≠ {𝑍}})
15		df-ne 2956	. . . . . . 7 ⊢ (𝑦 ≠ 𝑍 ↔ ¬ 𝑦 = 𝑍)
16	15	bibi2i 340	. . . . . 6 ⊢ ((𝑥𝑅𝑦 ↔ 𝑦 ≠ 𝑍) ↔ (𝑥𝑅𝑦 ↔ ¬ 𝑦 = 𝑍))
17	16	exbii 1880	. . . . 5 ⊢ (∃𝑦(𝑥𝑅𝑦 ↔ 𝑦 ≠ 𝑍) ↔ ∃𝑦(𝑥𝑅𝑦 ↔ ¬ 𝑦 = 𝑍))
18	17	anbi2i 635	. . . 4 ⊢ ((∃𝑦 𝑥𝑅𝑦 ∧ ∃𝑦(𝑥𝑅𝑦 ↔ 𝑦 ≠ 𝑍)) ↔ (∃𝑦 𝑥𝑅𝑦 ∧ ∃𝑦(𝑥𝑅𝑦 ↔ ¬ 𝑦 = 𝑍)))
19	18	abbii 2827	. . 3 ⊢ {𝑥 ∣ (∃𝑦 𝑥𝑅𝑦 ∧ ∃𝑦(𝑥𝑅𝑦 ↔ 𝑦 ≠ 𝑍))} = {𝑥 ∣ (∃𝑦 𝑥𝑅𝑦 ∧ ∃𝑦(𝑥𝑅𝑦 ↔ ¬ 𝑦 = 𝑍))}
20	19	a1i 11	. 2 ⊢ ((𝑅 ∈ 𝑉 ∧ 𝑍 ∈ 𝑊) → {𝑥 ∣ (∃𝑦 𝑥𝑅𝑦 ∧ ∃𝑦(𝑥𝑅𝑦 ↔ 𝑦 ≠ 𝑍))} = {𝑥 ∣ (∃𝑦 𝑥𝑅𝑦 ∧ ∃𝑦(𝑥𝑅𝑦 ↔ ¬ 𝑦 = 𝑍))})
21		suppval 8181	. 2 ⊢ ((𝑅 ∈ 𝑉 ∧ 𝑍 ∈ 𝑊) → (𝑅 supp 𝑍) = {𝑥 ∈ dom 𝑅 ∣ (𝑅 “ {𝑥}) ≠ {𝑍}})
22	14, 20, 21	3eqtr4rd 2806	1 ⊢ ((𝑅 ∈ 𝑉 ∧ 𝑍 ∈ 𝑊) → (𝑅 supp 𝑍) = {𝑥 ∣ (∃𝑦 𝑥𝑅𝑦 ∧ ∃𝑦(𝑥𝑅𝑦 ↔ 𝑦 ≠ 𝑍))})

This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ↔ wb 209   ∧ wa 401   = wceq 1569  ∃wex 1811   ∈ wcel 2144  {cab 2738   ≠ wne 2955  {crab 3412  Vcvv 3450  {csn 4584   class class class wbr 5102  dom cdm 5650   “ cima 5653  (class class class)co 7420   supp csupp 8179

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-10 2177  ax-11 2193  ax-12 2212  ax-ext 2732  ax-sep 5248  ax-pr 5390  ax-un 7751

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1572  df-fal 1582  df-ex 1812  df-nf 1816  df-sb 2099  df-mo 2564  df-eu 2594  df-clab 2739  df-cleq 2752  df-clel 2835  df-nfc 2909  df-ne 2956  df-ral 3077  df-rex 3087  df-rab 3413  df-v 3452  df-sbc 3739  df-ss 3896  df-dif 4047  df-in 4091  df-un 4151  df-nul 4279  df-if 4482  df-pw 4558  df-sn 4585  df-pr 4587  df-op 4835  df-uni 4867  df-br 5103  df-opab 5167  df-id 5545  df-xp 5656  df-rel 5657  df-cnv 5658  df-co 5659  df-dm 5660  df-rn 5661  df-res 5662  df-ima 5663  df-iota 6494  df-fun 6540  df-fv 6546  df-ov 7423  df-oprab 7424  df-mpo 7425  df-supp 8180

This theorem is used by: (None)