sdrgsubrg - Metamath Proof Explorer

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Theorem sdrgsubrg 20770

Description: A sub-division-ring is a subring. (Contributed by SN, 19-Feb-2025.)

**Assertion**
Ref	Expression
sdrgsubrg	⊢ (𝐴 ∈ (SubDRing‘𝑅) → 𝐴 ∈ (SubRing‘𝑅))

**Proof of Theorem sdrgsubrg**
Step	Hyp	Ref	Expression
1		issdrg 20767	. 2 ⊢ (𝐴 ∈ (SubDRing‘𝑅) ↔ (𝑅 ∈ DivRing ∧ 𝐴 ∈ (SubRing‘𝑅) ∧ (𝑅 ↾_s 𝐴) ∈ DivRing))
2	1	simp2bi 1152	1 ⊢ (𝐴 ∈ (SubDRing‘𝑅) → 𝐴 ∈ (SubRing‘𝑅))

Colors of variables: wff setvar class

Syntax hints: → wi 4 ∈ wcel 2119 ‘cfv 6492 (class class class)co 7363 ↾_s cress 17198 SubRingcsubrg 20548 DivRingcdr 20708 SubDRingcsdrg 20765

This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1802 ax-4 1816 ax-5 1917 ax-6 1974 ax-7 2015 ax-8 2121 ax-9 2129 ax-10 2152 ax-11 2168 ax-12 2189 ax-ext 2712 ax-sep 5225 ax-nul 5235 ax-pr 5369

This theorem depends on definitions: df-bi 208 df-an 397 df-or 854 df-3an 1094 df-tru 1550 df-fal 1560 df-ex 1787 df-nf 1791 df-sb 2074 df-mo 2543 df-eu 2573 df-clab 2719 df-cleq 2732 df-clel 2815 df-nfc 2889 df-ne 2936 df-ral 3055 df-rex 3065 df-rab 3393 df-v 3434 df-dif 3893 df-un 3895 df-in 3897 df-ss 3907 df-nul 4269 df-if 4462 df-pw 4538 df-sn 4563 df-pr 4565 df-op 4569 df-uni 4846 df-br 5080 df-opab 5142 df-mpt 5161 df-id 5520 df-xp 5631 df-rel 5632 df-cnv 5633 df-co 5634 df-dm 5635 df-rn 5636 df-res 5637 df-ima 5638 df-iota 6448 df-fun 6494 df-fv 6500 df-ov 7366 df-sdrg 20766