sdrgsubrg - Metamath Proof Explorer

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Theorem sdrgsubrg 20708

Description: A sub-division-ring is a subring. (Contributed by SN, 19-Feb-2025.)

**Assertion**
Ref	Expression
sdrgsubrg	⊢ (𝐴 ∈ (SubDRing‘𝑅) → 𝐴 ∈ (SubRing‘𝑅))

**Proof of Theorem sdrgsubrg**
Step	Hyp	Ref	Expression
1		issdrg 20705	. 2 ⊢ (𝐴 ∈ (SubDRing‘𝑅) ↔ (𝑅 ∈ DivRing ∧ 𝐴 ∈ (SubRing‘𝑅) ∧ (𝑅 ↾_s 𝐴) ∈ DivRing))
2	1	simp2bi 1146	1 ⊢ (𝐴 ∈ (SubDRing‘𝑅) → 𝐴 ∈ (SubRing‘𝑅))

Colors of variables: wff setvar class

Syntax hints: → wi 4 ∈ wcel 2113 ‘cfv 6486 (class class class)co 7352 ↾_s cress 17143 SubRingcsubrg 20486 DivRingcdr 20646 SubDRingcsdrg 20703

This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1796 ax-4 1810 ax-5 1911 ax-6 1968 ax-7 2009 ax-8 2115 ax-9 2123 ax-10 2146 ax-11 2162 ax-12 2182 ax-ext 2705 ax-sep 5236 ax-nul 5246 ax-pr 5372

This theorem depends on definitions: df-bi 207 df-an 396 df-or 848 df-3an 1088 df-tru 1544 df-fal 1554 df-ex 1781 df-nf 1785 df-sb 2068 df-mo 2537 df-eu 2566 df-clab 2712 df-cleq 2725 df-clel 2808 df-nfc 2882 df-ne 2930 df-ral 3049 df-rex 3058 df-rab 3397 df-v 3439 df-dif 3901 df-un 3903 df-in 3905 df-ss 3915 df-nul 4283 df-if 4475 df-pw 4551 df-sn 4576 df-pr 4578 df-op 4582 df-uni 4859 df-br 5094 df-opab 5156 df-mpt 5175 df-id 5514 df-xp 5625 df-rel 5626 df-cnv 5627 df-co 5628 df-dm 5629 df-rn 5630 df-res 5631 df-ima 5632 df-iota 6442 df-fun 6488 df-fv 6494 df-ov 7355 df-sdrg 20704