| Step | Hyp | Ref
| Expression |
| 1 | | brprlng.p |
. . 3
⊢ ∥ =
(parlnG‘𝐺) |
| 2 | | df-prlng 29061 |
. . . 4
⊢ parlnG =
(𝑔 ∈ V ↦
{〈𝑎, 𝑏〉 ∣ ((𝑎 ∈ ran (LineG‘𝑔) ∧ 𝑏 ∈ ran (LineG‘𝑔)) ∧ (𝑎 = 𝑏 ∨ (∃ℎ ∈ ran (hlG‘𝑔)(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅)))}) |
| 3 | | fveq2 6867 |
. . . . . . . . . 10
⊢ (𝑔 = 𝐺 → (LineG‘𝑔) = (LineG‘𝐺)) |
| 4 | | brprlng.l |
. . . . . . . . . 10
⊢ 𝐿 = (LineG‘𝐺) |
| 5 | 3, 4 | eqtr4di 2815 |
. . . . . . . . 9
⊢ (𝑔 = 𝐺 → (LineG‘𝑔) = 𝐿) |
| 6 | 5 | rneqd 5914 |
. . . . . . . 8
⊢ (𝑔 = 𝐺 → ran (LineG‘𝑔) = ran 𝐿) |
| 7 | 6 | eleq2d 2848 |
. . . . . . 7
⊢ (𝑔 = 𝐺 → (𝑎 ∈ ran (LineG‘𝑔) ↔ 𝑎 ∈ ran 𝐿)) |
| 8 | 6 | eleq2d 2848 |
. . . . . . 7
⊢ (𝑔 = 𝐺 → (𝑏 ∈ ran (LineG‘𝑔) ↔ 𝑏 ∈ ran 𝐿)) |
| 9 | 7, 8 | anbi12d 641 |
. . . . . 6
⊢ (𝑔 = 𝐺 → ((𝑎 ∈ ran (LineG‘𝑔) ∧ 𝑏 ∈ ran (LineG‘𝑔)) ↔ (𝑎 ∈ ran 𝐿 ∧ 𝑏 ∈ ran 𝐿))) |
| 10 | | fveq2 6867 |
. . . . . . . . . . 11
⊢ (𝑔 = 𝐺 → (hlG‘𝑔) = (hlG‘𝐺)) |
| 11 | | brprlng.e |
. . . . . . . . . . 11
⊢ 𝐸 = (hlG‘𝐺) |
| 12 | 10, 11 | eqtr4di 2815 |
. . . . . . . . . 10
⊢ (𝑔 = 𝐺 → (hlG‘𝑔) = 𝐸) |
| 13 | 12 | rneqd 5914 |
. . . . . . . . 9
⊢ (𝑔 = 𝐺 → ran (hlG‘𝑔) = ran 𝐸) |
| 14 | 13 | rexeqdv 3321 |
. . . . . . . 8
⊢ (𝑔 = 𝐺 → (∃ℎ ∈ ran (hlG‘𝑔)(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ↔ ∃ℎ ∈ ran 𝐸(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ))) |
| 15 | 14 | anbi1d 640 |
. . . . . . 7
⊢ (𝑔 = 𝐺 → ((∃ℎ ∈ ran (hlG‘𝑔)(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅) ↔ (∃ℎ ∈ ran 𝐸(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅))) |
| 16 | 15 | orbi2d 926 |
. . . . . 6
⊢ (𝑔 = 𝐺 → ((𝑎 = 𝑏 ∨ (∃ℎ ∈ ran (hlG‘𝑔)(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅)) ↔ (𝑎 = 𝑏 ∨ (∃ℎ ∈ ran 𝐸(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅)))) |
| 17 | 9, 16 | anbi12d 641 |
. . . . 5
⊢ (𝑔 = 𝐺 → (((𝑎 ∈ ran (LineG‘𝑔) ∧ 𝑏 ∈ ran (LineG‘𝑔)) ∧ (𝑎 = 𝑏 ∨ (∃ℎ ∈ ran (hlG‘𝑔)(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅))) ↔ ((𝑎 ∈ ran 𝐿 ∧ 𝑏 ∈ ran 𝐿) ∧ (𝑎 = 𝑏 ∨ (∃ℎ ∈ ran 𝐸(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅))))) |
| 18 | 17 | opabbidv 5166 |
. . . 4
⊢ (𝑔 = 𝐺 → {〈𝑎, 𝑏〉 ∣ ((𝑎 ∈ ran (LineG‘𝑔) ∧ 𝑏 ∈ ran (LineG‘𝑔)) ∧ (𝑎 = 𝑏 ∨ (∃ℎ ∈ ran (hlG‘𝑔)(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅)))} = {〈𝑎, 𝑏〉 ∣ ((𝑎 ∈ ran 𝐿 ∧ 𝑏 ∈ ran 𝐿) ∧ (𝑎 = 𝑏 ∨ (∃ℎ ∈ ran 𝐸(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅)))}) |
| 19 | | brprlng.g |
. . . . 5
⊢ (𝜑 → 𝐺 ∈ 𝑉) |
| 20 | 19 | elexd 3477 |
. . . 4
⊢ (𝜑 → 𝐺 ∈ V) |
| 21 | 4 | fvexi 6881 |
. . . . . . 7
⊢ 𝐿 ∈ V |
| 22 | 21 | rnex 7891 |
. . . . . 6
⊢ ran 𝐿 ∈ V |
| 23 | 22 | a1i 11 |
. . . . 5
⊢ (𝜑 → ran 𝐿 ∈ V) |
| 24 | | simprll 788 |
. . . . 5
⊢ ((𝜑 ∧ ((𝑎 ∈ ran 𝐿 ∧ 𝑏 ∈ ran 𝐿) ∧ (𝑎 = 𝑏 ∨ (∃ℎ ∈ ran 𝐸(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅)))) → 𝑎 ∈ ran 𝐿) |
| 25 | | simprlr 789 |
. . . . 5
⊢ ((𝜑 ∧ ((𝑎 ∈ ran 𝐿 ∧ 𝑏 ∈ ran 𝐿) ∧ (𝑎 = 𝑏 ∨ (∃ℎ ∈ ran 𝐸(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅)))) → 𝑏 ∈ ran 𝐿) |
| 26 | 23, 23, 24, 25 | opabex2 8038 |
. . . 4
⊢ (𝜑 → {〈𝑎, 𝑏〉 ∣ ((𝑎 ∈ ran 𝐿 ∧ 𝑏 ∈ ran 𝐿) ∧ (𝑎 = 𝑏 ∨ (∃ℎ ∈ ran 𝐸(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅)))} ∈ V) |
| 27 | 2, 18, 20, 26 | fvmptd3 6999 |
. . 3
⊢ (𝜑 → (parlnG‘𝐺) = {〈𝑎, 𝑏〉 ∣ ((𝑎 ∈ ran 𝐿 ∧ 𝑏 ∈ ran 𝐿) ∧ (𝑎 = 𝑏 ∨ (∃ℎ ∈ ran 𝐸(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅)))}) |
| 28 | 1, 27 | eqtrid 2809 |
. 2
⊢ (𝜑 → ∥ = {〈𝑎, 𝑏〉 ∣ ((𝑎 ∈ ran 𝐿 ∧ 𝑏 ∈ ran 𝐿) ∧ (𝑎 = 𝑏 ∨ (∃ℎ ∈ ran 𝐸(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅)))}) |
| 29 | | eqeq12 2779 |
. . . 4
⊢ ((𝑎 = 𝐴 ∧ 𝑏 = 𝐵) → (𝑎 = 𝑏 ↔ 𝐴 = 𝐵)) |
| 30 | | sseq1 3961 |
. . . . . . 7
⊢ (𝑎 = 𝐴 → (𝑎 ⊆ ℎ ↔ 𝐴 ⊆ ℎ)) |
| 31 | | sseq1 3961 |
. . . . . . 7
⊢ (𝑏 = 𝐵 → (𝑏 ⊆ ℎ ↔ 𝐵 ⊆ ℎ)) |
| 32 | 30, 31 | bi2anan9 647 |
. . . . . 6
⊢ ((𝑎 = 𝐴 ∧ 𝑏 = 𝐵) → ((𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ↔ (𝐴 ⊆ ℎ ∧ 𝐵 ⊆ ℎ))) |
| 33 | 32 | rexbidv 3186 |
. . . . 5
⊢ ((𝑎 = 𝐴 ∧ 𝑏 = 𝐵) → (∃ℎ ∈ ran 𝐸(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ↔ ∃ℎ ∈ ran 𝐸(𝐴 ⊆ ℎ ∧ 𝐵 ⊆ ℎ))) |
| 34 | | ineq12 4167 |
. . . . . 6
⊢ ((𝑎 = 𝐴 ∧ 𝑏 = 𝐵) → (𝑎 ∩ 𝑏) = (𝐴 ∩ 𝐵)) |
| 35 | 34 | eqeq1d 2764 |
. . . . 5
⊢ ((𝑎 = 𝐴 ∧ 𝑏 = 𝐵) → ((𝑎 ∩ 𝑏) = ∅ ↔ (𝐴 ∩ 𝐵) = ∅)) |
| 36 | 33, 35 | anbi12d 641 |
. . . 4
⊢ ((𝑎 = 𝐴 ∧ 𝑏 = 𝐵) → ((∃ℎ ∈ ran 𝐸(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅) ↔ (∃ℎ ∈ ran 𝐸(𝐴 ⊆ ℎ ∧ 𝐵 ⊆ ℎ) ∧ (𝐴 ∩ 𝐵) = ∅))) |
| 37 | 29, 36 | orbi12d 929 |
. . 3
⊢ ((𝑎 = 𝐴 ∧ 𝑏 = 𝐵) → ((𝑎 = 𝑏 ∨ (∃ℎ ∈ ran 𝐸(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅)) ↔ (𝐴 = 𝐵 ∨ (∃ℎ ∈ ran 𝐸(𝐴 ⊆ ℎ ∧ 𝐵 ⊆ ℎ) ∧ (𝐴 ∩ 𝐵) = ∅)))) |
| 38 | 37 | adantl 485 |
. 2
⊢ ((𝜑 ∧ (𝑎 = 𝐴 ∧ 𝑏 = 𝐵)) → ((𝑎 = 𝑏 ∨ (∃ℎ ∈ ran 𝐸(𝑎 ⊆ ℎ ∧ 𝑏 ⊆ ℎ) ∧ (𝑎 ∩ 𝑏) = ∅)) ↔ (𝐴 = 𝐵 ∨ (∃ℎ ∈ ran 𝐸(𝐴 ⊆ ℎ ∧ 𝐵 ⊆ ℎ) ∧ (𝐴 ∩ 𝐵) = ∅)))) |
| 39 | 28, 38 | brab2d 5508 |
1
⊢ (𝜑 → (𝐴 ∥ 𝐵 ↔ ((𝐴 ∈ ran 𝐿 ∧ 𝐵 ∈ ran 𝐿) ∧ (𝐴 = 𝐵 ∨ (∃ℎ ∈ ran 𝐸(𝐴 ⊆ ℎ ∧ 𝐵 ⊆ ℎ) ∧ (𝐴 ∩ 𝐵) = ∅))))) |