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Theorem idfu1 18070
Description: Value of the object part of the identity functor. (Contributed by Mario Carneiro, 3-Jan-2017.)
Hypotheses
Ref Expression
idfuval.i 𝐼 = (idfunc‘𝐶)
idfuval.b 𝐵 = (Base‘𝐶)
idfuval.c (𝜑 → 𝐶 ∈ Cat)
idfu1.x (𝜑 → 𝑋 ∈ 𝐵)
Assertion
Ref Expression
idfu1 (𝜑 → ((1st ‘𝐼)‘𝑋) = 𝑋)

Proof of Theorem idfu1
StepHypRef Expression
1 idfuval.i . . . 4 𝐼 = (idfunc‘𝐶)
2 idfuval.b . . . 4 𝐵 = (Base‘𝐶)
3 idfuval.c . . . 4 (𝜑 → 𝐶 ∈ Cat)
41, 2, 3idfu1st 18069 . . 3 (𝜑 → (1st ‘𝐼) = ( I ↾ 𝐵))
54fveq1d 6898 . 2 (𝜑 → ((1st ‘𝐼)‘𝑋) = (( I ↾ 𝐵)‘𝑋))
6 idfu1.x . . 3 (𝜑 → 𝑋 ∈ 𝐵)
7 fvresi 7188 . . 3 (𝑋 ∈ 𝐵 → (( I ↾ 𝐵)‘𝑋) = 𝑋)
86, 7syl 18 . 2 (𝜑 → (( I ↾ 𝐵)‘𝑋) = 𝑋)
95, 8eqtrd 2798 1 (𝜑 → ((1st ‘𝐼)‘𝑋) = 𝑋)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   = wceq 1569   ∈ wcel 2146   I cid 5549   ↾ cres 5657  ‘cfv 6547  1st c1st 8009  Basecbs 17402  Catccat 17853  idfunccidfu 18045
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1944  ax-6 2001  ax-7 2042  ax-8 2148  ax-9 2156  ax-10 2179  ax-11 2196  ax-12 2215  ax-ext 2735  ax-rep 5235  ax-sep 5252  ax-nul 5263  ax-pow 5331  ax-pr 5395  ax-un 7761
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1572  df-fal 1582  df-ex 1812  df-nf 1816  df-sb 2101  df-mo 2567  df-eu 2597  df-clab 2742  df-cleq 2755  df-clel 2839  df-nfc 2913  df-ne 2960  df-ral 3081  df-rex 3091  df-reu 3370  df-rab 3417  df-v 3456  df-sbc 3743  df-csb 3852  df-ss 3901  df-dif 4050  df-in 4094  df-un 4154  df-nul 4282  df-if 4486  df-pw 4562  df-sn 4589  df-pr 4591  df-op 4839  df-uni 4871  df-iun 4956  df-br 5107  df-opab 5171  df-mpt 5190  df-id 5550  df-xp 5661  df-rel 5662  df-cnv 5663  df-co 5664  df-dm 5665  df-rn 5666  df-res 5667  df-ima 5668  df-iota 6501  df-fun 6549  df-fn 6550  df-f 6551  df-f1 6552  df-fo 6553  df-f1o 6554  df-fv 6555  df-1st 8011  df-idfu 18049
This theorem is used by:  idffth  18125  ressffth  18130  catciso  18301  idfu1a  50363  cofid1a  50373
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