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Theorem dedekindicclemub 15728
Description: Lemma for dedekindicc 15734. The lower cut has an upper bound. (Contributed by Jim Kingdon, 15-Feb-2024.)
Hypotheses
Ref Expression
dedekindicc.a (𝜑𝐴 ∈ ℝ)
dedekindicc.b (𝜑𝐵 ∈ ℝ)
dedekindicc.lss (𝜑𝐿 ⊆ (𝐴[,]𝐵))
dedekindicc.uss (𝜑𝑈 ⊆ (𝐴[,]𝐵))
dedekindicc.lm (𝜑 → ∃𝑞 ∈ (𝐴[,]𝐵)𝑞𝐿)
dedekindicc.um (𝜑 → ∃𝑟 ∈ (𝐴[,]𝐵)𝑟𝑈)
dedekindicc.lr (𝜑 → ∀𝑞 ∈ (𝐴[,]𝐵)(𝑞𝐿 ↔ ∃𝑟𝐿 𝑞 < 𝑟))
dedekindicc.ur (𝜑 → ∀𝑟 ∈ (𝐴[,]𝐵)(𝑟𝑈 ↔ ∃𝑞𝑈 𝑞 < 𝑟))
dedekindicc.disj (𝜑 → (𝐿𝑈) = ∅)
dedekindicc.loc (𝜑 → ∀𝑞 ∈ (𝐴[,]𝐵)∀𝑟 ∈ (𝐴[,]𝐵)(𝑞 < 𝑟 → (𝑞𝐿𝑟𝑈)))
Assertion
Ref Expression
dedekindicclemub (𝜑 → ∃𝑥 ∈ (𝐴[,]𝐵)∀𝑦𝐿 𝑦 < 𝑥)
Distinct variable groups:   𝐴,𝑞,𝑟,𝑦   𝑥,𝐴,𝑦   𝐵,𝑞,𝑟,𝑦   𝑥,𝐵   𝐿,𝑞,𝑦   𝑥,𝐿   𝑈,𝑞,𝑟,𝑦   𝜑,𝑞,𝑦
Allowed substitution hints:   𝜑(𝑥, 𝑟)   𝑈(𝑥)   𝐿(𝑟)

Proof of Theorem dedekindicclemub
Dummy variable 𝑎 is distinct from all other variables.
StepHypRef Expression
1 dedekindicc.um . . 3 (𝜑 → ∃𝑟 ∈ (𝐴[,]𝐵)𝑟𝑈)
2 eleq1w 2299 . . . 4 (𝑟 = 𝑎 → (𝑟𝑈𝑎𝑈))
32cbvrexv 2787 . . 3 (∃𝑟 ∈ (𝐴[,]𝐵)𝑟𝑈 ↔ ∃𝑎 ∈ (𝐴[,]𝐵)𝑎𝑈)
41, 3sylib 122 . 2 (𝜑 → ∃𝑎 ∈ (𝐴[,]𝐵)𝑎𝑈)
5 simprl 535 . . 3 ((𝜑 ∧ (𝑎 ∈ (𝐴[,]𝐵) ∧ 𝑎𝑈)) → 𝑎 ∈ (𝐴[,]𝐵))
6 dedekindicc.a . . . . 5 (𝜑𝐴 ∈ ℝ)
76adantr 276 . . . 4 ((𝜑 ∧ (𝑎 ∈ (𝐴[,]𝐵) ∧ 𝑎𝑈)) → 𝐴 ∈ ℝ)
8 dedekindicc.b . . . . 5 (𝜑𝐵 ∈ ℝ)
98adantr 276 . . . 4 ((𝜑 ∧ (𝑎 ∈ (𝐴[,]𝐵) ∧ 𝑎𝑈)) → 𝐵 ∈ ℝ)
10 dedekindicc.lss . . . . 5 (𝜑𝐿 ⊆ (𝐴[,]𝐵))
1110adantr 276 . . . 4 ((𝜑 ∧ (𝑎 ∈ (𝐴[,]𝐵) ∧ 𝑎𝑈)) → 𝐿 ⊆ (𝐴[,]𝐵))
12 dedekindicc.uss . . . . 5 (𝜑𝑈 ⊆ (𝐴[,]𝐵))
1312adantr 276 . . . 4 ((𝜑 ∧ (𝑎 ∈ (𝐴[,]𝐵) ∧ 𝑎𝑈)) → 𝑈 ⊆ (𝐴[,]𝐵))
14 dedekindicc.lm . . . . 5 (𝜑 → ∃𝑞 ∈ (𝐴[,]𝐵)𝑞𝐿)
1514adantr 276 . . . 4 ((𝜑 ∧ (𝑎 ∈ (𝐴[,]𝐵) ∧ 𝑎𝑈)) → ∃𝑞 ∈ (𝐴[,]𝐵)𝑞𝐿)
161adantr 276 . . . 4 ((𝜑 ∧ (𝑎 ∈ (𝐴[,]𝐵) ∧ 𝑎𝑈)) → ∃𝑟 ∈ (𝐴[,]𝐵)𝑟𝑈)
17 dedekindicc.lr . . . . 5 (𝜑 → ∀𝑞 ∈ (𝐴[,]𝐵)(𝑞𝐿 ↔ ∃𝑟𝐿 𝑞 < 𝑟))
1817adantr 276 . . . 4 ((𝜑 ∧ (𝑎 ∈ (𝐴[,]𝐵) ∧ 𝑎𝑈)) → ∀𝑞 ∈ (𝐴[,]𝐵)(𝑞𝐿 ↔ ∃𝑟𝐿 𝑞 < 𝑟))
19 dedekindicc.ur . . . . 5 (𝜑 → ∀𝑟 ∈ (𝐴[,]𝐵)(𝑟𝑈 ↔ ∃𝑞𝑈 𝑞 < 𝑟))
2019adantr 276 . . . 4 ((𝜑 ∧ (𝑎 ∈ (𝐴[,]𝐵) ∧ 𝑎𝑈)) → ∀𝑟 ∈ (𝐴[,]𝐵)(𝑟𝑈 ↔ ∃𝑞𝑈 𝑞 < 𝑟))
21 dedekindicc.disj . . . . 5 (𝜑 → (𝐿𝑈) = ∅)
2221adantr 276 . . . 4 ((𝜑 ∧ (𝑎 ∈ (𝐴[,]𝐵) ∧ 𝑎𝑈)) → (𝐿𝑈) = ∅)
23 dedekindicc.loc . . . . 5 (𝜑 → ∀𝑞 ∈ (𝐴[,]𝐵)∀𝑟 ∈ (𝐴[,]𝐵)(𝑞 < 𝑟 → (𝑞𝐿𝑟𝑈)))
2423adantr 276 . . . 4 ((𝜑 ∧ (𝑎 ∈ (𝐴[,]𝐵) ∧ 𝑎𝑈)) → ∀𝑞 ∈ (𝐴[,]𝐵)∀𝑟 ∈ (𝐴[,]𝐵)(𝑞 < 𝑟 → (𝑞𝐿𝑟𝑈)))
25 simprr 537 . . . 4 ((𝜑 ∧ (𝑎 ∈ (𝐴[,]𝐵) ∧ 𝑎𝑈)) → 𝑎𝑈)
267, 9, 11, 13, 15, 16, 18, 20, 22, 24, 25dedekindicclemuub 15727 . . 3 ((𝜑 ∧ (𝑎 ∈ (𝐴[,]𝐵) ∧ 𝑎𝑈)) → ∀𝑦𝐿 𝑦 < 𝑎)
27 brralrspcev 4189 . . 3 ((𝑎 ∈ (𝐴[,]𝐵) ∧ ∀𝑦𝐿 𝑦 < 𝑎) → ∃𝑥 ∈ (𝐴[,]𝐵)∀𝑦𝐿 𝑦 < 𝑥)
285, 26, 27syl2anc 415 . 2 ((𝜑 ∧ (𝑎 ∈ (𝐴[,]𝐵) ∧ 𝑎𝑈)) → ∃𝑥 ∈ (𝐴[,]𝐵)∀𝑦𝐿 𝑦 < 𝑥)
294, 28rexlimddv 2673 1 (𝜑 → ∃𝑥 ∈ (𝐴[,]𝐵)∀𝑦𝐿 𝑦 < 𝑥)
Colors of variables:    wff set class
This proof depends on syntax axioms:  wi 4  wa 104  wb 105  wo 720   = wceq 1402  wcel 2209  wral 2528  wrex 2529  cin 3219  wss 3220  c0 3520   class class class wbr 4130  (class class class)co 6085  cr 8178   < clt 8360  [,]cicc 10293
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 623  ax-in2 624  ax-io 721  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-10 1558  ax-11 1559  ax-i12 1560  ax-bndl 1562  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-14 2212  ax-ext 2220  ax-sep 4249  ax-pow 4311  ax-pr 4346  ax-un 4578  ax-setind 4684  ax-cnex 8270  ax-resscn 8271  ax-pre-ltirr 8291  ax-pre-ltwlin 8292  ax-pre-lttrn 8293
This proof depends on definitions:  df-bi 117  df-3or 1010  df-3an 1011  df-tru 1405  df-fal 1408  df-nf 1514  df-sb 1816  df-eu 2089  df-mo 2090  df-clab 2225  df-cleq 2231  df-clel 2234  df-nfc 2381  df-ne 2421  df-nel 2516  df-ral 2533  df-rex 2534  df-rab 2537  df-v 2823  df-sbc 3052  df-dif 3222  df-un 3224  df-in 3226  df-ss 3233  df-nul 3521  df-pw 3690  df-sn 3715  df-pr 3716  df-op 3718  df-uni 3936  df-br 4131  df-opab 4193  df-id 4438  df-po 4441  df-iso 4442  df-xp 4780  df-rel 4781  df-cnv 4782  df-co 4783  df-dm 4784  df-iota 5337  df-fun 5379  df-fv 5385  df-ov 6088  df-oprab 6089  df-mpo 6090  df-pnf 8362  df-mnf 8363  df-xr 8364  df-ltxr 8365  df-le 8366  df-icc 10297
This theorem is used by: (None)
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