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Theorem fconstg 6305
Description: A Cartesian product with a singleton is a constant function. (Contributed by NM, 19-Oct-2004.)
Assertion
Ref Expression
fconstg (𝐵𝑉 → (𝐴 × {𝐵}):𝐴⟶{𝐵})

Proof of Theorem fconstg
Dummy variable 𝑥 is distinct from all other variables.
StepHypRef Expression
1 sneq 4376 . . . 4 (𝑥 = 𝐵 → {𝑥} = {𝐵})
21xpeq2d 5340 . . 3 (𝑥 = 𝐵 → (𝐴 × {𝑥}) = (𝐴 × {𝐵}))
3 feq1 6235 . . . 4 ((𝐴 × {𝑥}) = (𝐴 × {𝐵}) → ((𝐴 × {𝑥}):𝐴⟶{𝑥} ↔ (𝐴 × {𝐵}):𝐴⟶{𝑥}))
4 feq3 6237 . . . 4 ({𝑥} = {𝐵} → ((𝐴 × {𝐵}):𝐴⟶{𝑥} ↔ (𝐴 × {𝐵}):𝐴⟶{𝐵}))
53, 4sylan9bb 506 . . 3 (((𝐴 × {𝑥}) = (𝐴 × {𝐵}) ∧ {𝑥} = {𝐵}) → ((𝐴 × {𝑥}):𝐴⟶{𝑥} ↔ (𝐴 × {𝐵}):𝐴⟶{𝐵}))
62, 1, 5syl2anc 580 . 2 (𝑥 = 𝐵 → ((𝐴 × {𝑥}):𝐴⟶{𝑥} ↔ (𝐴 × {𝐵}):𝐴⟶{𝐵}))
7 vex 3386 . . 3 𝑥 ∈ V
87fconst 6304 . 2 (𝐴 × {𝑥}):𝐴⟶{𝑥}
96, 8vtoclg 3451 1 (𝐵𝑉 → (𝐴 × {𝐵}):𝐴⟶{𝐵})
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 198   = wceq 1653  wcel 2157  {csn 4366   × cxp 5308  wf 6095
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1891  ax-4 1905  ax-5 2006  ax-6 2072  ax-7 2107  ax-9 2166  ax-10 2185  ax-11 2200  ax-12 2213  ax-13 2354  ax-ext 2775  ax-sep 4973  ax-nul 4981  ax-pr 5095
This theorem depends on definitions:  df-bi 199  df-an 386  df-or 875  df-3an 1110  df-tru 1657  df-ex 1876  df-nf 1880  df-sb 2065  df-mo 2590  df-eu 2607  df-clab 2784  df-cleq 2790  df-clel 2793  df-nfc 2928  df-ne 2970  df-ral 3092  df-rab 3096  df-v 3385  df-dif 3770  df-un 3772  df-in 3774  df-ss 3781  df-nul 4114  df-if 4276  df-sn 4367  df-pr 4369  df-op 4373  df-br 4842  df-opab 4904  df-mpt 4921  df-id 5218  df-xp 5316  df-rel 5317  df-cnv 5318  df-co 5319  df-dm 5320  df-rn 5321  df-fun 6101  df-fn 6102  df-f 6103
This theorem is referenced by:  fnconstg  6306  fconst6g  6307  xpsng  6631  fvconst2g  6694  fconst2g  6695  xkoptsub  21783  mbfconstlem  23732  i1fmulclem  23807  i1fmulc  23808  itg2mulclem  23851  dvcmulf  24046  dvef  24081  coemulc  24349  resf1o  30015  locfinref  30416  ccatmulgnn0dir  31129
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