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Theorem mgmidsssn0 13027
Description: Property of the set of identities of 𝐺. Either 𝐺 has no identities, and 𝑂 = ∅, or it has one and this identity is unique and identified by the 0g function. (Contributed by Mario Carneiro, 7-Dec-2014.)
Hypotheses
Ref Expression
mgmidsssn0.b 𝐵 = (Base‘𝐺)
mgmidsssn0.z 0 = (0g𝐺)
mgmidsssn0.p + = (+g𝐺)
mgmidsssn0.o 𝑂 = {𝑥𝐵 ∣ ∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦)}
Assertion
Ref Expression
mgmidsssn0 (𝐺𝑉𝑂 ⊆ { 0 })
Distinct variable groups:   𝑥,𝑦,𝐵   𝑥,𝐺,𝑦   𝑥, + ,𝑦   𝑥,𝑉   𝑥, 0 ,𝑦
Allowed substitution hints:   𝑂(𝑥,𝑦)   𝑉(𝑦)

Proof of Theorem mgmidsssn0
Dummy variable 𝑧 is distinct from all other variables.
StepHypRef Expression
1 mgmidsssn0.o . 2 𝑂 = {𝑥𝐵 ∣ ∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦)}
2 simpr 110 . . . . . . . 8 ((𝐺𝑉 ∧ (𝑥𝐵 ∧ ∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦))) → (𝑥𝐵 ∧ ∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦)))
3 mgmidsssn0.b . . . . . . . . 9 𝐵 = (Base‘𝐺)
4 mgmidsssn0.z . . . . . . . . 9 0 = (0g𝐺)
5 mgmidsssn0.p . . . . . . . . 9 + = (+g𝐺)
6 oveq1 5929 . . . . . . . . . . . . 13 (𝑧 = 𝑥 → (𝑧 + 𝑦) = (𝑥 + 𝑦))
76eqeq1d 2205 . . . . . . . . . . . 12 (𝑧 = 𝑥 → ((𝑧 + 𝑦) = 𝑦 ↔ (𝑥 + 𝑦) = 𝑦))
87ovanraleqv 5946 . . . . . . . . . . 11 (𝑧 = 𝑥 → (∀𝑦𝐵 ((𝑧 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑧) = 𝑦) ↔ ∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦)))
98rspcev 2868 . . . . . . . . . 10 ((𝑥𝐵 ∧ ∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦)) → ∃𝑧𝐵𝑦𝐵 ((𝑧 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑧) = 𝑦))
109adantl 277 . . . . . . . . 9 ((𝐺𝑉 ∧ (𝑥𝐵 ∧ ∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦))) → ∃𝑧𝐵𝑦𝐵 ((𝑧 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑧) = 𝑦))
113, 4, 5, 10ismgmid 13020 . . . . . . . 8 ((𝐺𝑉 ∧ (𝑥𝐵 ∧ ∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦))) → ((𝑥𝐵 ∧ ∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦)) ↔ 0 = 𝑥))
122, 11mpbid 147 . . . . . . 7 ((𝐺𝑉 ∧ (𝑥𝐵 ∧ ∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦))) → 0 = 𝑥)
1312eqcomd 2202 . . . . . 6 ((𝐺𝑉 ∧ (𝑥𝐵 ∧ ∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦))) → 𝑥 = 0 )
14 velsn 3639 . . . . . 6 (𝑥 ∈ { 0 } ↔ 𝑥 = 0 )
1513, 14sylibr 134 . . . . 5 ((𝐺𝑉 ∧ (𝑥𝐵 ∧ ∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦))) → 𝑥 ∈ { 0 })
1615expr 375 . . . 4 ((𝐺𝑉𝑥𝐵) → (∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦) → 𝑥 ∈ { 0 }))
1716ralrimiva 2570 . . 3 (𝐺𝑉 → ∀𝑥𝐵 (∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦) → 𝑥 ∈ { 0 }))
18 rabss 3260 . . 3 ({𝑥𝐵 ∣ ∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦)} ⊆ { 0 } ↔ ∀𝑥𝐵 (∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦) → 𝑥 ∈ { 0 }))
1917, 18sylibr 134 . 2 (𝐺𝑉 → {𝑥𝐵 ∣ ∀𝑦𝐵 ((𝑥 + 𝑦) = 𝑦 ∧ (𝑦 + 𝑥) = 𝑦)} ⊆ { 0 })
201, 19eqsstrid 3229 1 (𝐺𝑉𝑂 ⊆ { 0 })
Colors of variables: wff set class
Syntax hints:  wi 4  wa 104   = wceq 1364  wcel 2167  wral 2475  wrex 2476  {crab 2479  wss 3157  {csn 3622  cfv 5258  (class class class)co 5922  Basecbs 12678  +gcplusg 12755  0gc0g 12927
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 710  ax-5 1461  ax-7 1462  ax-gen 1463  ax-ie1 1507  ax-ie2 1508  ax-8 1518  ax-10 1519  ax-11 1520  ax-i12 1521  ax-bndl 1523  ax-4 1524  ax-17 1540  ax-i9 1544  ax-ial 1548  ax-i5r 1549  ax-13 2169  ax-14 2170  ax-ext 2178  ax-sep 4151  ax-pow 4207  ax-pr 4242  ax-un 4468  ax-cnex 7970  ax-resscn 7971  ax-1re 7973  ax-addrcl 7976
This theorem depends on definitions:  df-bi 117  df-3an 982  df-tru 1367  df-nf 1475  df-sb 1777  df-eu 2048  df-mo 2049  df-clab 2183  df-cleq 2189  df-clel 2192  df-nfc 2328  df-ral 2480  df-rex 2481  df-reu 2482  df-rmo 2483  df-rab 2484  df-v 2765  df-sbc 2990  df-csb 3085  df-un 3161  df-in 3163  df-ss 3170  df-pw 3607  df-sn 3628  df-pr 3629  df-op 3631  df-uni 3840  df-int 3875  df-br 4034  df-opab 4095  df-mpt 4096  df-id 4328  df-xp 4669  df-rel 4670  df-cnv 4671  df-co 4672  df-dm 4673  df-rn 4674  df-res 4675  df-iota 5219  df-fun 5260  df-fn 5261  df-fv 5266  df-riota 5877  df-ov 5925  df-inn 8991  df-ndx 12681  df-slot 12682  df-base 12684  df-0g 12929
This theorem is referenced by:  gsumress  13038  gsumvallem2  13125
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