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Theorem fn0 6652
Description: A function with empty domain is empty. (Contributed by NM, 15-Apr-1998.) (Proof shortened by Andrew Salmon, 17-Sep-2011.)
Assertion
Ref Expression
fn0 (𝐹 Fn ∅ ↔ 𝐹 = ∅)

Proof of Theorem fn0
StepHypRef Expression
1 fnrel 6623 . . 3 (𝐹 Fn ∅ → Rel 𝐹)
2 fndm 6624 . . 3 (𝐹 Fn ∅ → dom 𝐹 = ∅)
3 reldm0 5894 . . . 4 (Rel 𝐹 → (𝐹 = ∅ ↔ dom 𝐹 = ∅))
43biimpar 477 . . 3 ((Rel 𝐹 ∧ dom 𝐹 = ∅) → 𝐹 = ∅)
51, 2, 4syl2anc 584 . 2 (𝐹 Fn ∅ → 𝐹 = ∅)
6 fun0 6584 . . . 4 Fun ∅
7 dm0 5887 . . . 4 dom ∅ = ∅
8 df-fn 6517 . . . 4 (∅ Fn ∅ ↔ (Fun ∅ ∧ dom ∅ = ∅))
96, 7, 8mpbir2an 711 . . 3 ∅ Fn ∅
10 fneq1 6612 . . 3 (𝐹 = ∅ → (𝐹 Fn ∅ ↔ ∅ Fn ∅))
119, 10mpbiri 258 . 2 (𝐹 = ∅ → 𝐹 Fn ∅)
125, 11impbii 209 1 (𝐹 Fn ∅ ↔ 𝐹 = ∅)
Colors of variables: wff setvar class
Syntax hints:  wb 206   = wceq 1540  c0 4299  dom cdm 5641  Rel wrel 5646  Fun wfun 6508   Fn wfn 6509
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2008  ax-8 2111  ax-9 2119  ax-ext 2702  ax-sep 5254  ax-nul 5264  ax-pr 5390
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1543  df-fal 1553  df-ex 1780  df-sb 2066  df-mo 2534  df-clab 2709  df-cleq 2722  df-clel 2804  df-ral 3046  df-rex 3055  df-rab 3409  df-v 3452  df-dif 3920  df-un 3922  df-ss 3934  df-nul 4300  df-if 4492  df-sn 4593  df-pr 4595  df-op 4599  df-br 5111  df-opab 5173  df-id 5536  df-xp 5647  df-rel 5648  df-cnv 5649  df-co 5650  df-dm 5651  df-fun 6516  df-fn 6517
This theorem is referenced by:  mpt0  6663  f0  6744  f00  6745  f0bi  6746  f1o00  6838  fo00  6839  tpos0  8238  ixp0x  8902  0fz1  13512  hashf1  14429  fuchom  17933  grpinvfvi  18921  mulgfval  19008  mulgfvalALT  19009  mulgfvi  19012  0frgp  19716  invrfval  20305  psrvscafval  21864  tmdgsum  23989  deg1fvi  25997  hon0  31729  fnchoice  45030  dvnprodlem3  45953  0funcg2  49077  0funcALT  49081  0fucterm  49536
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