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Theorem lsppropd 21298
Description: If two structures have the same components (properties), they have the same span function. (Contributed by Mario Carneiro, 9-Feb-2015.) (Revised by Mario Carneiro, 14-Jun-2015.) (Revised by AV, 24-Apr-2024.)
Hypotheses
Ref Expression
lsspropd.b1 (𝜑 → 𝐵 = (Base‘𝐾))
lsspropd.b2 (𝜑 → 𝐵 = (Base‘𝐿))
lsspropd.w (𝜑 → 𝐵 ⊆ 𝑊)
lsspropd.p ((𝜑 ∧ (𝑥 ∈ 𝑊 ∧ 𝑦 ∈ 𝑊)) → (𝑥(+g‘𝐾)𝑦) = (𝑥(+g‘𝐿)𝑦))
lsspropd.s1 ((𝜑 ∧ (𝑥 ∈ 𝑃 ∧ 𝑦 ∈ 𝐵)) → (𝑥( ·𝑠 ‘𝐾)𝑦) ∈ 𝑊)
lsspropd.s2 ((𝜑 ∧ (𝑥 ∈ 𝑃 ∧ 𝑦 ∈ 𝐵)) → (𝑥( ·𝑠 ‘𝐾)𝑦) = (𝑥( ·𝑠 ‘𝐿)𝑦))
lsspropd.p1 (𝜑 → 𝑃 = (Base‘(Scalar‘𝐾)))
lsspropd.p2 (𝜑 → 𝑃 = (Base‘(Scalar‘𝐿)))
lsppropd.v1 (𝜑 → 𝐾 ∈ 𝑋)
lsppropd.v2 (𝜑 → 𝐿 ∈ 𝑌)
Assertion
Ref Expression
lsppropd (𝜑 → (LSpan‘𝐾) = (LSpan‘𝐿))
Distinct variable groups:   𝑥,𝑦,𝐵   𝑥,𝐾,𝑦   𝜑,𝑥,𝑦   𝑥,𝑊,𝑦   𝑥,𝐿,𝑦   𝑥,𝑃,𝑦
Allowed substitution hints:   𝑋(𝑥, 𝑦)   𝑌(𝑥, 𝑦)

Proof of Theorem lsppropd
Dummy variables 𝑠 𝑡 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 lsspropd.b1 . . . . 5 (𝜑 → 𝐵 = (Base‘𝐾))
2 lsspropd.b2 . . . . 5 (𝜑 → 𝐵 = (Base‘𝐿))
31, 2eqtr3d 2797 . . . 4 (𝜑 → (Base‘𝐾) = (Base‘𝐿))
43pweqd 4573 . . 3 (𝜑 → 𝒫 (Base‘𝐾) = 𝒫 (Base‘𝐿))
5 lsspropd.w . . . . . 6 (𝜑 → 𝐵 ⊆ 𝑊)
6 lsspropd.p . . . . . 6 ((𝜑 ∧ (𝑥 ∈ 𝑊 ∧ 𝑦 ∈ 𝑊)) → (𝑥(+g‘𝐾)𝑦) = (𝑥(+g‘𝐿)𝑦))
7 lsspropd.s1 . . . . . 6 ((𝜑 ∧ (𝑥 ∈ 𝑃 ∧ 𝑦 ∈ 𝐵)) → (𝑥( ·𝑠 ‘𝐾)𝑦) ∈ 𝑊)
8 lsspropd.s2 . . . . . 6 ((𝜑 ∧ (𝑥 ∈ 𝑃 ∧ 𝑦 ∈ 𝐵)) → (𝑥( ·𝑠 ‘𝐾)𝑦) = (𝑥( ·𝑠 ‘𝐿)𝑦))
9 lsspropd.p1 . . . . . 6 (𝜑 → 𝑃 = (Base‘(Scalar‘𝐾)))
10 lsspropd.p2 . . . . . 6 (𝜑 → 𝑃 = (Base‘(Scalar‘𝐿)))
111, 2, 5, 6, 7, 8, 9, 10lsspropd 21297 . . . . 5 (𝜑 → (LSubSp‘𝐾) = (LSubSp‘𝐿))
1211rabeqdv 3427 . . . 4 (𝜑 → {𝑡 ∈ (LSubSp‘𝐾) ∣ 𝑠 ⊆ 𝑡} = {𝑡 ∈ (LSubSp‘𝐿) ∣ 𝑠 ⊆ 𝑡})
1312inteqd 4911 . . 3 (𝜑 → ∩ {𝑡 ∈ (LSubSp‘𝐾) ∣ 𝑠 ⊆ 𝑡} = ∩ {𝑡 ∈ (LSubSp‘𝐿) ∣ 𝑠 ⊆ 𝑡})
144, 13mpteq12dv 5191 . 2 (𝜑 → (𝑠 ∈ 𝒫 (Base‘𝐾) ↦ ∩ {𝑡 ∈ (LSubSp‘𝐾) ∣ 𝑠 ⊆ 𝑡}) = (𝑠 ∈ 𝒫 (Base‘𝐿) ↦ ∩ {𝑡 ∈ (LSubSp‘𝐿) ∣ 𝑠 ⊆ 𝑡}))
15 lsppropd.v1 . . 3 (𝜑 → 𝐾 ∈ 𝑋)
16 eqid 2760 . . . 4 (Base‘𝐾) = (Base‘𝐾)
17 eqid 2760 . . . 4 (LSubSp‘𝐾) = (LSubSp‘𝐾)
18 eqid 2760 . . . 4 (LSpan‘𝐾) = (LSpan‘𝐾)
1916, 17, 18lspfval 21253 . . 3 (𝐾 ∈ 𝑋 → (LSpan‘𝐾) = (𝑠 ∈ 𝒫 (Base‘𝐾) ↦ ∩ {𝑡 ∈ (LSubSp‘𝐾) ∣ 𝑠 ⊆ 𝑡}))
2015, 19syl 18 . 2 (𝜑 → (LSpan‘𝐾) = (𝑠 ∈ 𝒫 (Base‘𝐾) ↦ ∩ {𝑡 ∈ (LSubSp‘𝐾) ∣ 𝑠 ⊆ 𝑡}))
21 lsppropd.v2 . . 3 (𝜑 → 𝐿 ∈ 𝑌)
22 eqid 2760 . . . 4 (Base‘𝐿) = (Base‘𝐿)
23 eqid 2760 . . . 4 (LSubSp‘𝐿) = (LSubSp‘𝐿)
24 eqid 2760 . . . 4 (LSpan‘𝐿) = (LSpan‘𝐿)
2522, 23, 24lspfval 21253 . . 3 (𝐿 ∈ 𝑌 → (LSpan‘𝐿) = (𝑠 ∈ 𝒫 (Base‘𝐿) ↦ ∩ {𝑡 ∈ (LSubSp‘𝐿) ∣ 𝑠 ⊆ 𝑡}))
2621, 25syl 18 . 2 (𝜑 → (LSpan‘𝐿) = (𝑠 ∈ 𝒫 (Base‘𝐿) ↦ ∩ {𝑡 ∈ (LSubSp‘𝐿) ∣ 𝑠 ⊆ 𝑡}))
2714, 20, 263eqtr4d 2805 1 (𝜑 → (LSpan‘𝐾) = (LSpan‘𝐿))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ∧ wa 401   = wceq 1569   ∈ wcel 2144  {crab 3412   ⊆ wss 3895  𝒫 cpw 4556  ∩ cint 4906   ↦ cmpt 5185  ‘cfv 6538  (class class class)co 7420  Basecbs 17392  +gcplusg 17433  Scalarcsca 17436   ·𝑠 cvsca 17437  LSubSpclss 21211  LSpanclspn 21251
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-10 2177  ax-11 2193  ax-12 2212  ax-ext 2732  ax-rep 5231  ax-sep 5248  ax-nul 5259  ax-pow 5326  ax-pr 5390
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1572  df-fal 1582  df-ex 1812  df-nf 1816  df-sb 2099  df-mo 2564  df-eu 2594  df-clab 2739  df-cleq 2752  df-clel 2835  df-nfc 2909  df-ne 2956  df-ral 3077  df-rex 3087  df-reu 3366  df-rab 3413  df-v 3452  df-sbc 3739  df-csb 3847  df-ss 3896  df-dif 4047  df-in 4091  df-un 4151  df-nul 4279  df-if 4482  df-pw 4558  df-sn 4585  df-pr 4587  df-op 4835  df-uni 4867  df-int 4907  df-iun 4952  df-br 5103  df-opab 5167  df-mpt 5186  df-id 5545  df-xp 5656  df-rel 5657  df-cnv 5658  df-co 5659  df-dm 5660  df-rn 5661  df-res 5662  df-ima 5663  df-iota 6494  df-fun 6540  df-fn 6541  df-f 6542  df-f1 6543  df-fo 6544  df-f1o 6545  df-fv 6546  df-ov 7423  df-lss 21212  df-lsp 21252
This theorem is used by:  lbspropd  21379  lidlrsppropd  21537  lindfpropd  33983
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