Proof of Theorem fvun1
| Step | Hyp | Ref
| Expression |
| 1 | | fnfun 5355 |
. . 3
⊢ (𝐹 Fn 𝐴 → Fun 𝐹) |
| 2 | 1 | 3ad2ant1 1020 |
. 2
⊢ ((𝐹 Fn 𝐴 ∧ 𝐺 Fn 𝐵 ∧ ((𝐴 ∩ 𝐵) = ∅ ∧ 𝑋 ∈ 𝐴)) → Fun 𝐹) |
| 3 | | fnfun 5355 |
. . 3
⊢ (𝐺 Fn 𝐵 → Fun 𝐺) |
| 4 | 3 | 3ad2ant2 1021 |
. 2
⊢ ((𝐹 Fn 𝐴 ∧ 𝐺 Fn 𝐵 ∧ ((𝐴 ∩ 𝐵) = ∅ ∧ 𝑋 ∈ 𝐴)) → Fun 𝐺) |
| 5 | | fndm 5357 |
. . . . . . 7
⊢ (𝐹 Fn 𝐴 → dom 𝐹 = 𝐴) |
| 6 | | fndm 5357 |
. . . . . . 7
⊢ (𝐺 Fn 𝐵 → dom 𝐺 = 𝐵) |
| 7 | 5, 6 | ineqan12d 3366 |
. . . . . 6
⊢ ((𝐹 Fn 𝐴 ∧ 𝐺 Fn 𝐵) → (dom 𝐹 ∩ dom 𝐺) = (𝐴 ∩ 𝐵)) |
| 8 | 7 | eqeq1d 2205 |
. . . . 5
⊢ ((𝐹 Fn 𝐴 ∧ 𝐺 Fn 𝐵) → ((dom 𝐹 ∩ dom 𝐺) = ∅ ↔ (𝐴 ∩ 𝐵) = ∅)) |
| 9 | 8 | biimprd 158 |
. . . 4
⊢ ((𝐹 Fn 𝐴 ∧ 𝐺 Fn 𝐵) → ((𝐴 ∩ 𝐵) = ∅ → (dom 𝐹 ∩ dom 𝐺) = ∅)) |
| 10 | 9 | adantrd 279 |
. . 3
⊢ ((𝐹 Fn 𝐴 ∧ 𝐺 Fn 𝐵) → (((𝐴 ∩ 𝐵) = ∅ ∧ 𝑋 ∈ 𝐴) → (dom 𝐹 ∩ dom 𝐺) = ∅)) |
| 11 | 10 | 3impia 1202 |
. 2
⊢ ((𝐹 Fn 𝐴 ∧ 𝐺 Fn 𝐵 ∧ ((𝐴 ∩ 𝐵) = ∅ ∧ 𝑋 ∈ 𝐴)) → (dom 𝐹 ∩ dom 𝐺) = ∅) |
| 12 | | simp3r 1028 |
. . 3
⊢ ((𝐹 Fn 𝐴 ∧ 𝐺 Fn 𝐵 ∧ ((𝐴 ∩ 𝐵) = ∅ ∧ 𝑋 ∈ 𝐴)) → 𝑋 ∈ 𝐴) |
| 13 | 5 | eleq2d 2266 |
. . . 4
⊢ (𝐹 Fn 𝐴 → (𝑋 ∈ dom 𝐹 ↔ 𝑋 ∈ 𝐴)) |
| 14 | 13 | 3ad2ant1 1020 |
. . 3
⊢ ((𝐹 Fn 𝐴 ∧ 𝐺 Fn 𝐵 ∧ ((𝐴 ∩ 𝐵) = ∅ ∧ 𝑋 ∈ 𝐴)) → (𝑋 ∈ dom 𝐹 ↔ 𝑋 ∈ 𝐴)) |
| 15 | 12, 14 | mpbird 167 |
. 2
⊢ ((𝐹 Fn 𝐴 ∧ 𝐺 Fn 𝐵 ∧ ((𝐴 ∩ 𝐵) = ∅ ∧ 𝑋 ∈ 𝐴)) → 𝑋 ∈ dom 𝐹) |
| 16 | | funun 5302 |
. . . . . . 7
⊢ (((Fun
𝐹 ∧ Fun 𝐺) ∧ (dom 𝐹 ∩ dom 𝐺) = ∅) → Fun (𝐹 ∪ 𝐺)) |
| 17 | | ssun1 3326 |
. . . . . . . . 9
⊢ 𝐹 ⊆ (𝐹 ∪ 𝐺) |
| 18 | | dmss 4865 |
. . . . . . . . 9
⊢ (𝐹 ⊆ (𝐹 ∪ 𝐺) → dom 𝐹 ⊆ dom (𝐹 ∪ 𝐺)) |
| 19 | 17, 18 | ax-mp 5 |
. . . . . . . 8
⊢ dom 𝐹 ⊆ dom (𝐹 ∪ 𝐺) |
| 20 | 19 | sseli 3179 |
. . . . . . 7
⊢ (𝑋 ∈ dom 𝐹 → 𝑋 ∈ dom (𝐹 ∪ 𝐺)) |
| 21 | 16, 20 | anim12i 338 |
. . . . . 6
⊢ ((((Fun
𝐹 ∧ Fun 𝐺) ∧ (dom 𝐹 ∩ dom 𝐺) = ∅) ∧ 𝑋 ∈ dom 𝐹) → (Fun (𝐹 ∪ 𝐺) ∧ 𝑋 ∈ dom (𝐹 ∪ 𝐺))) |
| 22 | 21 | anasss 399 |
. . . . 5
⊢ (((Fun
𝐹 ∧ Fun 𝐺) ∧ ((dom 𝐹 ∩ dom 𝐺) = ∅ ∧ 𝑋 ∈ dom 𝐹)) → (Fun (𝐹 ∪ 𝐺) ∧ 𝑋 ∈ dom (𝐹 ∪ 𝐺))) |
| 23 | 22 | 3impa 1196 |
. . . 4
⊢ ((Fun
𝐹 ∧ Fun 𝐺 ∧ ((dom 𝐹 ∩ dom 𝐺) = ∅ ∧ 𝑋 ∈ dom 𝐹)) → (Fun (𝐹 ∪ 𝐺) ∧ 𝑋 ∈ dom (𝐹 ∪ 𝐺))) |
| 24 | | funfvdm 5624 |
. . . 4
⊢ ((Fun
(𝐹 ∪ 𝐺) ∧ 𝑋 ∈ dom (𝐹 ∪ 𝐺)) → ((𝐹 ∪ 𝐺)‘𝑋) = ∪ ((𝐹 ∪ 𝐺) “ {𝑋})) |
| 25 | 23, 24 | syl 14 |
. . 3
⊢ ((Fun
𝐹 ∧ Fun 𝐺 ∧ ((dom 𝐹 ∩ dom 𝐺) = ∅ ∧ 𝑋 ∈ dom 𝐹)) → ((𝐹 ∪ 𝐺)‘𝑋) = ∪ ((𝐹 ∪ 𝐺) “ {𝑋})) |
| 26 | | imaundir 5083 |
. . . . . 6
⊢ ((𝐹 ∪ 𝐺) “ {𝑋}) = ((𝐹 “ {𝑋}) ∪ (𝐺 “ {𝑋})) |
| 27 | 26 | a1i 9 |
. . . . 5
⊢ ((Fun
𝐹 ∧ Fun 𝐺 ∧ ((dom 𝐹 ∩ dom 𝐺) = ∅ ∧ 𝑋 ∈ dom 𝐹)) → ((𝐹 ∪ 𝐺) “ {𝑋}) = ((𝐹 “ {𝑋}) ∪ (𝐺 “ {𝑋}))) |
| 28 | 27 | unieqd 3850 |
. . . 4
⊢ ((Fun
𝐹 ∧ Fun 𝐺 ∧ ((dom 𝐹 ∩ dom 𝐺) = ∅ ∧ 𝑋 ∈ dom 𝐹)) → ∪
((𝐹 ∪ 𝐺) “ {𝑋}) = ∪ ((𝐹 “ {𝑋}) ∪ (𝐺 “ {𝑋}))) |
| 29 | | disjel 3505 |
. . . . . . . . 9
⊢ (((dom
𝐹 ∩ dom 𝐺) = ∅ ∧ 𝑋 ∈ dom 𝐹) → ¬ 𝑋 ∈ dom 𝐺) |
| 30 | | ndmima 5046 |
. . . . . . . . 9
⊢ (¬
𝑋 ∈ dom 𝐺 → (𝐺 “ {𝑋}) = ∅) |
| 31 | 29, 30 | syl 14 |
. . . . . . . 8
⊢ (((dom
𝐹 ∩ dom 𝐺) = ∅ ∧ 𝑋 ∈ dom 𝐹) → (𝐺 “ {𝑋}) = ∅) |
| 32 | 31 | 3ad2ant3 1022 |
. . . . . . 7
⊢ ((Fun
𝐹 ∧ Fun 𝐺 ∧ ((dom 𝐹 ∩ dom 𝐺) = ∅ ∧ 𝑋 ∈ dom 𝐹)) → (𝐺 “ {𝑋}) = ∅) |
| 33 | 32 | uneq2d 3317 |
. . . . . 6
⊢ ((Fun
𝐹 ∧ Fun 𝐺 ∧ ((dom 𝐹 ∩ dom 𝐺) = ∅ ∧ 𝑋 ∈ dom 𝐹)) → ((𝐹 “ {𝑋}) ∪ (𝐺 “ {𝑋})) = ((𝐹 “ {𝑋}) ∪ ∅)) |
| 34 | | un0 3484 |
. . . . . 6
⊢ ((𝐹 “ {𝑋}) ∪ ∅) = (𝐹 “ {𝑋}) |
| 35 | 33, 34 | eqtrdi 2245 |
. . . . 5
⊢ ((Fun
𝐹 ∧ Fun 𝐺 ∧ ((dom 𝐹 ∩ dom 𝐺) = ∅ ∧ 𝑋 ∈ dom 𝐹)) → ((𝐹 “ {𝑋}) ∪ (𝐺 “ {𝑋})) = (𝐹 “ {𝑋})) |
| 36 | 35 | unieqd 3850 |
. . . 4
⊢ ((Fun
𝐹 ∧ Fun 𝐺 ∧ ((dom 𝐹 ∩ dom 𝐺) = ∅ ∧ 𝑋 ∈ dom 𝐹)) → ∪
((𝐹 “ {𝑋}) ∪ (𝐺 “ {𝑋})) = ∪ (𝐹 “ {𝑋})) |
| 37 | 28, 36 | eqtrd 2229 |
. . 3
⊢ ((Fun
𝐹 ∧ Fun 𝐺 ∧ ((dom 𝐹 ∩ dom 𝐺) = ∅ ∧ 𝑋 ∈ dom 𝐹)) → ∪
((𝐹 ∪ 𝐺) “ {𝑋}) = ∪ (𝐹 “ {𝑋})) |
| 38 | | funfvdm 5624 |
. . . . . 6
⊢ ((Fun
𝐹 ∧ 𝑋 ∈ dom 𝐹) → (𝐹‘𝑋) = ∪ (𝐹 “ {𝑋})) |
| 39 | 38 | eqcomd 2202 |
. . . . 5
⊢ ((Fun
𝐹 ∧ 𝑋 ∈ dom 𝐹) → ∪ (𝐹 “ {𝑋}) = (𝐹‘𝑋)) |
| 40 | 39 | adantrl 478 |
. . . 4
⊢ ((Fun
𝐹 ∧ ((dom 𝐹 ∩ dom 𝐺) = ∅ ∧ 𝑋 ∈ dom 𝐹)) → ∪
(𝐹 “ {𝑋}) = (𝐹‘𝑋)) |
| 41 | 40 | 3adant2 1018 |
. . 3
⊢ ((Fun
𝐹 ∧ Fun 𝐺 ∧ ((dom 𝐹 ∩ dom 𝐺) = ∅ ∧ 𝑋 ∈ dom 𝐹)) → ∪
(𝐹 “ {𝑋}) = (𝐹‘𝑋)) |
| 42 | 25, 37, 41 | 3eqtrd 2233 |
. 2
⊢ ((Fun
𝐹 ∧ Fun 𝐺 ∧ ((dom 𝐹 ∩ dom 𝐺) = ∅ ∧ 𝑋 ∈ dom 𝐹)) → ((𝐹 ∪ 𝐺)‘𝑋) = (𝐹‘𝑋)) |
| 43 | 2, 4, 11, 15, 42 | syl112anc 1253 |
1
⊢ ((𝐹 Fn 𝐴 ∧ 𝐺 Fn 𝐵 ∧ ((𝐴 ∩ 𝐵) = ∅ ∧ 𝑋 ∈ 𝐴)) → ((𝐹 ∪ 𝐺)‘𝑋) = (𝐹‘𝑋)) |