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Theorem readdridaddlidd 43501
Description: Given some real number 𝐵 where 𝐴 acts like a right additive identity, derive that 𝐴 is a left additive identity. Note that the hypothesis is weaker than proving that 𝐴 is a right additive identity (for all numbers). Although, if there is a right additive identity, then by readdcan 11511, 𝐴 is the right additive identity. (Contributed by Steven Nguyen, 14-Jan-2023.)
Hypotheses
Ref Expression
readdridaddlidd.a (𝜑 → 𝐴 ∈ ℝ)
readdridaddlidd.b (𝜑 → 𝐵 ∈ ℝ)
readdridaddlidd.1 (𝜑 → (𝐵 + 𝐴) = 𝐵)
Assertion
Ref Expression
readdridaddlidd ((𝜑 ∧ 𝐶 ∈ ℝ) → (𝐴 + 𝐶) = 𝐶)

Proof of Theorem readdridaddlidd
StepHypRef Expression
1 readdridaddlidd.b . . . . . 6 (𝜑 → 𝐵 ∈ ℝ)
21adantr 486 . . . . 5 ((𝜑 ∧ 𝐶 ∈ ℝ) → 𝐵 ∈ ℝ)
32recnd 11364 . . . 4 ((𝜑 ∧ 𝐶 ∈ ℝ) → 𝐵 ∈ ℂ)
4 readdridaddlidd.a . . . . . 6 (𝜑 → 𝐴 ∈ ℝ)
54adantr 486 . . . . 5 ((𝜑 ∧ 𝐶 ∈ ℝ) → 𝐴 ∈ ℝ)
65recnd 11364 . . . 4 ((𝜑 ∧ 𝐶 ∈ ℝ) → 𝐴 ∈ ℂ)
7 simpr 490 . . . . 5 ((𝜑 ∧ 𝐶 ∈ ℝ) → 𝐶 ∈ ℝ)
87recnd 11364 . . . 4 ((𝜑 ∧ 𝐶 ∈ ℝ) → 𝐶 ∈ ℂ)
93, 6, 8addassd 11358 . . 3 ((𝜑 ∧ 𝐶 ∈ ℝ) → ((𝐵 + 𝐴) + 𝐶) = (𝐵 + (𝐴 + 𝐶)))
10 readdridaddlidd.1 . . . . 5 (𝜑 → (𝐵 + 𝐴) = 𝐵)
1110adantr 486 . . . 4 ((𝜑 ∧ 𝐶 ∈ ℝ) → (𝐵 + 𝐴) = 𝐵)
1211oveq1d 7458 . . 3 ((𝜑 ∧ 𝐶 ∈ ℝ) → ((𝐵 + 𝐴) + 𝐶) = (𝐵 + 𝐶))
139, 12eqtr3d 2800 . 2 ((𝜑 ∧ 𝐶 ∈ ℝ) → (𝐵 + (𝐴 + 𝐶)) = (𝐵 + 𝐶))
145, 7readdcld 11365 . . 3 ((𝜑 ∧ 𝐶 ∈ ℝ) → (𝐴 + 𝐶) ∈ ℝ)
15 readdcan 11511 . . 3 (((𝐴 + 𝐶) ∈ ℝ ∧ 𝐶 ∈ ℝ ∧ 𝐵 ∈ ℝ) → ((𝐵 + (𝐴 + 𝐶)) = (𝐵 + 𝐶) ↔ (𝐴 + 𝐶) = 𝐶))
1614, 7, 2, 15syl3anc 1399 . 2 ((𝜑 ∧ 𝐶 ∈ ℝ) → ((𝐵 + (𝐴 + 𝐶)) = (𝐵 + 𝐶) ↔ (𝐴 + 𝐶) = 𝐶))
1713, 16mpbid 235 1 ((𝜑 ∧ 𝐶 ∈ ℝ) → (𝐴 + 𝐶) = 𝐶)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   = wceq 1570   ∈ wcel 2147  (class class class)co 7443  ℝcr 11226   + caddc 11230
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-10 2180  ax-11 2197  ax-12 2216  ax-ext 2735  ax-sep 5252  ax-nul 5263  ax-pow 5331  ax-pr 5395  ax-un 7775  ax-resscn 11284  ax-addrcl 11288  ax-addass 11292  ax-pre-lttri 11301  ax-pre-lttrn 11302  ax-pre-ltadd 11303
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3or 1104  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2102  df-mo 2567  df-eu 2597  df-clab 2742  df-cleq 2755  df-clel 2839  df-nfc 2913  df-ne 2960  df-nel 3066  df-ral 3081  df-rex 3091  df-rab 3417  df-v 3456  df-sbc 3743  df-csb 3852  df-ss 3901  df-dif 4050  df-in 4094  df-un 4154  df-nul 4282  df-if 4486  df-pw 4562  df-sn 4589  df-pr 4591  df-op 4839  df-uni 4871  df-br 5107  df-opab 5171  df-mpt 5190  df-id 5550  df-po 5563  df-so 5564  df-xp 5661  df-rel 5662  df-cnv 5663  df-co 5664  df-dm 5665  df-rn 5666  df-res 5667  df-ima 5668  df-iota 6512  df-fun 6560  df-fn 6561  df-f 6562  df-f1 6563  df-fo 6564  df-f1o 6565  df-fv 6566  df-ov 7446  df-er 8745  df-en 9002  df-dom 9003  df-sdom 9004  df-pnf 11372  df-mnf 11373  df-ltxr 11375
This theorem is used by:  reneg0addlid  43618
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