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Theorem readdridaddlidd 43401
Description: Given some real number 𝐵 where 𝐴 acts like a right additive identity, derive that 𝐴 is a left additive identity. Note that the hypothesis is weaker than proving that 𝐴 is a right additive identity (for all numbers). Although, if there is a right additive identity, then by readdcan 11487, 𝐴 is the right additive identity. (Contributed by Steven Nguyen, 14-Jan-2023.)
Hypotheses
Ref Expression
readdridaddlidd.a (𝜑 → 𝐴 ∈ ℝ)
readdridaddlidd.b (𝜑 → 𝐵 ∈ ℝ)
readdridaddlidd.1 (𝜑 → (𝐵 + 𝐴) = 𝐵)
Assertion
Ref Expression
readdridaddlidd ((𝜑 ∧ 𝐶 ∈ ℝ) → (𝐴 + 𝐶) = 𝐶)

Proof of Theorem readdridaddlidd
StepHypRef Expression
1 readdridaddlidd.b . . . . . 6 (𝜑 → 𝐵 ∈ ℝ)
21adantr 486 . . . . 5 ((𝜑 ∧ 𝐶 ∈ ℝ) → 𝐵 ∈ ℝ)
32recnd 11340 . . . 4 ((𝜑 ∧ 𝐶 ∈ ℝ) → 𝐵 ∈ ℂ)
4 readdridaddlidd.a . . . . . 6 (𝜑 → 𝐴 ∈ ℝ)
54adantr 486 . . . . 5 ((𝜑 ∧ 𝐶 ∈ ℝ) → 𝐴 ∈ ℝ)
65recnd 11340 . . . 4 ((𝜑 ∧ 𝐶 ∈ ℝ) → 𝐴 ∈ ℂ)
7 simpr 490 . . . . 5 ((𝜑 ∧ 𝐶 ∈ ℝ) → 𝐶 ∈ ℝ)
87recnd 11340 . . . 4 ((𝜑 ∧ 𝐶 ∈ ℝ) → 𝐶 ∈ ℂ)
93, 6, 8addassd 11334 . . 3 ((𝜑 ∧ 𝐶 ∈ ℝ) → ((𝐵 + 𝐴) + 𝐶) = (𝐵 + (𝐴 + 𝐶)))
10 readdridaddlidd.1 . . . . 5 (𝜑 → (𝐵 + 𝐴) = 𝐵)
1110adantr 486 . . . 4 ((𝜑 ∧ 𝐶 ∈ ℝ) → (𝐵 + 𝐴) = 𝐵)
1211oveq1d 7435 . . 3 ((𝜑 ∧ 𝐶 ∈ ℝ) → ((𝐵 + 𝐴) + 𝐶) = (𝐵 + 𝐶))
139, 12eqtr3d 2797 . 2 ((𝜑 ∧ 𝐶 ∈ ℝ) → (𝐵 + (𝐴 + 𝐶)) = (𝐵 + 𝐶))
145, 7readdcld 11341 . . 3 ((𝜑 ∧ 𝐶 ∈ ℝ) → (𝐴 + 𝐶) ∈ ℝ)
15 readdcan 11487 . . 3 (((𝐴 + 𝐶) ∈ ℝ ∧ 𝐶 ∈ ℝ ∧ 𝐵 ∈ ℝ) → ((𝐵 + (𝐴 + 𝐶)) = (𝐵 + 𝐶) ↔ (𝐴 + 𝐶) = 𝐶))
1614, 7, 2, 15syl3anc 1398 . 2 ((𝜑 ∧ 𝐶 ∈ ℝ) → ((𝐵 + (𝐴 + 𝐶)) = (𝐵 + 𝐶) ↔ (𝐴 + 𝐶) = 𝐶))
1713, 16mpbid 235 1 ((𝜑 ∧ 𝐶 ∈ ℝ) → (𝐴 + 𝐶) = 𝐶)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   = wceq 1569   ∈ wcel 2144  (class class class)co 7420  ℝcr 11202   + caddc 11206
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-10 2177  ax-11 2193  ax-12 2212  ax-ext 2732  ax-sep 5248  ax-nul 5259  ax-pow 5326  ax-pr 5390  ax-un 7751  ax-resscn 11260  ax-addrcl 11264  ax-addass 11268  ax-pre-lttri 11277  ax-pre-lttrn 11278  ax-pre-ltadd 11279
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3or 1104  df-3an 1105  df-tru 1572  df-fal 1582  df-ex 1812  df-nf 1816  df-sb 2099  df-mo 2564  df-eu 2594  df-clab 2739  df-cleq 2752  df-clel 2835  df-nfc 2909  df-ne 2956  df-nel 3062  df-ral 3077  df-rex 3087  df-rab 3413  df-v 3452  df-sbc 3739  df-csb 3847  df-ss 3896  df-dif 4047  df-in 4091  df-un 4151  df-nul 4279  df-if 4482  df-pw 4558  df-sn 4585  df-pr 4587  df-op 4835  df-uni 4867  df-br 5103  df-opab 5167  df-mpt 5186  df-id 5545  df-po 5558  df-so 5559  df-xp 5656  df-rel 5657  df-cnv 5658  df-co 5659  df-dm 5660  df-rn 5661  df-res 5662  df-ima 5663  df-iota 6494  df-fun 6540  df-fn 6541  df-f 6542  df-f1 6543  df-fo 6544  df-f1o 6545  df-fv 6546  df-ov 7423  df-er 8720  df-en 8977  df-dom 8978  df-sdom 8979  df-pnf 11348  df-mnf 11349  df-ltxr 11351
This theorem is used by:  reneg0addlid  43518
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